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Step 1:Use the formula for string factorial

Short Answer

Expert verified

Total number of arrangements of n objects if al are different

Ifof them are same number of ways are given by

\(C\left( {n + r - 1,r} \right) = \frac{{(n + r - 1)!}}{{n!r!}}\)

TheIs string length

are outcome of strings

Step by step solution

01

Step 2: Solution of x1 ≥ 1

Let’s, appliedandvalues,

Here,

\(\begin{aligned}{l}C\left( {n + r - 1,r} \right) &= \frac{{(n + r - 1)!}}{{n!r!}}\\n &= 21\\r &= 4\\C\left( {n + r - 1,r} \right) &= C\left( {21 + 4 - 1,4} \right)\\c(24,4) &= 10626\end{aligned}\)

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