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18. Find \(\frac{{dy}}{{dx}}\) by implicit differentiation.

18. \(\sin x\cos y = {x^2} - 5y\)

Short Answer

Expert verified

The value is \(\frac{{dy}}{{dx}} = \frac{{2x - \cos x\cos y}}{{5 - \sin x\sin y}}\).

Step by step solution

01

Differentiate the given equation

The given equation is\(\sin x\cos y = {x^2} - 5y\). Both sides of this equation are differentiated with respect to\(x\)as follows:

\(\begin{array}{c}\frac{d}{{dx}}\left( {\sin x\cos y} \right) = \frac{d}{{dx}}\left( {{x^2} - 5y} \right)\\\sin x\left( { - \sin y} \right) \cdot y' + \cos y\left( {\cos x} \right) = 2x - 5y'\end{array}\)

02

Simplify the resulting equation

Simplify the resulting equation to obtain the expression for \(\frac{{dy}}{{dx}}\), as shown below:

\(\begin{array}{c}5y' - \sin x\sin y \cdot y' &= 2x - \cos x\cos y\\y'\left( {5 - \sin x\sin y} \right) &= 2x - \cos x\cos y\\y' &= \frac{{2x - \cos x\cos y}}{{5 - \sin x\sin y}}\end{array}\).

Thus, the value is \(\frac{{dy}}{{dx}} = \frac{{2x - \cos x\cos y}}{{5 - \sin x\sin y}}\).

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