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Find the critical numbers of the function.

39. \(h\left( t \right) = {t^{\frac{{\bf{3}}}{{\bf{4}}}}} - {\bf{2}}{t^{\frac{{\bf{1}}}{{\bf{4}}}}}\)

Short Answer

Expert verified

The critical numbers are \(t = 0{\rm{ and }}\frac{4}{9}\).

Step by step solution

01

Critical Numbers of a function

TheCritical numbersfor any function \(h\left( t \right)\) are obtained by putting \(h'\left( t \right) = 0\).

02

Differentiating the function for critical numbers

The given function is:

\(h\left( t \right) = {t^{\frac{3}{4}}} - 2{t^{\frac{1}{4}}}\)

On differentiating with respect to\(t\)as:

\(\begin{array}{c}h'\left( t \right) = \frac{d}{{dt}}\left( {{t^{\frac{3}{4}}} - 2{t^{\frac{1}{4}}}} \right)\\ = \frac{d}{{dt}}\left( {{t^{\frac{3}{4}}}} \right) - 2\frac{d}{{dt}}\left( {{t^{\frac{1}{4}}}} \right)\\ = \frac{3}{4}{t^{ - \frac{1}{4}}} - \frac{1}{2}{t^{ - \frac{3}{4}}}\end{array}\)

Solving for critical numbers:

\(\begin{array}{c}h'\left( t \right) = 0\\\frac{3}{4}{t^{ - \frac{1}{4}}} - \frac{1}{2}{t^{ - \frac{3}{4}}} = 0\\\frac{1}{4}{t^{ - \frac{3}{4}}}\left( {3\sqrt t - 2} \right) = 0\\t = 0,\,\,\,\,\sqrt t = \frac{2}{3}\\t = 0,\frac{4}{9}\end{array}\)

Hence, the critical numbers are \(t = 0{\rm{ and }}\frac{4}{9}\).

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