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Two steps of Euler's method For the following initial value problems, compute the first two approximations \(u_{1}\)and\(u_{2}\) given by Euler's method using the given time step. $$y^{\prime}(t)=-y, y(0)=-1 ; \Delta t=0.2$$

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Question: Compute the first two approximations for the given initial value problem using Euler's method with a time step of 0.2: \(y'(t) = -y\) and \(y(0) = -1\). Answer: The first two approximations using Euler's method for the given initial value problem are: $$u_1 = -0.8$$ $$u_2 = -0.64$$

Step by step solution

01

Understand Euler's method formula

To apply Euler's method, we need to use the following general formula: $$u_{n+1} = u_n + \Delta t \cdot f(t_n, u_n)$$ Here, \(f(t_n, u_n)\) represents the given differential equation, with an initial condition \(u_0 = y(0)\), and a time step \(\Delta t\). For the given problem, we have: $$f(t, y) = -y$$ and $$y(0) = -1$$
02

Calculate u1 (First Approximation)

Using the formula and known values, let's find the first approximation \(u_1\). $$u_1 = u_0 + \Delta t \cdot f(t_0, u_0)$$ We have: $$u_0 = y(0) = -1$$ $$\Delta t = 0.2$$ $$f(t_0, u_0) = -u_0 = 1$$ Now, plug in the values to get: $$u_1 = -1 + 0.2 \cdot 1 = -1 + 0.2 = -0.8$$
03

Calculate u2 (Second Approximation)

Next, we have to find the second approximation \(u_2\). Use the formula again with the new values. $$u_2 = u_1 + \Delta t \cdot f(t_1, u_1)$$ Note that: $$t_1 = 0.2$$ $$u_1 = -0.8$$ $$f(t_1, u_1) = -u_1 = 0.8$$ Plugging in the values, we get: $$u_2 = -0.8 + 0.2 \cdot 0.8 = -0.8 + 0.16 = -0.64$$ Thus, the first two approximations using Euler's method for the given initial value problem are: $$u_1 = -0.8$$ $$u_2 = -0.64$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Value Problems
In the realm of differential equations, an Initial Value Problem (IVP) is essentially a puzzle that gives you a starting point and a rule for finding the path ahead. It usually consists of an ordinary differential equation (ODE) and an accompanying initial condition. This initial condition pinpoints the value of the unknown function at a specific point. In our problem, the differential equation is given by \( y'(t) = -y \), and the initial condition is \( y(0) = -1 \). This condition helps anchor the solution curve. Without it, we could have infinitely many potential solutions since differential equations sometimes have families of solutions. The role of Euler's method in an IVP is to approximate these solutions numerically instead of solving them analytically, especially when an algebraic solution is hard or impossible to find. Thus, the initial values provide the essential groundwork from which numerical methods can begin their approximation efforts.
Numerical Approximation
Numerical Approximation involves using mathematical techniques to find approximate solutions to mathematical problems that may not be easy to solve exactly. Euler's method is a basic—yet powerful—technique for doing this with differential equations, particularly when dealing with initial value problems. In our exercise, Euler's method gives us approximate solutions \( u_1 \) and \( u_2 \) as steps to solving the differential equation using a specified time step \( \Delta t = 0.2 \). Instead of calculating the exact continuous trajectory of the solution, Euler's method incrementally progresses in small steps, predicting the new values based on current information. It uses a simple formula:
  • \( u_{n+1} = u_n + \Delta t \cdot f(t_n, u_n) \)
With each step, we obtain a new approximation. This iterative nature can introduce some errors, but it also allows us to gain insights into the nature of solutions without full-on solving the differential equation analytically. The smaller the time step, generally, the closer the approximation will be to the actual solution.
Differential Equations
Differential Equations are a fundamental tool in modeling real-world phenomena, where rates of change play a significant role. A differential equation relates a function to its derivatives, essentially describing how a particular quantity changes over time or space. In our example, \( y'(t) = -y \) speaks to the rate of change of \( y \); it tells us that the rate is proportional to the negative of its current value. This type of equation frequently appears in scenarios where processes decay exponentially or substances cool down. Solving differential equations analytically can sometimes be straightforward, as in simple linear cases, but they often require numerical methods like Euler's method for complex or nonlinear situations. Understanding how to set up a differential equation helps decode and interpret the puzzles they present, providing solutions that describe dynamic systems and their behavior over time.

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Most popular questions from this chapter

Analyzing models The following models were discussed in Section 9.1 and reappear in later sections of this chapter. In each case carry out the indicated analysis using direction fields. Chemical rate equations Consider the chemical rate equations \(y^{\prime}(t)=-k y(t)\) and \(y^{\prime}(t)=-k y^{2}(t),\) where \(y(t)\) is the concentration of the compound for \(t \geq 0,\) and \(k>0\) is a constant that determines the speed of the reaction. Assume the initial concentration of the compound is \(y(0)=y_{0}>0\). a. Let \(k=0.3\) and make a sketch of the direction fields for both equations. What is the equilibrium solution in both cases? b. According to the direction fields, which reaction approaches its equilibrium solution faster?

Solve the following initial value problems and leave the solution in implicit form. Use graphing software to plot the solution. If the implicit solution describes more than one function, be sure to indicate which function corresponds to the solution of the initial value problem. $$z^{\prime}(x)=\frac{z^{2}+4}{x^{2}+16}, z(4)=2$$

Consider the general first-order linear equation \(y^{\prime}(t)+a(t) y(t)=f(t) .\) This equation can be solved, in principle, by defining the integrating factor \(p(t)=\exp \left(\int a(t) d t\right) .\) Here is how the integrating factor works. Multiply both sides of the equation by \(p\) (which is always positive) and show that the left side becomes an exact derivative. Therefore, the equation becomes $$p(t)\left(y^{\prime}(t)+a(t) y(t)\right)=\frac{d}{d t}(p(t) y(t))=p(t) f(t)$$ Now integrate both sides of the equation with respect to t to obtain the solution. Use this method to solve the following initial value problems. Begin by computing the required integrating factor. $$y^{\prime}(t)+\frac{2 t}{t^{2}+1} y(t)=1+3 t^{2}, y(1)=4$$

Equilibrium solutions \(A\) differential equation of the form \(y^{\prime}(t)=f(y)\) is said to be autonomous (the function \(f\) depends only on y. The constant function \(y=y_{0}\) is an equilibrium solution of the equation provided \(f\left(y_{0}\right)=0\) (because then \(y^{\prime}(t)=0\) and the solution remains constant for all \(t\) ). Note that equilibrium solutions correspond to horizontal lines in the direction field. Note also that for autonomous equations, the direction field is independent of t. Carry out the following analysis on the given equations. a. Find the equilibrium solutions. b. Sketch the direction field, for \(t \geq 0\). c. Sketch the solution curve that corresponds to the initial condition \(y(0)=1\). $$y^{\prime}(t)=\sin y$$

Euler's method on more general grids Suppose the solution of the initial value problem \(y^{\prime}(t)=f(t, y), y(a)=A\) is to be approximated on the interval \([a, b]\) a. If \(N+1\) grid points are used (including the endpoints), what is the time step \(\Delta t ?\) b. Write the first step of Euler's method to compute \(u_{1}\) c. Write the general step of Euler's method that applies, for \(k=0,1, \ldots, N-1\)

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