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If \(x=4\) tan \(\theta,\) express \(\sin \theta\) in terms of \(x\)

Short Answer

Expert verified
In this problem, we were given that \(x=4\text{tan}\ \theta\) and were asked to express \(\sin\theta\) in terms of \(x\). Through a series of steps using trigonometric identities and algebraic manipulations, we were able to find the expression: \(\sin \theta = \frac{x}{\sqrt{x^2 + 16}}\).

Step by step solution

01

Express \(\tan \theta\) in terms of \(x\)

We are given the equation \(x=4 \text{tan} \ \theta\). To express \(\tan \theta\) in terms of \(x\), divide both sides by 4: \(\text{tan} \ \theta = \frac{x}{4}\)
02

Recall the definition of \(\tan \theta\)

The tangent function is defined as the ratio of the sine function to the cosine function: \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)
03

Substitute the expression for \(\tan \theta\) in terms of \(x\)

Replace \(\tan \theta\) in the definition with the expression we found in Step 1: \(\frac{x}{4} = \frac{\sin \theta}{\cos \theta}\)
04

Find an expression for \(\sin \theta\)

To find an expression for \(\sin \theta\), we can multiply both sides of the equation by \(\cos \theta\): \(\sin \theta = \frac{x}{4} \cos \theta\)
05

Use the Pythagorean identity

Recall the Pythagorean identity: \(\sin^2\theta + \cos^2\theta = 1\) Since we have an expression for \(\sin \theta\) in terms of \(x\) and \(\cos \theta\), we can square both sides of the equation found in Step 4: \((\sin \theta)^2 = (\frac{x}{4}\cos \theta)^2\)
06

Replace \((\sin \theta)^2\) in the Pythagorean identity and solve for \(\cos^2\theta\)

Replace \((\sin \theta)^2\) in the Pythagorean identity with \((\frac{x}{4}\cos \theta)^2\): \((\frac{x}{4}\cos \theta)^2 + \cos^2\theta = 1\) Now, factor out \(\cos^2\theta\): \(\cos^2\theta (\frac{x^2}{16} + 1) = 1\) To find \(\cos^2\theta\), divide both sides by \((\frac{x^2}{16} + 1)\): \(\cos^2\theta = \frac{1}{\frac{x^2}{16} + 1}\)
07

Find \(\sin^2\theta\) using the Pythagorean identity

Using the Pythagorean identity and the expression for \(\cos^2\theta\) we found in Step 6: \(\sin^2\theta = 1 - \cos^2\theta\) Substitute the expression for \(\cos^2\theta\): \(\sin^2\theta = 1 - \frac{1}{\frac{x^2}{16} + 1}\)
08

Solve for \(\sin \theta\)

To find \(\sin \theta\), we take the square root of both sides of the equation. Keep in mind that taking a square root will give two different values, positive and negative. However, we will only consider the positive value here for simplicity: \(\sin \theta = \sqrt{1 - \frac{1}{\frac{x^2}{16} + 1}}\)
09

Simplify the expression

To simplify the expression for \(\sin \theta\), find a common denominator: \(\sin \theta = \sqrt{\frac{(\frac{x^2}{16} + 1) - 1}{\frac{x^2}{16} + 1}}\) Simplify the numerator: \(\sin \theta = \sqrt{\frac{\frac{x^2}{16}}{\frac{x^2}{16} + 1}}\) Finally, multiply both the numerator and denominator by 16 to get rid of the fractions: \(\sin \theta = \frac{x}{\sqrt{x^2 + 16}}\) Now we have expressed \(\sin \theta\) in terms of \(x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
In trigonometry, the tangent function, represented as \( \tan \theta \), plays a crucial role in relating the sine and cosine functions. It is defined as the ratio of the length of the opposite side to the adjacent side in a right-angled triangle. Mathematically, it is expressed as \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). This relationship is fundamental to understanding triangles and their properties.
  • This equation tells us that if you know the values of sine and cosine for a particular angle, you can easily find the tangent.
  • This property of tangent is extensively used in solving trigonometrical expressions where direct measurement might not be possible.
In our exercise, we transformed the equation \( x = 4 \tan \theta \) to express \( \tan \theta = \frac{x}{4} \). This simple transformation makes it easier for us to manipulate the expression further and relate it to other trigonometric identities.
Pythagorean Identity
The Pythagorean Identity is a vital aspect of trigonometry that forms the backbone of many trigonometric relationships. It states that for any angle \( \theta \), the identity \( \sin^2 \theta + \cos^2 \theta = 1 \) always holds true. This identity arises from the Pythagorean theorem in a unit circle, where the radius is 1.
  • This identity allows us to express one trigonometric function in terms of another, thereby simplifying complex expressions.
  • It also helps in proving other trigonometric equations and relationships.
In our given problem, we used this identity to find \( \cos^2 \theta \) when we already know the expression for \( \sin \theta \) in terms of \( x \). By manipulating this identity, we were able to arrive at expressions that describe the trigonometric relationships of known quantities.
Trigonometric Ratios
Trigonometric ratios are simple relationships between the angles and sides of a right-angled triangle. These ratios are fundamental in solving problems related to angles and distances. The primary trigonometric ratios are sine, cosine, and tangent. These are defined as:
  • Sine (\(\sin \theta\)): the ratio of the length of the opposite side to the hypotenuse.
  • Cosine (\(\cos \theta\)): the ratio of the length of the adjacent side to the hypotenuse.
  • Tangent (\(\tan \theta\)): the ratio of the length of the opposite side to the adjacent side.
Knowing these ratios helps in deriving other trigonometric identities and expressions. For example, in our problem, we needed to convert \( \tan \theta = \frac{x}{4} \) into related expressions of \( \sin \theta \) using the identities mentioned.
Understanding these basic ratios not only aids in solving elementary trigonometric problems but also provides the building blocks for more advanced mathematical concepts, such as calculus and analytical geometry. By manipulating these ratios and identities, one can solve a vast array of mathematical challenges, reinforcing their significance in the mathematical toolkit.

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Most popular questions from this chapter

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. Suppose \(\int_{a}^{b} f(x) d x\) is approximated with Simpson's Rule using \(n=18\) subintervals, where \(\left|f^{(4)}(x)\right| \leq 1\) on \([a, b]\) The absolute error \(E_{S}\) in approximating the integral satisfies \(E_{s} \leq \frac{(\Delta x)^{5}}{10}\) 1\. If the number of subintervals used in the Midpoint Rule is increased by a factor of \(3,\) the error is expected to decrease by a factor of \(8 .\) c. If the number of subintervals used in the Trapezoid Rule is increased by a factor of \(4,\) the error is expected to decrease by a factor of \(16 .\)

For a real number \(a\), suppose \(\lim _{x \rightarrow a^{+}} f(x)=-\infty\) or \(\lim _{x \rightarrow a^{+}} f(x)=\infty .\) In these cases, the integral \(\int_{a}^{\infty} f(x) d x\) is improper for two reasons: \(\infty\) appears in the upper limit and \(f\) is unbounded at \(x=a .\) It can be shown that \(\int_{a}^{\infty} f(x) d x=\int_{a}^{c} f(x) d x+\int_{c}^{\infty} f(x) d x\) for any \(c>a .\) Use this result to evaluate the following improper integrals. $$\int_{1}^{\infty} \frac{d x}{x \sqrt{x-1}}$$

The family \(f(x)=\frac{1}{x^{p}}\) revisited Consider the family of functions \(f(x)=\frac{1}{x^{p}},\) where \(p\) is a real number. For what values of \(p\) does the integral \(\int_{0}^{1} f(x) d x\) exist? What is its value?

Determine whether the following integrals converge or diverge. $$\int_{1}^{\infty} \frac{2+\cos x}{x^{2}} d x$$

An integrand with trigonometric functions in the numerator and denominator can often be converted to a rational function using the substitution \(u=\tan (x / 2)\) or, equivalently, \(x=2 \tan ^{-1} u .\) The following relations are used in making this change of variables. $$A: d x=\frac{2}{1+u^{2}} d u \quad B: \sin x=\frac{2 u}{1+u^{2}} \quad C: \cos x=\frac{1-u^{2}}{1+u^{2}}$$ $$\text { Evaluate } \int_{0}^{\pi / 3} \frac{\sin \theta}{1-\sin \theta} d \theta$$.

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