Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Choosing an integration strategy Identify a technique of integration for evaluating the following integrals. If necessary, explain how to first simplify the integrals before applying the suggested technique of integration. You do not need to evaluate the integrals. (1+tanx)sec2xdx

Short Answer

Expert verified
The integral (1+tanx)sec2xdx is simplified into two separate integrals: sec2xdx and tanxsec2xdx. The integration technique used for sec2xdx is directly applying the antiderivative rule, while the integration technique used for tanxsec2xdx is substitution method with u=tanx.

Step by step solution

01

Distribute the secant squared function

With the given integral, we can distribute the sec2x term to both parts inside the parenthesis: (1+tanx)sec2xdx=(sec2x+tanxsec2x)dx Now that we have simplified the integral, let's identify an integration technique for each part of the sum:
02

Identify integration technique for the first term

For the first term, sec2xdx, we can directly apply the definition of the antiderivative as it is a well-known rule that: sec2xdx=tanx+C
03

Identify integration technique for the second term

For the second term, tanxsec2xdx, we apply the substitution method. Let u=tanx. Then, the derivative of u with respect to x is: dudx=sec2xdu=sec2xdx By making the substitution and changing the integral, we have: tanxsec2xdx=udu We will find an antiderivative of `u` with respect to `x`. In summary: - For sec2xdx, the integration technique used is directly applying the antiderivative rule. - For tanxsec2xdx, the integration technique used is substitution method with u=tanx.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Substitution
The integration by substitution method, also known as the u-substitution, is a powerful technique in calculus for finding the antiderivatives of more complex functions. It involves replacing a part of the integrand with a new variable, typically denoted as 'u'.

For instance, if we have a composite function like a trigonometric expression multiplied by its own derivative, we look for a substitution that will simplify the integral. Once you've determined a suitable substitution, you find the differential of 'u' (denoted as du) and replace the corresponding parts of the integrand with 'u' and 'du'.

This technique not only simplifies the integral but also reveals familiar patterns that are easier to integrate. After integrating with respect to 'u', you then substitute back the original variables to complete the problem.
Antiderivatives
Antiderivatives are the reverse process of differentiation. Simply put, if differentiation gives you the speed of a car at any moment, antiderivatives tell you the position of the car over time, provided you know where you started (this is the '+ C' in the integrals).

When you take the antiderivative of a function, you're essentially looking for a function whose derivative is the original function you started with. In the context of the integral of sec2xdx, we know from calculus that the antiderivative of sec2x is tanx because the derivative of tanx gives us sec2x. Therefore, sec2xdx=tanx+C, where 'C' represents the constant of integration.
Secant Squared Function
In trigonometry, the secant function, denoted secx, is defined as the reciprocal of the cosine function. The secant squared function is the square of the secant function, sec2x, and it plays a significant role in integration. An integral involving sec2x often arises in problems involving trigonometric identities.

One of the key aspects to remember is that the derivative of the tangent function, tanx, is sec2x. This relationship makes finding antiderivatives of sec2x straightforward, since we readily know it will lead to tanx+C. Recognizing these kinds of relationships between trigonometric functions is an essential skill when solving integrals that involve trigonometric terms.
Trigonometric Integration
Trigonometric integration involves finding the antiderivatives of trigonometric functions. This area of integration can be tricky due to the cyclical nature of trigonometric functions, but it is manageable with knowledge of some key insights and identities. When faced with an integral that includes trigonometric functions, look for opportunities to apply these identities to simplify the problem.

Trigonometric integrals often involve strategies such as substituting trigonometric identities, using u-substitution, or rewriting the integrands in a more workable form. For example, recognizing that sec2xdx simplifies to tanx+C or that sinxcosxdx can be simplified by substitution are key steps in solving trigonometric integrals. Mastery of these techniques opens the door to solving a wide variety of integrals involving trigonometric functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the following integrals converge or diverge. 3dxlnx( Hint: lnxx.)

An integrand with trigonometric functions in the numerator and denominator can often be converted to a rational function using the substitution u=tan(x/2) or, equivalently, x=2tan1u. The following relations are used in making this change of variables. A:dx=21+u2duB:sinx=2u1+u2C:cosx=1u21+u2  Evaluate 0π/2dθcosθ+sinθ.

The nucleus of an atom is positively charged because it consists of positively charged protons and uncharged neutrons. To bring a free proton toward a nucleus, a repulsive force F(r)=kqQ/r2 must be overcome, where q=1.6×1019C( coulombs ) is the charge on the proton, k=9×109Nm2/C2,Q is the charge on the nucleus, and r is the distance between the center of the nucleus and the proton. Find the work required to bring a free proton (assumed to be a point mass) from a large distance (r) to the edge of a nucleus that has a charge Q=50q and a radius of 6×1011m.

Using one computer algebra system, it was found that dx1+sinx=sinx1cosx, and using another computer algebra system, it was found that dx1+sinx=2sin(x/2)cos(x/2)+sin(x/2). Reconcile the two answers.

Let R be the region between the curves y=ecx and y=ecx on the interval [a,), where a0 and c>0. The center of mass of R is located at (x¯,0) where x¯=axecxdxaecxdx. (The profile of the Eiffel Tower is modeled by the two exponential curves; see the Guided Project The exponential Eiffel Tower. ) a. For a=0 and c=2, sketch the curves that define R and find the center of mass of R. Indicate the location of the center of mass. b. With a=0 and c=2, find equations of the lines tangent to the curves at the points corresponding to x=0 c. Show that the tangent lines intersect at the center of mass. d. Show that this same property holds for any a0 and any c>0; that is, the tangent lines to the curves y=±ecx at x=a intersect at the center of mass of R

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free