Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Express \(3^{x}, x^{\pi},\) and \(x^{\sin x}\) using the base \(e\).

Short Answer

Expert verified
Question: Rewrite the expressions \(3^{x}, x^{\pi},\) and \(x^{\sin x}\) using base \(e\). Answer: The expressions rewritten using base \(e\) are \(3^{x} = e^{x \ln 3}, x^{\pi} = e^{\pi \ln x},\) and \(x^{\sin x} = e^{\sin x \ln x}\).

Step by step solution

01

Rewrite first expression using base \(e\)

We have the expression \(3^{x}\). Using the property \(a^{b} = e^{b \ln a}\), we can rewrite it as follows: \(3^{x} = e^{x \ln 3}\)
02

Rewrite second expression using base \(e\)

Now, for the expression \(x^{\pi}\). Using the property \(a^{b} = e^{b \ln a}\), we can rewrite it as follows: \(x^{\pi} = e^{\pi \ln x}\)
03

Rewrite third expression using base \(e\)

Finally, for the expression \(x^{\sin x}\). Using the property \(a^{b} = e^{b \ln a}\), we can rewrite it as follows: \(x^{\sin x} = e^{\sin x \ln x}\)
04

Final answer using base \(e\)

Therefore, the given expressions expressed using the base \(e\) are: \(3^{x} = e^{x \ln 3}\\ x^{\pi} = e^{\pi \ln x}\\ x^{\sin x} = e^{\sin x \ln x}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Base e Conversion
Converting expressions into base \( e \) is a useful technique in mathematics, particularly in calculus and analysis. Base \( e \), also known as Euler's number, is approximately 2.71828. It is the base of the natural logarithm and is a fundamental constant in mathematics.
When converting an expression like \( a^b \) into base \( e \), we use the formula:
  • \( a^b = e^{b \ln a} \)
This is possible because any number raised to a power can be expressed as a power of \( e \). The conversion happens by realizing that raising a number to a power means scaling the exponent of \( e \) using the natural logarithm.
For instance, in the exercise, \( 3^x \) can be rewritten as \( e^{x \ln 3} \). This conversion helps in simplifying differentiation and integration tasks, making it easier to deal with complex exponents.
Natural Logarithm
The natural logarithm, denoted \( \ln \), is the logarithm to the base \( e \). It is the inverse operation of exponentiation with base \( e \). This means that if \( e^y = x \), then \( \ln x = y \). Understanding the natural logarithm is crucial for converting powers into expressions that involve base \( e \).
In our conversion formula \( a^b = e^{b \ln a} \), the \( \ln a \) component computes the power that \( e \) must be raised to obtain \( a \). Hence, \( \ln \) translates multiplication in the power into addition in the exponent, matching the properties of exponential functions.
Some key properties of natural logarithms include:
  • \( \ln(ab) = \ln a + \ln b \)
  • \( \ln(a^b) = b \ln a \)
  • \( \ln(1) = 0 \)
These properties are often used to simplify complex exponential expressions.
Exponentiation
Exponentiation is the mathematical operation involving two numbers, the base and the exponent. It is written as \( a^b \) where \( a \) is the base and \( b \) is the exponent. This operation signifies the repeated multiplication of the base \( a \).
To convert expressions such as \( x^\pi \) and \( x^{\sin x} \) to base \( e \), we use the property \( a^b = e^{b \ln a} \). This transformation is essential when dealing with calculus problems as it can simplify the differentiation and integration of functions with variable bases and exponents.
Here are some basic rules of exponentiation:
  • \( a^0 = 1 \) for any \( a eq 0 \)
  • \( a^1 = a \)
  • \((a^m)^n = a^{m \cdot n}\)
Expressing expressions in terms of \( e \) is often necessary for solving complex mathematical problems efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Radioiodine treatment Roughly 12,000 Americans are diagnosed with thyroid cancer every year, which accounts for \(1 \$$ of all cancer cases. It occurs in women three times as frequently as in men. Fortunately, thyroid cancer can be treated successfully in many cases with radioactive iodine, or \)1-131 .\( This unstable form of iodine has a half-life of 8 days and is given in small doses measured in millicuries. a. Suppose a patient is given an initial dose of 100 millicuries. Find the function that gives the amount of \)1-131\( in the body after \)t \geq 0\( days. b. How long does it take the amount of \)1-131\( to reach \)10 \%\( of the initial dose? c. Finding the initial dose to give a particular patient is a critical calculation. How does the time to reach \)10 \%\( of the initial dose change if the initial dose is increased by \)5 \% ?$

Evaluate the following integrals. Include absolute values only when needed. $$\int_{1}^{e^{2}} \frac{(\ln x)^{5}}{x} d x$$

Evaluate the following integrals. Include absolute values only when needed. $$\int \frac{e^{5+\sqrt{x}}}{\sqrt{x}} d x$$

L'Hôpital loophole Explain why I'Hôpital's Rule fails when applied to the limit \(\lim _{x \rightarrow \infty} \frac{\sinh x}{\cosh x}\) and then find the limit another way.

Assume \(y>0\) is fixed and \(x>0 .\) Show that \(\frac{d}{d x}(\ln x y)=\frac{d}{d x}(\ln x) .\) Recall that if two functions have the same derivative, then they differ by an additive constant. Set \(x=1\) to evaluate the constant and prove that \(\ln x y=\ln x+\ln y\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free