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Give two examples of processes that are modeled by exponential decay.

Short Answer

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#Question# Provide two examples of processes that are modeled by exponential decay and briefly explain how they are modeled using exponential decay equations. #Answer# 1) Radioactive Decay: In this process, the number of radioactive atoms decreases over time following an exponential decay model given by N(t) = N * e^{-λt}, where N(t) is the number of atoms remaining at time t, N is the initial number of atoms, λ is the decay constant, and e is the base of the natural logarithm. 2) Cooling of an Object: Newton's law of cooling states that the rate of an object's cooling is proportional to the difference between the object's temperature and the surrounding environment's temperature. The temperature of the object at time t can be modeled by T(t) = T_e + (T0 - T_e) * e^{-kt}, where T(t) is the temperature of the object at time t, T0 is the initial temperature, T_e is the surrounding environment's temperature, e is the base of the natural logarithm, and k is a constant related to the object's cooling properties.

Step by step solution

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Example 1: Radioactive Decay

Radioactive decay is a process through which an unstable atomic nucleus loses energy by emitting radiation. In this process, the number of atoms of a radioactive material decreases over time, following an exponential decay model. Suppose we have an initial amount of N radioactive atoms and the decay constant is denoted by λ. The number of remaining atoms after a certain time t will be given by: N(t) = N * e^{-λt} In this equation, N(t) represents the number of atoms remaining at time t, N is the initial number of atoms, λ is the decay constant and e is the base of the natural logarithm.
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Example 2: Cooling of an Object

Another example of a process modeled by exponential decay is the cooling of an object over time. Newton's law of cooling states that the rate at which an object cools is proportional to the difference between the object's temperature and the temperature of the surrounding environment. Suppose we have an object with an initial temperature T(0) = T0 and the surrounding environment temperature being T_e. The temperature of the object at time t will be given by: T(t) = T_e + (T0 - T_e) * e^{-kt} Where T(t) represents the temperature of the object at time t, T0 is the initial temperature of the object, T_e is the temperature of the surrounding environment, e is the base of the natural logarithm and k is a constant related to the object's cooling properties.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
At its core, radioactive decay is a fundamental process by which an unstable atomic nucleus releases energy to reach a more stable state. Different isotopes (or versions of an element with varying numbers of neutrons) decay at different rates, and this rate of decay is predictable, described by an elegant mathematical model.

Most importantly, the decay doesn't happen all at once but gradually over time, and the rate of decay is proportional to the amount of substance remaining. This is what scientists refer to as an exponential decay process. The formula you see in exercises, N(t) = N \( e^{-\lambda t} \), succinctly captures this relationship. N(t) is the remaining quantity of the substance at time t, N is the initial quantity, and \(\lambda\) is a positive constant specific to the substance, aptly named the decay constant, indicative of the speed at which the substance undergoes decay.

Key takeaway? As time passes, the quantity of the radioactive substance decreases exponentially, never reaching zero but getting infinitesimally close over an infinite amount of time.
Newton's Law of Cooling
Closely related to the pattern of exponential decay, Newton's law of cooling reveals how the temperature of a warm object decreases over time. Similar to radioactive substances, the cooling of an object is not at a constant rate but depends on the difference between the object's current temperature and the ambient temperature of its surroundings.

Mathematically, Newton described this phenomenon with the equation T(t) = T_e + (T0 - T_e) \( e^{-kt} \). Here, T(t) symbolizes the temperature of the object at any time t, T_e signifies the environment’s constant temperature, and T0 is what the object's initial temperature was. The k is another decay constant, altering how fast the object cools depending on its properties, such as thermal conductivity and size.

Essentially, the exponential factor \( e^{-kt} \) governs the rate of temperature change, showcasing that as the difference in temperatures drops, the cooling slows down, leading to a gradual stabilization of the object’s temperature with the environment over time.
Decay Constant
The idea of a decay constant is pivotal in understanding exponential decay. It's not just a number; it symbolizes how swiftly a quantity decreases over time. Specific to each process, be it radioactive decay or cooling, the constant tells us the proportion of the substance or the difference in temperature that decays in a unit of time.

Relationship with Half-Life

Take radioactive decay, for instance. The decay constant \(\lambda\) is intertwined with another concept called the half-life, the time it takes for half the radioactive atoms in a sample to decay. The two are related mathematically by the natural logarithm: half-life = \( \frac{\ln(2)}{\lambda} \), where \( \ln \) is the natural logarithm.

The higher the decay constant, the faster the quantity diminishes, indicating a reactive substance or a highly conductive material in the context of cooling. Thus, by understanding the decay constant, one can predict the longevity of a substance or the cooling time for a meal straight out of the oven.
Natural Logarithm Base e
Finally, to fully grasp concepts like decay constant and exponential decay processes, a solid understanding of the natural logarithm base e is essential. What's special about e, approximately equal to 2.71828, is it arises naturally in various contexts of mathematics, especially in continuous growth or decay situations.

The natural logarithm, denoted by ln, is the inverse operation of taking e to a power. Specifically, for a positive number x, ln(x) answers the question: 'To what power must we raise e to get x?'. This function is key in calculating the half-life from the decay constant as mentioned earlier and appears in the formulas that describe both radioactive decay and Newton's law of cooling.

In sum, this quirky number e is not just any ordinary constant but the cornerstone of accurately modeling processes that change exponentially over time, helping us untangle the mysteries of atomic nuclei or predict when a warm pie will be cool enough to eat without burning our tongues.

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Most popular questions from this chapter

Caffeine After an individual drinks a beverage containing caffeine, the amount of caffeine in the bloodstream can be modeled by an exponential decay function, with a half-life that depends on several factors, including age and body weight. For the sake of simplicity, assume the caffeine in the following drinks immediately enters the bloodstream upon consumption. An individual consumes two cups of coffee, each containing \(90 \mathrm{mg}\) of caffeine, two hours apart. Assume the half-life of caffeine for this individual is 5.7 hours. a. Determine the amount of caffeine in the bloodstream 1 hour after drinking the first cup of coffee. b. Determine the amount of caffeine in the bloodstream 1 hour after drinking the second cup of coffee.

Designing exponential decay functions Devise an exponential decay function that fits the following data; then answer the accompanying questions. Be sure to identify the reference point \((t=0)\) and units of time. Drug metabolism A drug is eliminated from the body at a rate of \(15 \% /\) hr. After how many hours does the amount of drug reach \(10 \%\) of the initial dose?

Acceleration, velocity, position Suppose the acceleration of an object moving along a line is given by \(a(t)=-k v(t),\) where \(k\) is a positive constant and \(v\) is the object's velocity. Assume the initial velocity and position are given by \(v(0)=10\) and \(s(0)=0\) respectively. a. Use \(a(t)=v^{\prime}(t)\) to find the velocity of the object as a function of time. L. Use \(v(t)=s^{\prime}(t)\) to find the position of the object as a function of time. c. Use the fact that \(\frac{d v}{d t}=\frac{d v}{d s} \frac{d s}{d t}\) (by the Chain Rule) to find the velocity as a function of position.

Use l'Hôpital's Rule to evaluate the following limits. $$\lim _{x \rightarrow \infty} \frac{1-\operatorname{coth} x}{1-\tanh x}$$

Depreciation of equipment A large die-casting machine used to make automobile engine blocks is purchased for \(\$ 2.5\) million. For tax purposes, the value of the machine can be depreciated by \(6.8 \%\) of its current value each year. a. What is the value of the machine after 10 years? b. After how many years is the value of the machine \(10 \%\) of its original value?

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