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Explain the differences between computing the derivatives of functions that are defined implicitly and explicitly.

Short Answer

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Answer: The main differences between computing the derivatives of explicit and implicit functions are the methods used for differentiation and the complexity involved. In explicit functions, we can directly calculate the derivatives using standard differentiation rules like the sum, product, quotient, and chain rules. In implicit functions, we differentiate both sides of the equation and solve for the derivative using implicit differentiation. Generally, implicit differentiation is more complex and involves more algebraic manipulations compared to explicit differentiation.

Step by step solution

01

Understanding Explicit Functions

In an explicit function, one variable is expressed solely in terms of the other. For example, y = f(x) = 3x^2 + 2x +1. To compute the derivative of an explicit function, we use the standard rules of differentiation (sum, product, quotient, and chain rules).
02

Understanding Implicit Functions

In an implicit function, both dependent and independent variables are intertwined, making it difficult to isolate one variable from the other. For example, x^2 + y^2 = 1. To compute the derivative of an implicit function, we make use of implicit differentiation. It involves differentiating both sides of the equation with respect to the independent variable (usually x) while treating the other variable (usually y) as an implicit function of x. Then, we solve for dy/dx.
03

Comparing Derivatives of Implicit and Explicit Functions

Derivatives of explicit functions can be directly calculated using standard differentiation rules, while derivatives of implicit functions are determined indirectly by differentiating both sides of the equation and solving for the derivative. Explicit differentiation is generally simpler and less demanding; implicit differentiation is more complex and might involve more algebraic manipulations to reach the final result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Explicit Functions
Explicit functions are the kind of functions where you can clearly solve for one variable in terms of the other. This is like having a set recipe that you follow each time. For example, in the function \( y = 3x^2 + 2x + 1 \), \( y \) is expressed explicitly in terms of \( x \). You can think of explicit functions as straightforward and simple because they are easier to manipulate and compute. To find the derivative of an explicit function, you don't have to do anything too fancy; you just apply the basic rules of differentiation. These include rules like the sum rule, product rule, and chain rule, among others. By applying these rules, you can directly find how the function's value changes with respect to \( x \).
Differentiate Implicitly
Implicit functions are quite different from explicit functions. They are more like puzzles because the dependent and independent variables are tangled together, not neatly separated. An example of an implicit equation is \( x^2 + y^2 = 1 \). Here, it's not immediately possible to express \( y \) in terms of \( x \) without some transformation. To find the derivative of an implicit function, you use a process called implicit differentiation. This involves differentiating both sides of the equation with respect to \( x \), but you also treat \( y \) as a function of \( x \). This means you'll differentiate \( y \) using the chain rule whenever it appears. Once both sides are differentiated, you solve for \( \frac{dy}{dx} \), which gives you the rate of change of \( y \) with respect to \( x \). Implicit differentiation can be tricky but is a useful tool for dealing with complex relationships.
Derivatives
A derivative is a way to express how a function changes as its input changes. Think of it as the function's rate of change or its slope. When we're dealing with explicit functions, finding derivatives is relatively straightforward. Using the mathematical differentiation rules, you can apply them directly to compute the derivative. In the case of explicit functions, it's like a direct conversion. You input the function, use the rules, and output the derivative. However, with implicit functions, derivatives are not so straightforward. You have to understand the intertwined relationship between the variables first and then use implicit differentiation to tease out the derivative. Regardless, derivatives are crucial tools for understanding functions' behaviors, especially in calculus.
Mathematical Differentiation Rules
Differentiation rules make the process of finding derivatives simpler and more systematic. These rules include the sum rule, product rule, quotient rule, and chain rule. They are the building blocks of calculus. Here’s a quick overview:
  • The **sum rule** allows you to differentiate each term of a sum separately.
  • The **product rule** comes into play when you need to differentiate products of two functions.
  • The **quotient rule** is used when the function is a division of two other functions.
  • Lastly, the **chain rule** helps when you have a function of a function. For example, differentiating \( f(g(x)) \).
For explicit functions, these rules are often applied directly. But for implicit functions, these rules still apply, yet the process involves additional algebraic manipulation as you differentiate indirectly. Understanding these rules will help you solve derivatives, whether you are dealing with explicit or implicit functions.

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Most popular questions from this chapter

Carry out the following steps. \(x.\) a. Use implicit differentiation to find \(\frac{d y}{d x}.\) b. Find the slope of the curve at the given point. $$x y^{5 / 2}+x^{3 / 2} y=12 ;(4,1)$$

Work carefully Proceed with caution when using implicit differentiation to find points at which a curve has a specified slope. For the following curves, find the points on the curve (if they exist) at which the tangent line is horizontal or vertical. Once you have found possible points, make sure that they actually lie on the curve. Confirm your results with a graph. $$x^{2}(y-2)-e^{y}=0$$

The following equations implicitly define one or more functions. a. Find \(\frac{d y}{d x}\) using implicit differentiation. b. Solve the given equation for \(y\) to identify the implicitly defined functions \(y=f_{1}(x), y=f_{2}(x), \ldots.\) c. Use the functions found in part (b) to graph the given equation. \(y^{2}=\frac{x^{2}(4-x)}{4+x}\) (right strophoid)

Tangency question It is easily verified that the graphs of \(y=x^{2}\) and \(y=e^{x}\) have no point of intersection (for \(x>0\) ), while the graphs of \(y=x^{3}\) and \(y=e^{x}\) have two points of intersection. It follows that for some real number \(2 < p < 3,\) the graphs of \(y=x^{p}\) and \(y=e^{x}\) have exactly one point of intersection (for \(x > 0) .\) Using analytical and/or graphical methods, determine \(p\) and the coordinates of the single point of intersection.

Assume \(f\) and \(g\) are differentiable on their domains with \(h(x)=f(g(x)) .\) Suppose the equation of the line tangent to the graph of \(g\) at the point (4,7) is \(y=3 x-5\) and the equation of the line tangent to the graph of \(f\) at (7,9) is \(y=-2 x+23\) a. Calculate \(h(4)\) and \(h^{\prime}(4)\) b. Determine an equation of the line tangent to the graph of \(h\) at \((4, h(4))\)

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