Chapter 2: Problem 1
How is \(\lim _{x \rightarrow a} p(x)\) calculated if \(p\) is a polynomial function?
Short Answer
Expert verified
Answer: The limit of a polynomial function as x approaches a specific value a is the value of the polynomial function at x=a.
Step by step solution
01
1. Understand polynomial functions
Polynomial functions can be defined as the sum of terms, each consisting of a constant (coefficient) multiplied by a power of the independent variable. The general form of a polynomial function is \(p(x) = c_nx^n + c_{n-1}x^{n-1} + ... + c_1x + c_0\), where \(c_i\) are the coefficients (constants) and \(n\) is a non-negative integer. Polynomial functions are continuous and differentiable everywhere.
02
2. Properties of limits
When solving limits, it's essential to know the properties associated with them. Some of these properties are:
1. The limit of a constant is the constant itself, i.e., \(\lim_{x\to a} c = c\).
2. The limit of the independent variable as it approaches some value is that value, i.e., \(\lim_{x\to a} x = a\).
3. The limit of a sum or difference of functions is the sum or difference of their respective limits, i.e., \(\lim_{x\to a} (f(x) \pm g(x)) = \lim_{x\to a} f(x) \pm \lim_{x\to a} g(x)\).
4. The limit of a product of functions is the product of their respective limits, i.e., \(\lim_{x\to a} (f(x) \cdot g(x)) = \lim_{x\to a} f(x) \cdot \lim_{x\to a} g(x)\).
03
3. Calculate the limit
Since polynomial functions are continuous and differentiable everywhere, we can find the limit by direct substitution, i.e., substitute \(x\) with \(a\) in the polynomial function \(p(x)\). Using the properties of limits mentioned previously, we have:
\(\lim_{x\to a} p(x) = \lim_{x\to a} (c_nx^n + c_{n-1}x^{n-1} + ... + c_1x + c_0)\)
Applying the properties, we get:
\(\lim_{x\to a} p(x) = c_n ( \lim_{x\to a} x^n) + c_{n-1}( \lim_{x\to a} x^{n-1}) + ... + c_1( \lim_{x\to a} x) + c_0\)
Now, using the limit of the independent variable, property 2:
\(\lim_{x\to a} p(x) = c_na^n + c_{n-1}a^{n-1} + ... + c_1a + c_0\)
Hence, the limit of a polynomial function as \(x\) approaches \(a\) is the value of the polynomial at \(x=a\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Function
A polynomial function is a mathematical expression made up of a sum of terms, where each term consists of a constant (called a coefficient) multiplied by a power of the variable (usually \(x\)). The general form of a polynomial function is written as:\[ p(x) = c_n x^n + c_{n-1} x^{n-1} + \, ... \, + c_1 x + c_0 \]Here:
- \(c_n, c_{n-1}, ..., c_1, c_0\) are constants known as coefficients.
- \(n\) is a non-negative integer, indicating the highest power of the polynomial, which is also called the degree of the polynomial.
Properties of Limits
When we need to calculate the limit of a function, we use several useful properties of limits. Understanding these properties makes solving limit problems much more manageable. Here are some essential properties:
- The limit of a constant is the constant itself: \( \lim_{x \to a} c = c \).
- The limit of the variable \(x\) as it approaches some value \(a\) is \(a\): \( \lim_{x \to a} x = a \).
- The limit of a sum or difference of functions is equal to the sum or difference of their respective limits: \( \lim_{x \to a} (f(x) \pm g(x)) = \lim_{x \to a} f(x) \pm \lim_{x \to a} g(x) \).
- The limit of a product of functions is the product of their limits: \( \lim_{x \to a} (f(x) \cdot g(x)) = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x) \).
Direct Substitution
Direct substitution is a straightforward technique used to find the limit of a function, especially when dealing with polynomial functions. Because polynomial functions are continuous, you can find the limit by simply substituting the given value directly into the polynomial. Here’s how it works:For a polynomial \( p(x) = c_n x^n + c_{n-1} x^{n-1} + \, ... \, + c_1 x + c_0 \), the limit as \( x \to a \) is:\[ \lim_{x \to a} p(x) = c_n a^n + c_{n-1} a^{n-1} + \, ... \, + c_1 a + c_0 \]The reason this works so effortlessly is due to the continuity of polynomials. Since polynomial functions don’t have any breaks or undefined points, the value they take at \( x = a \) is exactly the limit value as \( x \to a \).To practically apply direct substitution:
- Take the given polynomial.
- Replace \(x\) with \(a\) in the expression.
- Simplify the expression to get the value of the limit.