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At what points of \(\mathbb{R}^{2}\) are the following functions continuous? $$S(x, y)=\frac{2 x y}{x^{2}-y^{2}}$$

Short Answer

Expert verified
Answer: The function S(x, y) is continuous on \(\mathbb{R}^{2}\) excluding the points lying on the lines y = x and y = -x.

Step by step solution

01

Find the Domain of the Function

We must first determine the domain of the function by finding the values of x and y for which S(x, y) exists. The function will be undefined when the denominator is equal to zero: $$x^{2} - y^{2} = 0$$ The equation can be factored as follows: $$(x+y)(x-y) = 0$$ There are two cases when the denominator is zero: 1. x + y = 0 or x = -y 2. x - y = 0 or x = y These are the values of x and y where the function S(x, y) is not defined (undefined).
02

Continuity at Other Points

Now, we must examine the continuity of the function at points where S(x, y) is defined. Since we have a rational function (a ratio of polynomials), it is continuous everywhere on its domain. Therefore, S(x, y) is continuous at every point (x, y) which satisfies: 1. x ≠ y 2. x ≠ -y
03

List the Continuous Points

Now that we know the continuity conditions for the function, we can list the points of \(\mathbb{R}^{2}\) where the function S(x, y) is continuous: 1. x ≠ y, or the set of all points (x, y) not lying on the line y = x. 2. x ≠ -y, or the set of all points (x, y) not lying on the line y = -x. Thus, the function S(x, y) is continuous on \(\mathbb{R}^{2}\) excluding the points lying on the lines y = x and y = -x.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
Understanding the domain of a function is fundamental in calculus, especially when analyzing continuity. The domain of a function consists of all the input values (often 'x' values) for which the function is defined. In simpler terms, it's the set of all possible x-values that won't cause any issues, like division by zero or taking the square root of a negative number in the context of real numbers.

For rational functions, the domain is all real numbers except those that make the denominator zero. Identifying the domain helps avoid undefined behavior in functions and is the first step toward understanding where a function can be continuous. For example, in the function \(S(x, y)=\frac{2 x y}{x^{2}-y^{2}}\), the domain is restricted due to the denominator. The equation \(x^{2} - y^{2} = 0\) implies that we exclude values where \(x = \pm y\), because these would make the denominator zero, thus undefined. Appreciating the domain allows students to better grasp the concept of continuity linked directly to the function's defined region.
Rational Functions
Rational functions are ratios of polynomials, like \(S(x, y)\) in the example, where we have a polynomial in the numerator and another in the denominator. A major characteristic of these functions is how they behave around values that are not included in their domain - this can lead to vertical asymptotes, holes, or undefined points in their graph.

Rational functions are typically discontinuous at points where the denominator equals zero. However, excluding these points from consideration, they are continuous everywhere else on their domain. This puts an emphasis on the importance of understanding not just the concept of functions but also of how they behave over different intervals and the significance of their constraints.
Limits and Continuity
The terms 'limits' and 'continuity' are intertwined in calculus. A function is continuous at a point if the limit of the function as it approaches that point exists and is equal to the function's value at that point. It's about predicting function values as you get infinitely close to a certain x-value without any unexpected jumps or gaps.

A pivotal piece in calculus puzzles, continuity requires a function to be defined at a point, the limit as it approaches the point must exist, and the two values should be the same. When evaluating rational functions like \(S(x, y)\), if they are defined and smooth (no abrupt changes in value) at a particular point, then they are continuous there. However, the catch is that limits and continuity can only be discussed for points within the domain. For \(S(x, y)\), this means everywhere but where \(x = y\) or \(x = - y\), as these are the breach points on the fabric of S’s domain where continuity is disrupted.

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Most popular questions from this chapter

Use Lagrange multipliers in the following problems. When the constraint curve is unbounded, explain why you have found an absolute maximum or minimum value. Maximum area rectangle in an ellipse Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse \(4 x^{2}+16 y^{2}=16\)

Find an equation of the plane passing through the point (3,2,1) that slices off the solid in the first octant with the least volume.

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$p(x, y)=1-|x-1|+|y+1|$$

Let \(P\) be a plane tangent to the ellipsoid \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1\) at a point in the first octant. Let \(T\) be the tetrahedron in the first octant bounded by \(P\) and the coordinate planes \(x=0, y=0,\) and \(z=0 .\) Find the minimum volume of \(T .\) (The volume of a tetrahedron is one-third the area of the base times the height.)

Steiner's problem for three points Given three distinct noncollinear points \(A, B,\) and \(C\) in the plane, find the point \(P\) in the plane such that the sum of the distances \(|A P|+|B P|+|C P|\) is a minimum. Here is how to proceed with three points, assuming the triangle formed by the three points has no angle greater than \(2 \pi / 3\left(120^{\circ}\right)\) a. Assume the coordinates of the three given points are \(A\left(x_{1}, y_{1}\right)\) \(B\left(x_{2}, y_{2}\right),\) and \(C\left(x_{3}, y_{3}\right) .\) Let \(d_{1}(x, y)\) be the distance between \(A\left(x_{1}, y_{1}\right)\) and a variable point \(P(x, y) .\) Compute the gradient of \(d_{1}\) and show that it is a unit vector pointing along the line between the two points. b. Define \(d_{2}\) and \(d_{3}\) in a similar way and show that \(\nabla d_{2}\) and \(\nabla d_{3}\) are also unit vectors in the direction of the line between the two points. c. The goal is to minimize \(f(x, y)=d_{1}+d_{2}+d_{3}\) Show that the condition \(f_{x}=f_{y}=0\) implies that \(\nabla d_{1}+\nabla d_{2}+\nabla d_{3}=0\) d. Explain why part (c) implies that the optimal point \(P\) has the property that the three line segments \(A P, B P\), and \(C P\) all intersect symmetrically in angles of \(2 \pi / 3\) e. What is the optimal solution if one of the angles in the triangle is greater than \(2 \pi / 3\) (just draw a picture)? f. Estimate the Steiner point for the three points (0,0),(0,1) and (2,0)

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