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What is the curvature of a straight line?

Short Answer

Expert verified
Answer: The curvature of a straight line is 0.

Step by step solution

01

Understand the concept of curvature

Curvature is a measure of how a curve deviates from a straight line. Mathematically, curvature can be defined for any curve in the plane or in space. It is the magnitude of the rate of change of the unit tangent vector of a curve with respect to the curve's natural parameter (also known as arc length).
02

Know the formula for curvature

The formula for curvature of a curve can be given as: k = |\frac{d\mathbf{T}}{ds}|, where k is the curvature, d\mathbf{T} represents the derivative of the unit tangent vector with respect to the arc length s. The absolute value indicates that the curvature is always positive (or zero in the case of a straight line).
03

Find the tangent vector of a straight line

A straight line has a constant direction, which means the tangent vector does not change along the line. Therefore, the unit tangent vector \mathbf{T} of a straight line will be constant.
04

Calculate the derivative of the tangent vector

Since the unit tangent vector \mathbf{T} of a straight line is constant, its derivative will be: \frac{d\mathbf{T}}{ds} = 0
05

Apply the formula to find the curvature

Using the curvature formula, we can find the curvature of a straight line: k = |\frac{d\mathbf{T}}{ds}| k = |0| = 0 The curvature of a straight line is 0, which confirms that a straight line has no curvature or deviation from its straight path.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Vector
The tangent vector is a fundamental concept when dealing with curves. It is a vector that points in the direction of the curve at a specific point. Imagine standing at a point on a curve. The tangent vector points in the direction you would walk if you were to move along the curve without turning.
  • For each point on a curve, there exists a tangent vector that indicates the curve's immediate direction at that point.
  • In mathematical terms, for a curve described by the parametric equations \(x(t), y(t)\), the tangent vector is often given as the derivative: \(\left(\frac{dx}{dt}, \frac{dy}{dt}\right)\).
  • The tangent vector is crucial in defining other properties of the curve, such as curvature.
For straight lines, the direction remains constant; hence, the tangent vector remains unchanged across points. This constancy simplifies many calculations when studying straight lines.
Derivative
The derivative is an essential tool in calculus. It measures how a function changes as its input changes. In the context of curves, the derivative of the unit tangent vector relates to curvature.
  • It helps determine the rate at which the tangent vector changes, which directly informs us about the curvature of the curve.
  • A constant tangent vector implies that its derivative is zero, indicating no curvature, as seen in straight lines.
When dealing with curves, derivatives can define acceleration, velocity, and, importantly, how sharply the curve changes direction. This measure of change provides insights into the curve's shape and behavior.
Arc Length
Arc length is the distance along the curved path of a line or a curve. Unlike straight lines, whose lengths are simply the distance between two points, curves require integration to find their arc length.
  • Calculating the arc length involves integrating the speed or the magnitude of the velocity vector over the interval of interest.
  • The arc length parameter, often denoted as \(s\), lets us express curves in terms that inherently comprehend the curve's own geometry.
Arc length is vital as it enables us to evaluate curvature. For any curve, using the arc length as a parameter allows us to understand its geometry seamlessly. This parameterization is key when examining properties like curvature.
Straight Line Geometry
Straight line geometry is arguably the simplest form of geometry. When examining lines, the properties are straightforward relative to curves. Here are the essential aspects of straight lines:
  • Straight lines have a constant tangent vector, implying no change in direction along their length.
  • Because their tangent vector doesn't change, the derivative of the tangent vector is zero.
  • This zero derivative corresponds to zero curvature. Hence, straight lines do not deviate or bend like curves do.
In geometrical terms, a straight line is the shortest distance between any two points in space or on a plane. This feature gives straight lines unique and easily computed properties, often making them a reference point for measuring curvature.

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Most popular questions from this chapter

Consider the curve. $$\mathbf{r}(t)=\langle a \cos t+b \sin t, c \cos t+d \sin t, e \cos t+f \sin t\rangle$$ where \(a, b, c, d, e,\) and \(f\) are real numbers. It can be shown that this curve lies in a plane. Find a general expression for a nonzero vector orthogonal to the plane containing the curve $$\mathbf{r}(t)=\langle a \cos t+b \sin t, c \cos t+d \sin t, e \cos t+f \sin t\rangle$$where \(\langle a, c, e\rangle \times\langle b, d, f\rangle \neq 0\)

Nonuniform straight-line motion Consider the motion of an object given by the position function $$\mathbf{r}(t)=f(t)\langle a, b, c\rangle+\left\langle x_{0}, y_{0}, z_{0}\right\rangle, \quad \text { for } t \geq 0$$ where \(a, b, c, x_{0}, y_{0},\) and \(z_{0}\) are constants, and \(f\) is a differentiable scalar function, for \(t \geq 0\) a. Explain why \(r\) describes motion along a line. b. Find the velocity function. In general, is the velocity constant in magnitude or direction along the path?

Time of flight, range, height Derive the formulas for time of flight, range, and maximum height in the case that an object is launched from the initial position \(\left\langle 0, y_{0}\right\rangle\) above the horizontal ground with initial velocity \(\left|\mathbf{v}_{0}\right|\langle\cos \alpha, \sin \alpha\rangle\).

Suppose the vector-valued function \(\mathbf{r}(t)=\langle f(t), g(t), h(t)\rangle\) is smooth on an interval containing the point \(t_{0}\) The line tangent to \(\mathbf{r}(t)\) at \(t=t_{0}\) is the line parallel to the tangent vector \(\mathbf{r}^{\prime}\left(t_{0}\right)\) that passes through \(\left(f\left(t_{0}\right), g\left(t_{0}\right), h\left(t_{0}\right)\right) .\) For each of the following functions, find an equation of the line tangent to the curve at \(t=t_{0} .\) Choose an orientation for the line that is the same as the direction of \(\mathbf{r}^{\prime}.\) $$\mathbf{r}(t)=\langle\sqrt{2 t+1}, \sin \pi t, 4\rangle ; t_{0}=4$$

Three-dimensional motion Consider the motion of the following objects. Assume the \(x\) -axis points east, the \(y\) -axis points north, the positive z-axis is vertical and opposite g. the ground is horizontal, and only the gravitational force acts on the object unless otherwise stated. a. Find the velocity and position vectors, for \(t \geq 0\). b. Make a sketch of the trajectory. c. Determine the time of flight and range of the object. d. Determine the maximum height of the object. A golf ball is hit east down a fairway with an initial velocity of \(\langle 50,0,30\rangle \mathrm{m} / \mathrm{s} .\) A crosswind blowing to the south produces an acceleration of the ball of \(-0.8 \mathrm{m} / \mathrm{s}^{2}\).

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