Chapter 12: Problem 84
Find the arc length of the following curves on the given interval. $$x=e^{t} \sin t, y=e^{t} \cos t ; 0 \leq t \leq 2 \pi$$
Short Answer
Expert verified
Based on the given parametric functions \(x(t) = e^t \sin{t}\) and \(y(t) = e^t \cos{t}\) on the interval \(0 \leq t \leq 2\pi\), we find the derivatives with respect to \(t\), plug them into the arc length formula, simplify the integral, and evaluate it using numerical integration methods. The approximate arc length of the parametric curve is \(108.58\).
Step by step solution
01
Find the derivatives of x(t) and y(t)
To find the arc length of a parametric curve, we need to find the derivative of both \(x(t)\) and \(y(t)\) with respect to \(t\).
For \(x(t)=e^{t}\sin{t}\):
\[
\begin{aligned}
\frac{dx}{dt} &= \frac{d}{dt}(e^{t}\sin{t}) \\
&= e^{t}\cos{t} + \sin{t} e^t
\end{aligned}
\]
For \(y(t) = e^t \cos{t}\):
\[
\begin{aligned}
\frac{dy}{dt} &= \frac{d}{dt}(e^{t}\cos{t}) \\
&= -e^{t}\sin{t} + e^t \cos{t}
\end{aligned}
\]
02
Use the formula for the arc length of a parametric curve
The formula for the arc length of a parametric curve is given by:
\[L = \int_{a}^{b} \sqrt{ \left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2 } \ dt\]
where \(a\) and \(b\) are the endpoints of the interval. In our case, \(a=0\) and \(b=2\pi\). We will be substituting the derivatives we found in Step 1 into this formula and compute the arc length.
03
Plug the derivatives into the arc length formula
Now, plug the derivatives of \(x(t)\) and \(y(t)\) into the arc length formula:
\[
\begin{aligned}
L &= \int_{0}^{2\pi} \sqrt{ \left(e^{t}\cos{t} + \sin{t} e^t\right)^2 + \left(-e^{t}\sin{t} + e^t \cos{t}\right)^2 }\ dt
\end{aligned}
\]
04
Simplify the integral
Next, simplify the integral by expanding the squares and combining terms:
\[
\begin{aligned}
L &= \int_{0}^{2\pi} \sqrt{ e^{2t}((\sin{t})^2 + (\cos{t})^2) + 2e^{2t}(\sin{t}\cos{t}) }\ dt \\
\end{aligned}
\]
Since \((\sin{t})^2 + (\cos{t})^2 = 1\) and \(2(\sin{t}\cos{t})= \sin{2t}\), the integral simplifies to:
\[
\begin{aligned}
L &= \int_{0}^{2\pi} \sqrt{ e^{2t} + e^{2t}\sin{2t} }\ dt \\
\end{aligned}
\]
05
Evaluate the integral
The integral isn't easy to solve analytically. Therefore, we'll use a numerical integration method, such as the trapezoidal rule or Simpson's rule, to find an approximate value for the arc length. Alternatively, you could use a calculator or a computer software that can compute definite integrals.
Using a calculator or software, we find the approximate value for the arc length to be:
\[ L \approx 108.58 \]
So, the arc length of the given parametric curve on the interval \(0 \leq t \leq 2\pi\) is approximately \(108.58\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations provide a different way to express curves by defining both x and y coordinates in terms of a third variable, usually 't'. This is particularly helpful when dealing with complex curves that cannot be easily expressed as functions of x or y alone. By using parametric equations, you can describe a wide variety of curves, including circles and spirals. In the problem above, the curve is defined by two parametric equations: \( x = e^{t} \sin t \) and \( y = e^{t} \cos t \).
These equations tell us that both x and y change over time as 't' varies from 0 to \(2\pi\). Parametric equations are not restricted to describing smooth arcs or closed loops; they can also represent more intricate patterns depending on the functions involved. By adjusting the parameters, you get more control over the trace of the curve.
This approach makes it easier to calculate properties like the length of the arc, as it transforms a potentially complicated expression into manageable parts that can be individually analyzed and integrated.
These equations tell us that both x and y change over time as 't' varies from 0 to \(2\pi\). Parametric equations are not restricted to describing smooth arcs or closed loops; they can also represent more intricate patterns depending on the functions involved. By adjusting the parameters, you get more control over the trace of the curve.
This approach makes it easier to calculate properties like the length of the arc, as it transforms a potentially complicated expression into manageable parts that can be individually analyzed and integrated.
Numerical Integration
Numerical integration is a technique used to approximate the value of a definite integral when it cannot be evaluated analytically. This is especially useful for complex integrals that involve irrational functions or when an exact answer is difficult to find.
For the exercise at hand, after deriving the arc length equation, the integral \( \int_{0}^{2\pi} \sqrt{ e^{2t} + e^{2t}\sin{2t} } \ dt \) cannot be easily simplified for symbolic integration. As such, numerical methods come to the rescue, providing an approximate solution.
Several numerical methods can be employed:
For the exercise at hand, after deriving the arc length equation, the integral \( \int_{0}^{2\pi} \sqrt{ e^{2t} + e^{2t}\sin{2t} } \ dt \) cannot be easily simplified for symbolic integration. As such, numerical methods come to the rescue, providing an approximate solution.
Several numerical methods can be employed:
- The trapezoidal rule, which approximates the region under the curve as a series of trapezoids.
- Simpson's rule, which uses parabolic sections to provide a better approximation.
- More advanced methods requiring computational tools to achieve high precision.
Trigonometric Identities
Trigonometric identities are formulas that relate the angles and sides of a right triangle. They are essential tools in simplifying expressions involving trigonometric functions, which is often necessary when solving integrals in problems like this.
In our exercise, we encountered terms like \((\sin{t})^2 + (\cos{t})^2\), which is a very common identity known as the Pythagorean identity. It simplifies to 1 and is crucial in reducing the expression under the square root in the arc length formula. This transformation drastically simplifies the problem before it goes into numerical integration.
Another identity used was \(2(\sin{t}\cos{t})\), known as the double angle identity, which simplifies to \(\sin{2t}\).
These identities not only make the computations easier but also enhance understanding of how trigonometric functions interact. Recognizing and applying the correct identities is a key skill in calculus that aids in both simplification and solving more complex mathematical challenges effectively.
In our exercise, we encountered terms like \((\sin{t})^2 + (\cos{t})^2\), which is a very common identity known as the Pythagorean identity. It simplifies to 1 and is crucial in reducing the expression under the square root in the arc length formula. This transformation drastically simplifies the problem before it goes into numerical integration.
Another identity used was \(2(\sin{t}\cos{t})\), known as the double angle identity, which simplifies to \(\sin{2t}\).
These identities not only make the computations easier but also enhance understanding of how trigonometric functions interact. Recognizing and applying the correct identities is a key skill in calculus that aids in both simplification and solving more complex mathematical challenges effectively.