Chapter 8: Problem 86
A glimpse ahead to power series. Use the Ratio Test to determine the values of \(x \geq 0\) for which each series converges. $$\sum_{k=1}^{\infty} \frac{x^{2 k}}{k^{2}}$$
Short Answer
Expert verified
Answer: The given power series converges for \(0\leq x<1\).
Step by step solution
01
Write down the general term of the series
The general term of the series is given by:
$$a_k = \frac{x^{2 k}}{k^{2}}$$
02
Write down the (k+1)-th term of the series
Substitute \(k+1\) in place of \(k\) to find the (k+1)-th term:
$$a_{k+1} = \frac{x^{2 (k+1)}}{(k+1)^2} = \frac{x^{2k+2}}{(k+1)^2}$$
03
Find the ratio of consecutive terms
Now, we will find the ratio \(\frac{a_{k+1}}{a_k}\):
$$\frac{a_{k+1}}{a_k} = \frac{\frac{x^{2k+2}}{(k+1)^2}}{\frac{x^{2k}}{k^2}}$$
04
Simplify the ratio
Simplify the fraction by dividing the terms:
$$\frac{a_{k+1}}{a_k} = \frac{x^{2k+2}}{(k+1)^2} \cdot \frac{k^2}{x^{2k}} =\frac{x^2}{\left(1+\frac{1}{k}\right)^2}$$
05
Apply the Ratio Test
The Ratio Test states that given a series \(\sum_{k=1}^{\infty} a_k\) , it will converge if
$$\lim_{k \to \infty} \frac{a_{k+1}}{a_k} < 1$$
Apply the limit to our simplified ratio:
$$\lim_{k \to \infty} \frac{x^2}{\left(1+\frac{1}{k}\right)^2} = x^2$$
06
Determine the range of x for convergence
The series will converge if \(x^2 < 1\). This implies that \(-1 < x < 1\). But we are asked to find the values of x for which the series converges for \(x\geq0\). Therefore, the given series converges for \(0\leq x<1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ratio Test
When attempting to determine if a series converges, the Ratio Test is a useful tool. It involves taking the limit of the ratio of consecutive terms in an infinite series. Specifically, for a series \( \sum_{k=1}^{\infty} a_k \), you calculate \( L = \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \). If \( L < 1 \) the series converges, if \( L > 1 \) it diverges, and if \( L = 1 \) the test is inconclusive.
This test is particularly effective for power series and can be useful for determining their radius of convergence. Practically, you need to find a way to simplify \( \frac{a_{k+1}}{a_k} \) before computing the limit, as was done in the provided exercise.
This test is particularly effective for power series and can be useful for determining their radius of convergence. Practically, you need to find a way to simplify \( \frac{a_{k+1}}{a_k} \) before computing the limit, as was done in the provided exercise.
Series Convergence
Series convergence is a fundamental concept in calculus, particularly when dealing with infinite series. A series is said to converge if the sum of its infinite terms approaches a finite value. Conversely, if the sum grows without bound or oscillates without approaching a particular value, then the series is said to diverge.
Understanding convergence is essential for many areas of mathematical analysis and applications, as it ensures that a given series can meaningfully contribute to a mathematical model or solution. The Ratio Test, along with other tests like the Root Test and the Integral Test, is employed to determine if a series converges or diverges.
Understanding convergence is essential for many areas of mathematical analysis and applications, as it ensures that a given series can meaningfully contribute to a mathematical model or solution. The Ratio Test, along with other tests like the Root Test and the Integral Test, is employed to determine if a series converges or diverges.
Power Series
A power series is an infinite series of the form \( \sum_{k=0}^{\infty} c_k (x-a)^k \), where \( c_k \) are coefficients, \( x \) is the variable, and \( a \) is the center of the series. Power series are used to represent functions as infinite polynomials and have applications in various fields such as physics, engineering, and economics.
The convergence of a power series depends on the value of \( x \). There exists an interval, known as the interval of convergence, within which the series converges to a function. The Ratio Test is especially helpful for determining this interval, as in the exercise where it was used to find the values of \( x \) for which the power series converges.
The convergence of a power series depends on the value of \( x \). There exists an interval, known as the interval of convergence, within which the series converges to a function. The Ratio Test is especially helpful for determining this interval, as in the exercise where it was used to find the values of \( x \) for which the power series converges.
Limits in Calculus
Limits are a core part of calculus and are essential in defining many concepts, including the convergence of series. A limit describes the value that a function or sequence 'approaches' as the input or index approaches some value. Limits can be finite or infinite and can be applied in different scenarios such as when assessing the behavior of a function near a point or as the independent variable grows without bound.
In the context of series convergence, limits allow us to assess what happens to the ratio of consecutive terms as the index becomes very large, which is crucial to the Ratio Test. Properly calculating limits is fundamental for understanding the behavior of functions and series in mathematics.
In the context of series convergence, limits allow us to assess what happens to the ratio of consecutive terms as the index becomes very large, which is crucial to the Ratio Test. Properly calculating limits is fundamental for understanding the behavior of functions and series in mathematics.