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A glimpse ahead to power series. Use the Ratio Test to determine the values of \(x \geq 0\) for which each series converges. $$\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}$$

Short Answer

Expert verified
Answer: The series converges for \(0\leq x < 1\).

Step by step solution

01

Write down the general term of the series

The given power series is \(\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}\). We start by writing down the general term of this series, which is given by \(a_k = \frac{x^k}{k^2}\).
02

Write down the ratio of consecutive terms

Following the Ratio Test, we need to find the ratio of consecutive terms, which is given by \(\frac{a_{k+1}}{a_k}\). Using the general term in step 1, we have: $$\frac{a_{k+1}}{a_k} = \frac{x^{k+1}/(k+1)^2}{x^k/k^2}.$$
03

Simplify the ratio

Now, we will simplify the ratio obtained in step 2: .$$ \frac{x^{k+1}/(k+1)^2}{x^k/k^2} = \frac{x^{k+1}k^2}{x^kk^2} = \frac{x}{\left(\frac{k+1}{k}\right)^2}.$$
04

Apply the Ratio Test

According to the Ratio Test, we need to find the limit of the ratio as \(k\) approaches infinity: $$\lim_{k\to\infty} \frac{x}{\left(\frac{k+1}{k}\right)^2}.$$ We can simplify the limit as follows: $$\lim_{k\to\infty} \frac{x}{\left(1+\frac{1}{k}\right)^2} = x\lim_{k\to\infty} \frac{1}{\left(1+\frac{1}{k}\right)^2} = x.$$ As \(k \to \infty\), the limit becomes \(x\).
05

Determine the conditions for convergence

For the series to converge, the limit must be less than 1. Therefore, we need to find the values of \(x\) that satisfy the condition: $$x<1.$$ Since we're asked to find the values of \(x \geq 0\) for which the series converges, the interval for convergence is \(0\leq x < 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Series
A power series is an infinite series of the form \( \sum_{k=0}^{\infty} a_k x^k \) where \( a_k \) are coefficients and \( x \) is a variable. In the given exercise, the series is \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \), where the term \( a_k \) is specified as \( \frac{1}{k^2} \). Each term of a power series involves raising \( x \) to successive powers, thus making it an expansion similar to a polynomial but with potentially infinite terms.
Power series play a critical role in calculus and analysis since they can represent functions incompletely or approximately. For example, functions like \( e^x \), \( \sin x \), and \( \cos x \) can be expressed as power series. The behavior of a power series changes depending on the values of \( x \), especially concerning its convergence, which specifies the input values for which the series gives a finite result.
Convergence of Series
The convergence of a series is a key concept determining whether the sum of an infinite sequence reaches a finite value. Specifically for power series, convergence depends on the value of \( x \). To test convergence, one common method is the Ratio Test.
The Ratio Test considers the ratio of successive terms in the series. When considering \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \), the Ratio Test simplifies the ratio \( \frac{a_{k+1}}{a_k} \), resulting in \( \lim_{k\to\infty} \frac{x}{\left(\frac{k+1}{k}\right)^2} \).
For the series to converge, this limit must be less than 1, meaning \( x < 1 \). Since \( x \geq 0 \) is specified, the interval of convergence for this series will be \( 0 \leq x < 1 \). Convergence is crucial in understanding which input values allow the series to sum to a finite quantity, thus revealing its practical applicability.
Calculus
In calculus, infinite series like power series are instrumental in approximating complex functions and facilitating the solution of differential equations. Calculus provides the necessary tools and tests, such as the Ratio Test, to analyze and predict the behavior of these series.
Such analysis involves limits, derivatives, and integrals, revealing important characteristics of functions and their approximations. Through the application of calculus, we can determine convergence, which ensures that an infinite series yields meaningful results.
By using calculus, students can explore areas like Taylor and Maclaurin series, where functions are expressed in infinite sums with varied polynomial degrees. These series help approximate values with great precision, which is essential in both theoretical and applied mathematics, improving mathematical models' efficiency and accuracy.

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Most popular questions from this chapter

A fishery manager knows that her fish population naturally increases at a rate of \(1.5 \%\) per month, while 80 fish are harvested each month. Let \(F_{n}\) be the fish population after the \(n\) th month, where \(F_{0}=4000\) fish. a. Write out the first five terms of the sequence \(\left\\{F_{n}\right\\}\). b. Find a recurrence relation that generates the sequence \(\left\\{F_{n}\right\\}\). c. Does the fish population decrease or increase in the long run? d. Determine whether the fish population decreases or increases in the long run if the initial population is 5500 fish. e. Determine the initial fish population \(F_{0}\) below which the population decreases.

Consider the alternating series $$ \sum_{k=1}^{\infty}(-1)^{k+1} a_{k}, \text { where } a_{k}=\left\\{\begin{array}{cl} \frac{4}{k+1}, & \text { if } k \text { is odd } \\ \frac{2}{k}, & \text { if } k \text { is even } \end{array}\right. $$ a. Write out the first ten terms of the series, group them in pairs, and show that the even partial sums of the series form the (divergent) harmonic series. b. Show that \(\lim _{k \rightarrow \infty} a_{k}=0\) c. Explain why the series diverges even though the terms of the series approach zero.

Find a formula for the nth term of the sequence of partial sums \(\left\\{S_{n}\right\\} .\) Then evaluate lim \(S_{n}\) to obtain the value of the series or state that the series diverges.\(^{n \rightarrow \infty}\) $$\sum_{k=1}^{\infty}\left(\tan ^{-1}(k+1)-\tan ^{-1} k\right)$$

After many nights of observation, you notice that if you oversleep one night, you tend to undersleep the following night, and vice versa. This pattern of compensation is described by the relationship $$x_{n+1}=\frac{1}{2}\left(x_{n}+x_{n-1}\right), \quad \text { for } n=1,2,3, \ldots.$$ where \(x_{n}\) is the number of hours of sleep you get on the \(n\) th night and \(x_{0}=7\) and \(x_{1}=6\) are the number of hours of sleep on the first two nights, respectively. a. Write out the first six terms of the sequence \(\left\\{x_{n}\right\\}\) and confirm that the terms alternately increase and decrease. b. Show that the explicit formula $$x_{n}=\frac{19}{3}+\frac{2}{3}\left(-\frac{1}{2}\right)^{n}, \text { for } n \geq 0.$$ generates the terms of the sequence in part (a). c. What is the limit of the sequence?

Evaluate the limit of the following sequences or state that the limit does not exist. $$a_{n}=\frac{75^{n-1}}{99^{n}}+\frac{5^{n} \sin n}{8^{n}}$$

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