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A glimpse ahead to power series. Use the Ratio Test to determine the values of \(x \geq 0\) for which each series converges. $$\sum_{i=1}^{\infty} \frac{x^{k}}{k !}$$

Short Answer

Expert verified
Answer: The series converges for all \(x \geq 0\).

Step by step solution

01

Identify the terms of the series

The series is given by: $$\sum_{k=1}^{\infty} \frac{x^{k}}{k !}$$ The terms of the series are: $$a_k = \frac{x^{k}}{k !}$$
02

Apply the Ratio Test

We will calculate the limit of the ratio of consecutive terms as \(k \to \infty\): $$\lim_{k \to \infty} \frac{a_{k+1}}{a_k} = \lim_{k \to \infty} \frac{\frac{x^{k+1}}{(k+1) !}}{\frac{x^{k}}{k !}}$$
03

Simplify the expression

To simplify the expression, we perform the following operations: $$\lim_{k \to \infty} \frac{(k!)x^{k+1}}{(k+1)!x^k} = \lim_{k \to \infty} \frac{x}{k+1}$$
04

Determine the limit

We can see that the limit is: $$\lim_{k \to \infty} \frac{x}{k+1} = 0$$
05

Convergence interval based on the Ratio Test

Since the limit is 0, which is less than 1, the series converges for all non-negative values of \(x\), i.e., \(x\geq 0\). The series converges for all \(x \geq 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Series
Understanding the concept of a power series is essential for exploring functions in calculus. It represents a function as an infinite sum of terms that are powers of a variable, usually denoted by 'x'. These terms are multiplied by coefficients that can be constants or depend on the index of the term. The general form of a power series is \[\sum_{n=0}^{fty} c_n(x-a)^n\] where \(c_n\) are the coefficients, \(x\) is the variable, \(a\) is the center of the series, and \(n\) indicates the nth term.

Series Convergence
A critical aspect of working with series is determining whether they converge or diverge; that is, if the sum of their infinite terms approaches a finite number (convergence) or not (divergence). The Ratio Test is a common method for determining a series' behavior. This test involves taking the limit of the ratio of consecutive terms (as seen with \(\frac{a_{k+1}}{a_k}\). If the limit is less than 1, the series is said to converge. Convergence is key to ensuring that the series sums up to a finite, well-defined value, making it possible to use power series for practical computations.

Factorial Notation in Series
Factorial notation is frequently encountered in series, particularly those involving exponential expressions and combinations. The factorial of a positive integer \(k\), denoted as \(k!\), is the product of all positive integers up to \(k\). For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\). In series, factorials provide a way to describe rapidly growing or shrinking sequence elements. They are particularly useful in power series expressions of exponential functions, such as the one described in our exercise \(\sum_{k=1}^{fty} \frac{x^{k}}{k !}\), which converges for all non-negative values of \(x\).

Limit of a Sequence
In mathematics, the concept of the limit of a sequence is a fundamental part of analysis, focusing on the behavior of sequences as they progress towards infinity. A sequence \(a_n\) has a limit \(L\) if, as \(n\) gets larger and larger, the sequence's terms get arbitrarily close to \(L\). In the context of series and the Ratio Test, we look for the limit of the ratio of consecutive terms to determine convergence. If this ratio tends towards zero, as with our exemplified series \(\lim_{k \to fty} \frac{x}{k+1} = 0\), the series is guaranteed to converge, which plays a crucial role in evaluating the behavior of power series across different values of \(x\).

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Most popular questions from this chapter

Pick two positive numbers \(a_{0}\) and \(b_{0}\) with \(a_{0}>b_{0},\) and write out the first few terms of the two sequences \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}:\) $$a_{n+1}=\frac{a_{n}+b_{n}}{2}, \quad b_{n+1}=\sqrt{a_{n} b_{n}}, \quad \text { for } n=0,1,2 \dots$$ (Recall that the arithmetic mean \(A=(p+q) / 2\) and the geometric mean \(G=\sqrt{p q}\) of two positive numbers \(p\) and \(q\) satisfy \(A \geq G.)\) a. Show that \(a_{n} > b_{n}\) for all \(n\). b. Show that \(\left\\{a_{n}\right\\}\) is a decreasing sequence and \(\left\\{b_{n}\right\\}\) is an increasing sequence. c. Conclude that \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}\) converge. d. Show that \(a_{n+1}-b_{n+1}<\left(a_{n}-b_{n}\right) / 2\) and conclude that \(\lim _{n \rightarrow \infty} a_{n}=\lim _{n \rightarrow \infty} b_{n} .\) The common value of these limits is called the arithmetic-geometric mean of \(a_{0}\) and \(b_{0},\) denoted \(\mathrm{AGM}\left(a_{0}, b_{0}\right)\). e. Estimate AGM(12,20). Estimate Gauss' constant \(1 / \mathrm{AGM}(1, \sqrt{2})\).

Consider the sequence \(\left\\{F_{n}\right\\}\) defined by $$F_{n}=\sum_{k=1}^{\infty} \frac{1}{k(k+n)},$$ for \(n=0,1,2, \ldots . .\) When \(n=0,\) the series is a \(p\) -series, and we have \(F_{0}=\pi^{2} / 6\) (Exercises 65 and 66 ). a. Explain why \(\left\\{F_{n}\right\\}\) is a decreasing sequence. b. Plot \(\left\\{F_{n}\right\\},\) for \(n=1,2, \ldots, 20\). c. Based on your experiments, make a conjecture about \(\lim _{n \rightarrow \infty} F_{n}\).

Consider the following sequences defined by a recurrence relation. Use a calculator, analytical methods, and/or graphing to make a conjecture about the limit of the sequence or state that the sequence diverges. $$a_{n+1}=\frac{1}{2} a_{n}+2 ; a_{0}=5$$

Suppose an alternating series \(\sum(-1)^{k} a_{k}\) with terms that are non increasing in magnitude, converges to \(S\) and the sum of the first \(n\) terms of the series is \(S_{n} .\) Suppose also that the difference between the magnitudes of consecutive terms decreases with \(k .\) It can be shown that for \(n \geq 1\) \(\left|S-\left(S_{n}+\frac{(-1)^{n+1} a_{n+1}}{2}\right)\right| \leq \frac{1}{2}\left|a_{n+1}-a_{n+2}\right|\) a. Interpret this inequality and explain why it is a better approximation to \(S\) than \(S_{n}\) b. For the following series, determine how many terms of the series are needed to approximate its exact value with an error less than \(10^{-6}\) using both \(S_{n}\) and the method explained in part (a). (i) \(\sum_{k=1}^{\infty} \frac{(-1)^{k}}{k}\) (ii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{k \ln k}\) (iii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{\sqrt{k}}\)

Use Exercise 89 to determine how many terms of each series are needed so that the partial sum is within \(10^{-6}\) of the value of the series (that is, to ensure \(\left|R_{n}\right|<10^{-6}\) ). Functions defined as series Suppose a function \(f\) is defined by the geometric series \(f(x)=\sum_{k=0}^{\infty}(-1)^{k} x^{k}\) a. Evaluate \(f(0), f(0.2), f(0.5), f(1),\) and \(f(1.5),\) if possible. b. What is the domain of \(f ?\)

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