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Is it true that if the terms of a series of positive terms decrease to zero, then the series converges? Explain using an example.

Short Answer

Expert verified
Answer: No, it is not always true. Although the terms of both the given examples decrease to zero, one series converges while the other diverges. It is essential to analyze the convergence or divergence using appropriate methods, such as the sum formula or integral test, to determine if a series converges or not.

Step by step solution

01

Understanding Convergence and Divergence

When we talk about a series converging or diverging, we are essentially referring to the sum of its terms. A series converges if the sum of its terms approaches a finite value, and it diverges if the sum of its terms goes to infinity or doesn't have a finite limit.
02

Example 1 - Converging Series

Let's consider a series of positive terms that decrease to zero: The geometric series \[\sum_{n=1}^{\infty} \frac{1}{2^n}\] To check whether this series converges or not, we calculate the sum of the infinite geometric series using the formula \[S = \frac{a_1}{1 - r}\] where \(a_1\) is the first term, and \(r\) is the common ratio. In this case, \(a_1 = \frac{1}{2}\) and \(r = \frac{1}{2}\). Therefore, \[S = \frac{\frac{1}{2}}{1 - \frac{1}{2}} = 1\] Since the sum is finite, this series converges.
03

Example 2 - Diverging Series

Let's consider another series of positive terms that decrease to zero: The harmonic series \[\sum_{n=1}^{\infty} \frac{1}{n}\] To check whether this series converges or not, we use the integral test, which states that the series converges if and only if the corresponding improper integral converges: \[\int_{1}^{\infty} \frac{1}{x} dx\] Calculate the integral: \[\int_{1}^{\infty} \frac{1}{x} dx = \lim_{b \to \infty} (\ln(x) \Big|_1^b)\] \[\lim_{b \to \infty} (\ln(b) - \ln(1)) = \lim_{b \to \infty} \ln(b) = \infty\] Since the improper integral diverges to infinity, the harmonic series also diverges.
04

Conclusion

Although the terms of both examples decrease to zero, one series converges while the other diverges. Therefore, it's not always true that if the terms of a series of positive terms decrease to zero, the series converges.

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Most popular questions from this chapter

In the following exercises, two sequences are given, one of which initially has smaller values, but eventually "overtakes" the other sequence. Find the sequence with the larger growth rate and the value of \(n\) at which it overtakes the other sequence. $$a_{n}=n^{10} \text { and } b_{n}=n^{9} \ln ^{3} n, n \geq 7$$

Use Theorem 8.6 to find the limit of the following sequences or state that they diverge. $$\left\\{\frac{e^{n / 10}}{2^{n}}\right\\}$$

Consider the following sequences defined by a recurrence relation. Use a calculator, analytical methods, and/or graphing to make a conjecture about the limit of the sequence or state that the sequence diverges. $$a_{n+1}=\frac{1}{2} a_{n}+2 ; a_{0}=5$$

Pick two positive numbers \(a_{0}\) and \(b_{0}\) with \(a_{0}>b_{0},\) and write out the first few terms of the two sequences \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}:\) $$a_{n+1}=\frac{a_{n}+b_{n}}{2}, \quad b_{n+1}=\sqrt{a_{n} b_{n}}, \quad \text { for } n=0,1,2 \dots$$ (Recall that the arithmetic mean \(A=(p+q) / 2\) and the geometric mean \(G=\sqrt{p q}\) of two positive numbers \(p\) and \(q\) satisfy \(A \geq G.)\) a. Show that \(a_{n} > b_{n}\) for all \(n\). b. Show that \(\left\\{a_{n}\right\\}\) is a decreasing sequence and \(\left\\{b_{n}\right\\}\) is an increasing sequence. c. Conclude that \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}\) converge. d. Show that \(a_{n+1}-b_{n+1}<\left(a_{n}-b_{n}\right) / 2\) and conclude that \(\lim _{n \rightarrow \infty} a_{n}=\lim _{n \rightarrow \infty} b_{n} .\) The common value of these limits is called the arithmetic-geometric mean of \(a_{0}\) and \(b_{0},\) denoted \(\mathrm{AGM}\left(a_{0}, b_{0}\right)\). e. Estimate AGM(12,20). Estimate Gauss' constant \(1 / \mathrm{AGM}(1, \sqrt{2})\).

Use Theorem 8.6 to find the limit of the following sequences or state that they diverge. $$\left\\{\frac{n^{10}}{\ln ^{20} n}\right\\}$$

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