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Find \(dy/dx\) for the following functions. $$y=x \cos x \sin x$$

Short Answer

Expert verified
Answer: The derivative is: $$\frac{dy}{dx} = -x\sin^2x + x\cos^2x + \cos x\sin x$$

Step by step solution

01

1. Find u'

Since u = x, the derivative with respect to x is: $$u'=1$$ Step 2: Differentiate v
02

2. Find v'

Since v = cos x, the derivative with respect to x is: $$ v'=-\sin x$$ Step 3: Differentiate w
03

3. Find w'

Since w = sin x, the derivative with respect to x is: $$w'=\cos x$$ Step 4: Apply the product rule
04

4. Apply product rule

Using the product rule and the derivatives we have found: $$ \frac{dy}{dx}= (x \cos x \sin x)'=x(-\sin x)(\cos x)+x(\cos x)(\sin x)+1(\cos x)(\sin x)$$ Step 5: Simplify the expression
05

5. Simplify expression

Combining terms to simplify the expression: $$ \frac{dy}{dx}=-x\sin^2 x + x\cos^2 x + \cos x\sin x$$ The final result is: $$ \frac{dy}{dx} = -x\sin^2 x + x\cos^2 x + \cos x\sin x $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Product Rule in Differentiation
The product rule is an essential concept in calculus, especially when differentiating functions that are the product of two or more factors. In simple terms, when you have a function y that is a product of two functions, say \( u(x) \) and \( v(x) \), the derivative of y with respect to x is given by the product rule: \( (uv)' = u'v + uv' \). This rule extends similarly if there are more than two factors involved.
  • First, differentiate each factor independently.
  • Next, sum the products of each differentiated term with the others.
Applying this rule requires careful attention to each part of the function, ensuring that derivatives are correctly computed and then multiplied accordingly. Always remember: take one function, differentiate it while keeping others constant, and switch. Then, sum all results to find the complete derivative.
Trigonometric Functions and Their Derivatives
Trigonometric functions, like sine and cosine, play a critical role in calculus. Their derivatives are fundamental for solving many types of problems. Here’s a quick reminder of the basics:
  • The derivative of \( \sin x \) is \( \cos x \).
  • The derivative of \( \cos x \) is \( -\sin x \).
Understanding these derivatives is crucial because they recur often in problems involving periodic phenomena or in cases where angles are manipulated.
In problems where trigonometric functions are combined with other functions (like \( y = x \cdot \cos x \cdot \sin x \) from the exercise), remembering these derivatives allows us to apply differentiation rules like the product rule effectively.
The Basics of Derivatives
Derivatives measure how a function changes as its input changes. They are a fundamental concept in calculus, representing the slope of the tangent line to the curve of a function at any point. When finding derivatives, especially of complex expressions, it’s essential to:
  • Identify which rules of differentiation apply (product rule, chain rule, etc.).
  • Carefully compute limits where necessary.
  • Simplify expressions to make them easier to interpret and analyze.
In the given exercise, the function \( y = x \cos x \sin x \) involves a product of three terms, and using the product rule and trigonometric identities can simplify the process of finding its derivative. Thus, derivatives allow you to understand the rate of change in systems modeled by mathematical equations. This understanding is key in both theoretical and applied sciences.

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Most popular questions from this chapter

A trough in the shape of a half cylinder has length \(5 \mathrm{m}\) and radius \(1 \mathrm{m}\). The trough is full of water when a valve is opened, and water flows out of the bottom of the trough at a rate of \(1.5 \mathrm{m}^{3} / \mathrm{hr}\) (see figure). (Hint: The area of a sector of a circle of a radius \(r\) subtended by an angle \(\theta\) is \(r^{2} \theta / 2 .\) ) a. How fast is the water level changing when the water level is \(0.5 \mathrm{m}\) from the bottom of the trough? b. What is the rate of change of the surface area of the water when the water is \(0.5 \mathrm{m}\) deep?

Quotient Rule for the second derivative Assuming the first and second derivatives of \(f\) and \(g\) exist at \(x,\) find a formula for \(\frac{d^{2}}{d x^{2}}\left(\frac{f(x)}{g(x)}\right)\)

Calculate the derivative of the following functions (i) using the fact that \(b^{x}=e^{x \ln b}\) and (ii) by using logarithmic differentiation. Verify that both answers are the same. $$y=\left(x^{2}+1\right)^{x}$$

\(F=f / g\) be the quotient of two functions that are differentiable at \(x\) a. Use the definition of \(F^{\prime}\) to show that $$ \frac{d}{d x}\left(\frac{f(x)}{g(x)}\right)=\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x+h)}{h g(x+h) g(x)} $$ b. Now add \(-f(x) g(x)+f(x) g(x)\) (which equals 0 ) to the numerator in the preceding limit to obtain $$\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x)+f(x) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}$$ Use this limit to obtain the Quotient Rule. c. Explain why \(F^{\prime}=(f / g)^{\prime}\) exists, whenever \(g(x) \neq 0\)

Prove the following identities and give the values of \(x\) for which they are true. $$\tan \left(2 \tan ^{-1} x\right)=\frac{2 x}{1-x^{2}}$$

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