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Use the General Power Rule where appropriate to find the derivative of the following functions. $$s(t)=\cos 2^{t}$$

Short Answer

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Question: Find the derivative of the function s(t) = cos(2^t) with respect to t. Answer: The derivative of the function s(t) = cos(2^t) with respect to t is s'(t) = -sin(2^t) * (2^t * ln(2)).

Step by step solution

01

Identify the inner function

The inner function is the function inside the cosine, which is 2^t.
02

Find the derivative of the inner function

The inner function is g(t) = 2^t. We can find its derivative g'(t) using the exponential function rule (d(e^u)/dt = e^u*(du/dt)): $$g'(t) = (2^t) \cdot \ln{2}$$
03

Apply the chain rule

The chain rule states that if we have a composite function, the derivative of the composite function is equal to the derivative of the outer function times the derivative of the inner function. In this case, our outer function is f(u) = cos(u) and the inner function is g(t) = 2^t, so s(t) = f(g(t)). Let's find the derivative of the outer function: $$f'(u) = -\sin(u)$$ Now we can use the chain rule to find s'(t): $$s'(t) = f'(g(t)) \cdot g'(t) = -\sin(2^t) \cdot (2^t \cdot \ln{2})$$
04

Write the final answer

The derivative of the function s(t) = cos(2^t) with respect to t is: $$s'(t) = -\sin(2^t) \cdot (2^t \cdot \ln{2})$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

General Power Rule
The General Power Rule is a fundamental concept in calculus used to differentiate functions of the form \((u(x))^n\). It extends the basic power rule, which is only applicable to simple power functions like \(x^n\). Here, \(u(x)\) represents any differentiable function, and \(n\) is a real number that dictates the power to which \(u(x)\) is raised.

When using the General Power Rule, follow these steps:
  • Differentiate the outer function as usual, treating the inner function \(u(x)\) as a constant. This means applying the standard power rule: bring down the exponent and reduce it by one.
  • Multiply by the derivative of the inner function \(u'(x)\).
Putting it into a formula, if you have a function \(y = (u(x))^n\), then the derivative is given by the rule:
\[ \frac{dy}{dx} = n \cdot (u(x))^{n-1} \cdot u'(x)\]

In our example, the General Power Rule wasn't directly used, but it is fundamental in understanding how to handle expressions where an inner function might be raised to a power.
Chain Rule
The Chain Rule is one of the cornerstones of differential calculus. It is particularly useful when dealing with composite functions, where you have a function nested inside another function, often making them seemingly complex to differentiate at first glance.

The principle behind the Chain Rule is simple: differentiate the outer function first, leaving the inner function as it is, and then multiply it by the derivative of the inner function. The Chain Rule is expressed in mathematical terms as:
\[ \frac{dy}{dx} = f'(g(x)) \cdot g'(x)\]
Here, \(f\) is the outer function, \(g(x)\) is the inner function, and \(g'(x)\) is the derivative of the inner function.

In the context of our example, we used the Chain Rule to differentiate \(s(t) = \cos(2^t)\). The outer function is \(f(u) = \cos(u)\) and the inner function is \(g(t) = 2^t\). After identifying these, we take the derivative of the outer function, which is \(-\sin(u)\), and multiply it by the derivative of the inner function, \((2^t \ln(2))\).

This step-by-step approach solidifies how the Chain Rule effectively breaks down complex derivatives into more manageable pieces.
Exponential Functions
Exponential functions are an intriguing type of function where a constant base is raised to a variable exponent, usually taking the form \(a^x\), where \(a\) is a positive constant and \(x\) is the variable. These functions are essential in calculus due to their constant growth rate properties, which have significant applications in fields such as finance, biology, and physics.

The derivative of an exponential function is closely tied to the natural logarithm. For a general exponential function \(g(x) = a^x\), the derivative is:
\[ g'(x) = a^x \cdot \ln(a)\]
This formula reflects the rate of change of an exponential function being proportional to its current value—a unique property of exponentials.

In the example problem, identifying and differentiating the inner function \(2^t\) was a crucial step. Here, using the rule for exponential functions, we found that the derivative was \((2^t \cdot \ln(2))\), showing how exponential functions smoothly integrate with other calculus rules like the Chain Rule for determining derivatives of composite functions.

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Most popular questions from this chapter

Tangent lines and exponentials. Assume \(b\) is given with \(b>0\) and \(b \neq 1 .\) Find the \(y\) -coordinate of the point on the curve \(y=b^{x}\) at which the tangent line passes through the origin. (Source: The College Mathematics Journal, 28, Mar 1997).

A 500-liter (L) tank is filled with pure water. At time \(t=0,\) a salt solution begins flowing into the tank at a rate of \(5 \mathrm{L} / \mathrm{min} .\) At the same time, the (fully mixed) solution flows out of the tank at a rate of \(5.5 \mathrm{L} / \mathrm{min}\). The mass of salt in grams in the tank at any time \(t \geq 0\) is given by $$M(t)=250(1000-t)\left(1-10^{-30}(1000-t)^{10}\right)$$ and the volume of solution in the tank (in liters) is given by \(V(t)=500-0.5 t\). a. Graph the mass function and verify that \(M(0)=0\). b. Graph the volume function and verify that the tank is empty when \(t=1000\) min. c. The concentration of the salt solution in the tank (in \(\mathrm{g} / \mathrm{L}\) ) is given by \(C(t)=M(t) / V(t) .\) Graph the concentration function and comment on its properties. Specifically, what are \(C(0)\) and \(\lim _{\theta \rightarrow 000^{-}} C(t) ?\) \(t \rightarrow 1\) d. Find the rate of change of the mass \(M^{\prime}(t),\) for \(0 \leq t \leq 1000\). e. Find the rate of change of the concentration \(C^{\prime}(t),\) for \(0 \leq t \leq 1000\). f. For what times is the concentration of the solution increasing? Decreasing?

Product Rule for three functions Assume that \(f, g,\) and \(h\) are differentiable at \(x\) a. Use the Product Rule (twice) to find a formula for \(\frac{d}{d x}(f(x) g(x) h(x))\) b. Use the formula in (a) to find \(\frac{d}{d x}\left(e^{2 x}(x-1)(x+3)\right)\)

General logarithmic and exponential derivatives Compute the following derivatives. Use logarithmic differentiation where appropriate. $$\frac{d}{d x}(2 x)^{2 x}$$.

Identifying functions from an equation. The following equations implicitly define one or more functions. a. Find \(\frac{d y}{d x}\) using implicit differentiation. b. Solve the given equation for \(y\) to identify the implicitly defined functions \(y=f_{1}(x), y=f_{2}(x), \ldots\) c. Use the functions found in part (b) to graph the given equation. $$x^{4}=2\left(x^{2}-y^{2}\right) \text { (eight curve) }$$

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