Chapter 2: Problem 39
Use the following definitions.
Assume fexists for all \(x\) near a with \(x>\) a. We say the limit of \(f(x)\) as
\(x\) approaches a from the right of a is \(L\) and write \(\lim _{x \rightarrow
a^{+}} f(x)=L,\) if for any \(\varepsilon>0\) there exists \(\delta>0\) such that
$$|f(x)-L|<\varepsilon \quad \text { whenever } \quad 0< x-a<\delta$$
Assume fexists for all \(x\) near a with \(x < \) a. We say the limit of \(f(x)\) as
\(x\) approaches a from the left of a is \(L\) and write \(\lim _{x \rightarrow
a^{-}} f(x)=L,\) if for any \(\varepsilon > 0 \) there exists \(\delta > 0\) such
that
$$|f(x)-L| < \varepsilon \quad \text { whenever } \quad 0< a-x <\delta$$
Why is the last inequality in the definition of \(\lim _{x \rightarrow a}
f(x)=L,\) namely, \(0<|x-a|<\delta,\) replaced with \(0
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.