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Determine the following limits. $$\lim _{x \rightarrow 0^{+}}(-10 \cot x)$$

Short Answer

Expert verified
Answer: As x approaches 0 from the positive side, the function approaches negative infinity. \(\lim_{x \rightarrow 0^{+}}(-10 \cot x) = -\infty\)

Step by step solution

01

Examine the cotangent function

The cotangent function \(\cot x\) is the reciprocal of the tangent function, that is, $$\cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x}$$ Notice that \(\cot x\) is undefined when \(\sin x = 0\), which occurs at integer multiples of \(\pi\).
02

Rewrite the limit in terms of sine and cosine

Before proceeding with the limit, let's express the original function in terms of sine and cosine: $$\lim_{x \rightarrow 0^{+}}(-10 \cot x) = \lim_{x \rightarrow 0^{+}}\left(-10\frac{\cos x}{\sin x}\right)$$
03

Evaluate the one-sided limit

The one-sided limit means we are approaching \(x=0\) from the positive side, which means \(x\) is a very small positive number. Since \(\lim_{x \rightarrow 0^{+}} \cos x = 1\) and \(\lim_{x \rightarrow 0^{+}} \sin x = 0^{+}\), we have: $$\lim_{x \rightarrow 0^{+}}\left(-10\frac{\cos x}{\sin x}\right) = -10\frac{1}{0^{+}}$$
04

Determine the behavior of the limit

When dividing by a very small positive number, the expression becomes very large. Since the division is multiplied by -10, the final limit is: $$\lim_{x \rightarrow 0^{+}}(-10 \cot x) = -\infty$$ meaning that when \(x\) approaches 0 from the positive side, this function approaches negative infinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cotangent Function
Understanding the cotangent function is crucial when dealing with trigonometric limits. Essentially, the cotangent is one of the six fundamental trigonometric functions and is denoted as \( \text{cot}(x) \). It represents the reciprocal of the tangent function, which implies that \( \text{cot}(x) = \frac{1}{\text{tan}(x)} = \frac{\text{cos}(x)}{\text{sin}(x)} \).

Since cotangent is defined as the ratio of the adjacent side to the opposite side in a right-angled triangle, it is undefined whenever the sine function equals zero, as division by zero is not allowed. The sine function equals zero at integer multiples of \( \text{pi} \), which are precisely the points where the cotangent function exhibits discontinuities or jumps from positive to negative infinity or vice versa. This behavior profoundly affects the limits as \( x \) approaches any of those points.
Limits of Trigonometric Functions
When dealing with limits of trigonometric functions, we're essentially trying to find the value that a trigonometric function approaches as the input gets infinitely close to a certain number. These limits can often be resolved by transforming the original function into a more manageable form using trigonometric identities.

For example, a limit involving the cotangent function might be transformed into a limit involving sine and cosine, as they are more fundamental and their behavior near certain critical points, like zero, is well understood. It's important to note that these transformations serve not only to simplify the expressions but also to help us avoid indeterminate forms that can complicate limit evaluation.
Indeterminate Forms
An indeterminate form is an expression that does not have a specific limit or value in its current form. In calculus, common indeterminate forms include \( \frac{0}{0} \), \( \frac{\text{infinity}}{\text{infinity}} \), 0 times infinity, \( \text{infinity} - \text{infinity} \), \( 0^0 \), \( \text{infinity}^0 \), and \( 1^\text{infinity} \).

These forms typically arise in the context of limits when the terms in a function approach values that make the function’s limit uncertain. To resolve these indeterminate forms and find the actual limit, we can apply L'Hôpital's rule, algebraic manipulation, or trigonometric identities. In the given exercise, we encounter the form \( \frac{1}{0^{+}} \), which suggests an infinite limit rather than a specific finite value.
Infinite Limits
Infinite limits occur when the value of a function grows without bound as the input approaches a particular point. It is to say, the function either goes to positive infinity (\( +\text{infinity} \)) or negative infinity (\( -\text{infinity} \)), depending on the direction of the growth.

In the given exercise, the negative sign in front of the cotangent function indicates that as the value of the cotangent grows larger, the entire expression moves in the negative direction, hence approaching negative infinity. Understanding infinite limits is essential, especially in one-sided limits where we're only concerned with the behavior of the function as it approaches from either the left or the right side, not both. This distinction is crucial in sketching accurate graphs of functions and in understanding their behavior near points where they are not defined.

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Most popular questions from this chapter

Evaluate the following limits or state that they do not exist. $$\lim _{x \rightarrow 0^{+}} \frac{x}{\ln x}$$

Suppose \(g(x)=f(1-x),\) for all \(x, \lim _{x \rightarrow 1^{+}} f(x)=4,\) and \(\lim _{x \rightarrow 1^{-}} f(x)=6 .\) Find \(\lim _{x \rightarrow 0^{+}} g(x)\) and \(\lim _{x \rightarrow 0^{-}} g(x)\).

a. Create a table of values of \(\tan (3 / x)\) for \(x=12 / \pi, 12 /(3 \pi), 12 /(5 \pi) \ldots . .12 /(11 \pi) .\) Describe the general pattern in the values you observe. b. Use a graphing utility to graph \(y=\tan (3 / x) .\) Why do graphing utilities have difficulty plotting the graph near \(x=0 ?\) c. What do you conclude about \(\lim _{x \rightarrow 0} \tan (3 / x) ?\)

We write \(\lim _{x \rightarrow \infty} f(x)=\infty\) if for any positive number \(M\) there is a corresponding \(N>0\) such that $$f(x)>M \quad \text { whenever } \quad x>N$$ Use this definition to prove the following statements. $$\lim _{x \rightarrow \infty} \frac{x}{100}=\infty$$

Determine whether the following statements are true and give an explanation or counterexample. Assume \(a\) and \(L\) are finite numbers. a. If \(\lim _{x \rightarrow a} f(x)=L,\) then \(f(a)=L\).0 b. If \(\lim _{x \rightarrow a^{-}} f(x)=L,\) then \(\lim _{x \rightarrow a^{+}} f(x)=L\). c. If \(\lim _{x \rightarrow a} f(x)=L\) and \(\lim _{x \rightarrow a} g(x)=L,\) then \(f(a)=g(a)\). d. The limit \(\lim _{x \rightarrow a} \frac{f(x)}{g(x)}\) does not exist if \(g(a)=0\). e. If \(\lim _{x \rightarrow 1^{+}} \sqrt{f(x)}=\sqrt{\lim _{x \rightarrow 1^{+}} f(x)}\), it follows that \(\lim _{x \rightarrow 1} \sqrt{f(x)}=\sqrt{\lim _{x \rightarrow 1} f(x)}\).

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