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Explain how spherical coordinates are used to describe a point in \(\mathbb{R}^{3}\).

Short Answer

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Question: Explain how spherical coordinates are used to describe a point in 3-dimensional space, and provide an example with a point's Cartesian coordinates given as (1, 1, 1). Answer: Spherical coordinates represent a point in 3-dimensional space using three parameters: radius (r), inclination angle (θ), and azimuthal angle (φ). The radius is the distance between a point and the origin, the inclination angle is the angle between the line connecting the center and the point and the positive z-axis, and the azimuthal angle is the angle between the projections of the line connecting the center and the point to the xy-plane and the positive x-axis. For example, consider a point P with Cartesian coordinates (1, 1, 1). To find its spherical coordinates (r, θ, φ), we can use the transformation formulas: r = √(1² + 1² + 1²) = √3 θ = arccos(1/√3) = π/4 φ = arctan(1/1) = π/4 Thus, the spherical coordinates of point P are (r, θ, φ) = (√3, π/4, π/4).

Step by step solution

01

Definition of Spherical Coordinates

Spherical coordinates are an alternative coordinate system representing a point in 3-dimensional space using three parameters: radius (\(r\)), inclination angle (\(\theta\)), and azimuthal angle (\(\phi\)). The radius is the distance between a point and the origin (i.e., the length of the vector from the origin to the point), the inclination angle is the angle between the line connecting the center and the point and the positive z-axis, and the azimuthal angle is the angle between the projections of the line connecting the center and the point to the xy-plane and the positive x-axis.
02

Relationship between Cartesian and Spherical Coordinates

To transform a point from spherical to Cartesian coordinates, we can use the following formulas: $$ x = r\sin\theta\cos\phi $$ $$y = r\sin\theta\sin\phi $$ $$z = r\cos\theta $$
03

Transformation from Cartesian to Spherical Coordinates

To transform a point from Cartesian coordinates to spherical coordinates, you can use the following formulas: $$r = \sqrt{x^2 + y^2 + z^2} $$ $$\theta = \arccos \frac{z}{\sqrt{x^2 + y^2 + z^2}} $$ $$\phi = \arctan \frac{y}{x} $$ Notice that sometimes the spherical coordinates system formally uses a range of \([0, 2\pi]\) for the inclination angle \(\theta\) and a range of \([0, \pi]\) for the azimuthal angle \(\phi\), while in other cases the conventions are reversed.
04

Example of Spherical Coordinates

Let's assume we have a point P with Cartesian coordinates \((x, y, z) = (1, 1, 1)\). To find its spherical coordinates \((r, \theta, \phi)\), we can use the transformation formulas: $$r = \sqrt{1^2 + 1^2 + 1^2} = \sqrt{3}$$ $$\theta = \arccos \left(\frac{1}{\sqrt{3}}\right) = \arccos \left(\frac{\sqrt{2}}{2} \right) = \frac{\pi}{4} $$ $$\phi = \arctan\left(\frac{1}{1}\right) = \arctan(1) = \frac{\pi}{4} $$ So the spherical coordinates of the point P are \((r, \theta, \phi) = \left(\sqrt{3}, \frac{\pi}{4}, \frac{\pi}{4}\right)\).

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Most popular questions from this chapter

Explain why or why not ,Determine whether the following statements are true and give an explanation or counterexample. a. A thin plate of constant density that is symmetric about the \(x\) -axis has a center of mass with an \(x\) -coordinate of zero. b. A thin plate of constant density that is symmetric about both the \(x\) -axis and the \(y\) -axis has its center of mass at the origin. c. The center of mass of a thin plate must lie on the plate. d. The center of mass of a connected solid region (all in one piece) must lie within the region.

Use integration to show that the circles \(r=2 a \cos \theta\) and \(r=2 a \sin \theta\) have the same area, which is \(\pi a^{2}\)

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