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What position vector is equal to the vector from (3,5,-2) to (0,-6,3)\(?\)

Short Answer

Expert verified
Answer: The position vector is (-3, -11, 5).

Step by step solution

01

Identify Coordinates of Point A and Point B

Given two points, let's call them A and B. The coordinates of Point A are (3, 5, -2) and the coordinates of Point B are (0, -6, 3).
02

Subtract Coordinates of Points A and B

To find the position vector from Point A to Point B, we subtract the coordinates of Point A from the coordinates of Point B: (x_B - x_A, y_B - y_A, z_B - z_A)
03

Calculate the Position Vector

Using the subtraction from Step 2, we have: (x_B - x_A, y_B - y_A, z_B - z_A) = (0 - 3, -6 - 5, 3 - (-2)). Now let's perform the subtraction to get the position vector: (-3, -11, 5)
04

Write the Final Answer

The position vector equal to the vector from (3,5,-2) to (0,-6,3) is (-3, -11, 5).

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Most popular questions from this chapter

Suppose the vector-valued function \(\mathbf{r}(t)=\langle f(t), g(t), h(t)\rangle\) is smooth on an interval containing the point \(t_{0} .\) The line tangent to \(\mathbf{r}(t)\) at \(t=t_{0}\) is the line parallel to the tangent vector \(\mathbf{r}^{\prime}\left(t_{0}\right)\) that passes through \(\left(f\left(t_{0}\right), g\left(t_{0}\right), h\left(t_{0}\right)\right) .\) For each of the following functions, find an equation of the line tangent to the curve at \(t=t_{0} .\) Choose an orientation for the line that is the same as the direction of \(\mathbf{r}^{\prime}\). $$\mathbf{r}(t)=\left\langle 3 t-1,7 t+2, t^{2}\right\rangle ; t_{0}=1$$

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Diagonals of a parallelogram Consider the parallelogram with adjacent sides \(\mathbf{u}\) and \(\mathbf{v}\) a. Show that the diagonals of the parallelogram are \(\mathbf{u}+\mathbf{v}\) and \(\mathbf{u}-\mathbf{v}\) b. Prove that the diagonals have the same length if and only if \(\mathbf{u} \cdot \mathbf{v}=0\) c. Show that the sum of the squares of the lengths of the diagonals equals the sum of the squares of the lengths of the sides.

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