Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Express the dot product of \(\mathbf{u}\) and \(\mathbf{v}\) in terms of their magnitudes and the angle between them.

Short Answer

Expert verified
Answer: The dot product of two vectors, u and v, is equal to the product of their magnitudes and the cosine of the angle between them, expressed as u · v = ||u|| * ||v|| * cos(θ).

Step by step solution

01

Recall the Dot Product Definition

The dot product of two vectors \(\mathbf{u}\) and \(\mathbf{v}\), denoted by \(\mathbf{u} \cdot \mathbf{v}\), is defined as the product of the magnitudes of the vectors and the cosine of the angle between them: \(\mathbf{u} \cdot \mathbf{v} = ||\mathbf{u}|| \, ||\mathbf{v}|| \cos{\theta}\) Where \(||\mathbf{u}||\) is the magnitude of vector \(\mathbf{u}\), \(||\mathbf{v}||\) is the magnitude of vector \(\mathbf{v}\), and \(\theta\) is the angle between the two vectors.
02

Solution

To express the dot product of \(\mathbf{u}\) and \(\mathbf{v}\) in terms of their magnitudes and the angle between them, we use the dot product definition from Step 1: \(\mathbf{u} \cdot \mathbf{v} = ||\mathbf{u}|| \, ||\mathbf{v}|| \cos{\theta}\) The dot product of vectors \(\mathbf{u}\) and \(\mathbf{v}\) is equal to the product of their magnitudes and the cosine of the angle between them.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free