Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A focal chord of a conic section is a line through a focus joining two points of the curve. The latus rectum is the focal chord perpendicular to the major axis of the conic. Prove the following properties. The length of the latus rectum of a hyperbola centered at the origin is \(2 b^{2} / a=2 b \sqrt{e^{2}-1}\)

Short Answer

Expert verified
Answer: The length of the latus rectum of a hyperbola is given by \(l = 2\sqrt{a^2(e^2 - 1)}\).

Step by step solution

01

Write the standard equation of a hyperbola centered at the origin.

The standard equation of a hyperbola centered at the origin and opens horizontally is given by \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
02

Identify the relationship between the semi-major axis \(a\), focus \(f\), and eccentricity \(e\) of a hyperbola.

For a hyperbola, the relationship between the semi-major axis, focus, and eccentricity is \(f = a * e\). The focus lies on the x-axis, so the coordinates of the two foci are (\(\pm f, 0\)).
03

Derive the relationship between \(a\), \(b\), and \(e\) for a hyperbola.

Using the foci and the vertices of a hyperbola, we can derive the relationship between \(a, b, e\) as follows: \(e = \frac{f}{a} = \frac{\sqrt{a^2 + b^2}}{a}\), then \(b^2 = a^2(e^2 - 1)\).
04

Find the coordinates of the vertices located on the latus rectum.

The latus rectum is the focal chord perpendicular to the major axis of the hyperbola. We are considering a horizontal hyperbola, so the latus rectum passes through both foci and is parallel to the y-axis. As the foci lie on the x-axis, their coordinates are (\(\pm f, 0\)). The latus rectum shares both foci, implying the end points of the latus rectum and vertices of the hyperbola are on the same horizontal with y-coordinate 0. Let's denote the coordinates of these two points to be (\(f + b\), 0) and (\(f - b\), 0).
05

Compute the length of the latus rectum.

The length of the latus rectum is the distance between the two end points found in Step 4. By applying the distance formula, we have \(l = |(f+b) - (f-b)| = 2b\). Now, we need to express \(b\) in terms of \(a\) and \(e\). From Step 3, we have \(b^2 = a^2(e^2 - 1)\). Taking the square root of both sides, we get \(b = \sqrt{a^2(e^2 - 1)}\). So, the length of the latus rectum is: \(l = 2b = 2\sqrt{a^2(e^2 - 1)}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Latus Rectum
The latus rectum is a vital concept when it comes to understanding hyperbolas and other conic sections. Particularly, the latus rectum is the chord that passes through the focus of a conic section and is perpendicular to its major axis. It plays an important role in the geometry of conics.

For a hyperbola, the latus rectum is related specifically to the foci and the semi-major axis, defining how the curve extends around its center in a specific measure. Since a hyperbola has two foci, there are two segments of the latus rectum, each associated with one of its foci. To determine the length of the latus rectum of a hyperbola, it's crucial to evaluate it in terms of the hyperbola's parameters: the semi-major axis \(a\), semi-minor axis \(b\), and eccentricity \(e\).

In the case of a hyperbola centered at the origin, we use the equation:
  • \(b^2 = a^2(e^2 - 1)\)
  • Length of latus rectum \(= 2b\)
By substituting \(b\) into the equation \(l = 2\sqrt{a^2(e^2 - 1)}\), we finalize the length of the latus rectum, bringing in clear geometric information about the hyperbola's width at the focus.
Conic Sections
Conic sections are the curves obtained by intersecting a cone with a plane. These include circles, ellipses, parabolas, and hyperbolas. They hold a critical place in both geometry and algebra, where each type of conic has distinct properties and equations.

Here's a quick overview of conic sections:
  • Circles: Defined by the equation \(x^2 + y^2 = r^2\), where \(r\) is the radius.
  • Ellipses: Have the general equation \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a\) and \(b\) are the semi-major and semi-minor axes, respectively.
  • Parabolas: Characterized by the equation \(y^2 = 4ax\), where \(a\) determines the distance of the vertex from the focus.
  • Hyperbolas: Defined by the equation \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\), with \(a\) and \(b\) determining the axes of the hyperbola.
Each conic section is determined by its eccentricity, which describes how "stretched" out the conic is. Despite their differences, they are all mathematically interrelated and have fascinating properties that provide solutions to various geometric problems.
Eccentricity
Eccentricity is a crucial parameter that distinguishes conic sections from each other. It effectively measures how much a conic section deviates from being circular. Each type of conic section is defined by a different range of eccentricity values, which alters its geometry significantly.

Here's a breakdown of eccentricity in each conic:
  • Circle: Eccentricity \(e = 0\) since it is perfectly symmetrical in all directions.
  • Ellipse: \(0 < e < 1\). The closer \(e\) is to zero, the more circular the ellipse is.
  • Parabola: Eccentricity \(e = 1\) signifying its opening shape.
  • Hyperbola: \(e > 1\), which means the two branches can stretch infinitely, apart from each other.
In hyperbolas specifically, eccentricity not only dictates the openness of the branches but also connects with the semi-major and semi-minor axes through the relation \(e = \frac{\sqrt{a^2 + b^2}}{a}\). This formula assists in calculating the semi-minor axis or eccentricity as required, providing significant insights into the structure of the hyperbola.
Semi-major Axis
In any conic section, the semi-major axis is one of the most significant geometric features. Specifically for hyperbolas, it represents half of the longest diameter that passes through the center. This term is most commonly used in ellipses, but it functions similarly in hyperbolas.

The semi-major axis \(a\) relates to various other components of the hyperbola:
  • It is used in the standard equation of a hyperbola, as in \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) for horizontally oriented hyperbolas.
  • It helps in determining the distance between the two vertices, with 2\(a\) being the full span of the major axis.
  • The semi-major axis also connects to the eccentricity, allowing derivations of other key formulas within a hyperbola, linking to the focal distance by \(f = ae\).
By understanding the role of the semi-major axis, one can grasp many geometric and algebraic properties of hyperbolas, making it a cornerstone in the study of conic sections.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A simplified model assumes that the orbits of Earth and Mars are circular with radii of 2 and \(3,\) respectively, and that Earth completes one orbit in one year while Mars takes two years. When \(t=0,\) Earth is at (2,0) and Mars is at (3,0) both orbit the Sun (at (0,0) ) in the counterclockwise direction. The position of Mars relative to Earth is given by the parametric equations \(x=(3-4 \cos \pi t) \cos \pi t+2, \quad y=(3-4 \cos \pi t) \sin \pi t\) a. Graph the parametric equations, for \(0 \leq t \leq 2\) b. Letting \(r=(3-4 \cos \pi t),\) explain why the path of Mars relative to Earth is a limaçon (Exercise 89).

Consider the parametric equations $$ x=a \cos t+b \sin t, \quad y=c \cos t+d \sin t $$ where \(a, b, c,\) and \(d\) are real numbers. a. Show that (apart from a set of special cases) the equations describe an ellipse of the form \(A x^{2}+B x y+C y^{2}=K,\) where \(A, B, C,\) and \(K\) are constants. b. Show that (apart from a set of special cases), the equations describe an ellipse with its axes aligned with the \(x\) - and \(y\) -axes provided \(a b+c d=0\) c. Show that the equations describe a circle provided \(a b+c d=0\) and \(c^{2}+d^{2}=a^{2}+b^{2} \neq 0\)

Equations of the form \(r=a \sin m \theta\) or \(r=a \cos m \theta,\) where \(a\) is a real number and \(m\) is a positive integer, have graphs known as roses (see Example 6 ). Graph the following roses. \(r=4 \cos 3 \theta\)

Circles in general $$r^{2}-2 r(a \cos \theta+b \sin \theta)=R^{2}-a^{2}-b^{2}$$ describes a circle of radius \(R\) centered at \((a, b)\).

Find an equation of the following hyperbolas, assuming the center is at the origin. Sketch a graph labeling the vertices, foci, and asymptotes. Use a graphing utility to check your work. A hyperbola with vertices (±4,0) and foci (±6,0)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free