Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find an equation of the line tangent to the following curves at the given point. $$x^{2}=-6 y ;(-6,-6)$$

Short Answer

Expert verified
Answer: The equation of the tangent line is $$y = 2x$$.

Step by step solution

01

Rewrite the given equation as a function of x and y

The given equation is already a function of x and y, so we can proceed to the next step without any changes.
02

Rewrite the equation as a function of y

We need to rewrite the equation in the form of $$y = f(x)$$. By solving for y, we have: $$y = -\frac{1}{6}x^{2}$$
03

Find the derivative dy/dx

To find the tangent line's slope at a given point, we need to calculate the derivative of y with respect to x: $$\frac{dy}{dx} = \frac{d}{dx} (-\frac{1}{6}x^{2})$$ Use the power rule: $$\frac{dy}{dx} = -\frac{1}{3}x$$
04

Evaluate the derivative at the given point

Now, plug in the x-coordinate of the given point (-6) into the derivative to find the tangent line's slope at the point: $$m = -\frac{1}{3}(-6) = 2$$
05

Use the point-slope form to find the equation of the tangent line

The point-slope form of a line's equation is given by: $$y - y_{1} = m (x - x_{1})$$ Plug in the coordinates of the given point and the slope calculated in step 4: $$y - (-6) = 2 (x - (-6))$$ Simplify: $$y + 6 = 2(x + 6)$$ Now, distribute and rearrange the equation to get the final equation of the tangent line: $$y = 2x + 6 - 6$$ $$y = 2x$$ The equation of the tangent line to the curve $$x^2 = -6y$$ at the point $$(-6, -6)$$ is $$y = 2x$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Circles in general $$r^{2}-2 r(a \cos \theta+b \sin \theta)=R^{2}-a^{2}-b^{2}$$ describes a circle of radius \(R\) centered at \((a, b)\).

Find parametric equations (not unique) of the following ellipses (see Exercises \(75-76\) ). Graph the ellipse and find a description in terms of \(x\) and \(y.\) An ellipse centered at the origin with major axis of length 6 on the \(x\) -axis and minor axis of length 3 on the \(y\) -axis, generated counterclockwise

Consider the polar curve \(r=2 \sec \theta\). a. Graph the curve on the intervals \((\pi / 2,3 \pi / 2),(3 \pi / 2,5 \pi / 2)\) and \((5 \pi / 2,7 \pi / 2) .\) In each case, state the direction in which the curve is generated as \(\theta\) increases. b. Show that on any interval \((n \pi / 2,(n+2) \pi / 2),\) where \(n\) is an odd integer, the graph is the vertical line \(x=2\).

Water flows in a shallow semicircular channel with inner and outer radii of \(1 \mathrm{m}\) and \(2 \mathrm{m}\) (see figure). At a point \(P(r, \theta)\) in the channel, the flow is in the tangential direction (counterclockwise along circles), and it depends only on \(r,\) the distance from the center of the semicircles. a. Express the region formed by the channel as a set in polar coordinates. b. Express the inflow and outflow regions of the channel as sets in polar coordinates. c. Suppose the tangential velocity of the water in \(\mathrm{m} / \mathrm{s}\) is given by \(v(r)=10 r,\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.5, \frac{\pi}{4}\right)\) or \(\left(1.2, \frac{3 \pi}{4}\right) ?\) Explain. d. Suppose the tangential velocity of the water is given by \(v(r)=\frac{20}{r},\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.8, \frac{\pi}{6}\right)\) or \(\left(1.3, \frac{2 \pi}{3}\right) ?\) Explain. e. The total amount of water that flows through the channel (across a cross section of the channel \(\theta=\theta_{0}\) ) is proportional to \(\int_{1}^{2} v(r) d r .\) Is the total flow through the channel greater for the flow in part (c) or (d)?

Find an equation of the following hyperbolas, assuming the center is at the origin. Sketch a graph labeling the vertices, foci, and asymptotes. Use a graphing utility to check your work. A hyperbola with vertices (±2,0) and asymptotes \(y=\pm 3 x / 2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free