Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Convert the following equations to polar coordinates. \((x-1)^{2}+y^{2}=1\)

Short Answer

Expert verified
Question: Convert the Cartesian equation \((x-1)^{2}+y^{2}=1\) into polar coordinates. Answer: The Cartesian equation \((x-1)^{2}+y^{2}=1\) is equivalent to the polar equation \(r(r-2\cos\theta) = 0\).

Step by step solution

01

Substitute polar coordinate conversion formulas

Replace \(x\) with \(r\cos\theta\) and \(y\) with \(r\sin\theta\) in the given equation: \([(r\cos\theta)-1]^{2}+(r\sin\theta)^2 = 1\)
02

Expand and Simplify

First, we expand the square terms: \((r^2\cos^2\theta - 2r\cos\theta + 1) + r^2\sin^2\theta = 1\) Now, combine the \(r^2\cos^2\theta\) and \(r^2\sin^2\theta\) terms using the identity \(\cos^2\theta + \sin^2\theta = 1\): \(r^2(\cos^2\theta + \sin^2\theta) - 2r\cos\theta + 1 = 1\) And replace \(\cos^2\theta + \sin^2\theta\) with 1: \(r^2 - 2r\cos\theta + 1 = 1\)
03

Solve for Polar Equation

Subtract 1 from both sides of the equation: \(r^2 - 2r\cos\theta = 0\) Factor out \(r\) from the equation: \(r(r - 2\cos\theta) = 0\) Now, we have the polar equation: \(r(r - 2\cos\theta) = 0\) The given Cartesian equation \((x-1)^{2}+y^{2}=1\) is equivalent to the polar equation \(r(r-2\cos\theta) = 0\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Identities
Trigonometric identities are essential tools when working with different coordinate systems, especially in polar coordinates conversion. One such identity used frequently is the Pythagorean identity. This identity states that for any angle \(\theta\), the sum of the squares of sine and cosine is equal to one: \[ \cos^2\theta + \sin^2\theta = 1 \]This identity helps simplify expressions involving sine and cosine. When converting Cartesian equations to polar form, as shown in the step-by-step solution, we used this identity to combine terms like \(r^2\cos^2\theta\) and \(r^2\sin^2\theta\) to simplify them to \(r^2\). Understanding and applying these identities can make equation simplification much more manageable, especially when dealing with trigonometric functions.
Coordinate Systems
Coordinate systems provide a framework for locating points in a plane. The two most common systems are Cartesian (rectangular) and Polar.
  • The Cartesian system uses \(x\) and \(y\) coordinates based on horizontal and vertical lines.
  • The Polar system, however, uses \(r\) (the radius or distance from the origin) and \(\theta\) (the angle from the positive x-axis).
When converting from Cartesian to Polar coordinates, we substitute \(x = r \cos \theta\) and \(y = r \sin \theta\). This conversion allows us to express points in terms of distance and angle, which can be particularly useful in scenarios involving rotations or circular paths.In our exercise, converting the Cartesian equation \((x-1)^2 + y^2 = 1\) into polar form illustrates how Polar coordinates transform the way equations are represented, emphasizing the relationship between distance and angle.
Algebraic Manipulation
Algebraic manipulation involves rearranging and simplifying expressions to solve equations effectively. In the context of converting equations to polar coordinates, it involves expanding terms, using identities, and reducing equations to simpler forms.For the equation \([(r\cos\theta)-1]^{2}+(r\sin\theta)^2 = 1\), we start by expanding the squared terms. This type of manipulation is crucial for isolating terms, making it easier to apply trigonometric identities. The goal in algebraic manipulation is to rewrite equations in a form where patterns or identities can be recognized and applied. Once simplified, the expression \(r^2 - 2r\cos\theta + 1 = 1\) was achieved by first expanding, then using the identity \(\cos^2\theta + \sin^2\theta = 1\). From this point, solving becomes more straightforward by factoring out common terms, leading us to the final polar equation.Algebraic manipulation is a powerful tool that often involves combining simplification strategies with known identities to yield clear and efficient solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that the polar equation of an ellipse or a hyperbola with one focus at the origin, major axis of length \(2 a\) on the \(x\) -axis, and eccentricity \(e\) is $$r=\frac{a\left(1-e^{2}\right)}{1+e \cos \theta}$$

An epitrochoid is the path of a point on a circle of radius \(b\) as it rolls on the outside of a circle of radius \(a\). It is described by the equations $$\begin{array}{l}x=(a+b) \cos t-c \cos \left(\frac{(a+b) t}{b}\right) \\\y=(a+b) \sin t-c \sin \left(\frac{(a+b) t}{b}\right)\end{array}$$ Use a graphing utility to explore the dependence of the curve on the parameters \(a, b,\) and \(c.\)

Graph the following spirals. Indicate the direction in which the spiral is generated as \(\theta\) increases, where \(\theta>0 .\) Let \(a=1\) and \(a=-1\). Hyperbolic spiral: \(r=a / \theta\)

A simplified model assumes that the orbits of Earth and Mars are circular with radii of 2 and \(3,\) respectively, and that Earth completes one orbit in one year while Mars takes two years. When \(t=0,\) Earth is at (2,0) and Mars is at (3,0) both orbit the Sun (at (0,0) ) in the counterclockwise direction. The position of Mars relative to Earth is given by the parametric equations \(x=(3-4 \cos \pi t) \cos \pi t+2, \quad y=(3-4 \cos \pi t) \sin \pi t\) a. Graph the parametric equations, for \(0 \leq t \leq 2\) b. Letting \(r=(3-4 \cos \pi t),\) explain why the path of Mars relative to Earth is a limaçon (Exercise 89).

Show that the equation \(r=a \cos \theta+b \sin \theta\) where \(a\) and \(b\) are real numbers, describes a circle. Find the center and radius of the circle.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free