Chapter 1: Problem 61
Right-triangle relationships Draw a right triangle to simplify the given expressions. Assume \(x>0.\) $$\sin \left(2 \cos ^{-1} x\right)(\text { Hint: Use } \sin 2 \theta=2 \sin \theta \cos \theta$$
Short Answer
Expert verified
Question: Simplify the expression \(\sin\left(2 \cos^{-1} x\right)\), assuming x is positive.
Answer: $$\sin\left(2 \cos ^{-1} x\right) = 2x\sqrt{1-x^2}$$
Step by step solution
01
Create the right triangle and assign values
Since we are given \(\cos^{-1} x\), we'll create a right triangle with an angle \(\theta\) such that \(\cos\theta = x\). Label the adjacent side to angle \(\theta\) as `A`, the opposite side as `B`, and the hypotenuse as `H`. We have:
- \(A = x\cdot H\)
- \(B = \sqrt{H^2 - A^2}\)
Notice that \(\cos\theta = \frac{A}{H}\), and \(\sin\theta = \frac{B}{H}\).
02
Find the value of \(\sin\left(2\cos^{-1} x\right)\) using the given hint
By using the trigonometric identity \(\sin(2\theta)=2\sin\theta\cos\theta\), we need to find expressions for \(\sin\theta\) and \(\cos\theta\). Since we already have \(\cos\theta=x\), we need to find out \(\sin\theta\). From step 1, we know that:
- \(\sin\theta = \frac{B}{H} = \frac{\sqrt{H^2 - A^2}}{H} = \frac{\sqrt{H^2 - (x\cdot H)^2}}{H} = \frac{\sqrt{H^2 - x^2\cdot H^2}}{H} = \frac{\sqrt{(1-x^2)H^2}}{H}\)
03
Substitute in the trigonometric identity
Now we have expressions for both \(\sin\theta\) and \(\cos\theta\), we can substitute these into the trigonometric identity:
\(\sin(2 \cos^{-1} x) = 2\sin\cos^{-1} x \cos\cos^{-1} x = 2 \cdot \frac{\sqrt{(1-x^2)H^2}}{H} \cdot x\)
04
Simplifying the expression
Now, we simplify the expression from step 3:
\(\sin(2 \cos^{-1} x) = \frac{2x\sqrt{(1-x^2)H^2}}{H}\)
Since we are asked to assume \(x > 0\) and \(H>0\), we can conclude that the final simplified expression for the given problem is:
$$\sin\left(2 \cos ^{-1} x\right) = 2x\sqrt{1-x^2}$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Right Triangle
A right triangle is a simple yet powerful geometric figure. It plays a crucial role in trigonometry, especially for simplifying expressions. A right triangle is characterized by having one angle equal to 90 degrees. The sides of a right triangle have specific roles: the longest side opposite the right angle is called the hypotenuse, while the other two sides are known as the legs.
To simplify trigonometric expressions using a right triangle, we often label the sides based on the trigonometric functions involved:
To simplify trigonometric expressions using a right triangle, we often label the sides based on the trigonometric functions involved:
- The adjacent side is the side closest to the angle in question, excluding the hypotenuse.
- The opposite side is across from the angle.
- The hypotenuse is always the longest side.
Inverse Trigonometric Functions
Inverse trigonometric functions are used to determine the angle that corresponds to a given trigonometric ratio. In this exercise, the function \( \cos^{-1} x \) (also known as arccosine) is utilized. This function yields an angle \( \theta \) whose cosine is \( x \).
The inverse cosine function is particularly useful when dealing with angles and triangles because it allows us to do the following:
The inverse cosine function is particularly useful when dealing with angles and triangles because it allows us to do the following:
- Translate a given trigonometric ratio back into an angle.
- Facilitate the construction of right triangles for simplification processes.
Trigonometric Simplification
Trigonometric simplification involves rewriting complex trigonometric expressions into simpler forms using known identities. This is particularly useful when dealing with expressions involving angles, functions, or inverse functions.
In our exercise, simplification enables the conversion of the expression \( \sin(2\cos^{-1} x) \) into a form that's easier to evaluate. We achieve this by:
In our exercise, simplification enables the conversion of the expression \( \sin(2\cos^{-1} x) \) into a form that's easier to evaluate. We achieve this by:
- Recognizing and using known identities, like \( \sin(2\theta) = 2 \sin \theta \cos \theta \), which are crucial for simplification.
- Substituting known values for \( \sin \theta \) and \( \cos \theta \) derived from the right triangle relationships.
- Reducing the expressions mathematically to express them in simplest terms: \( 2x\sqrt{1-x^2} \).