Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine whether the following sequences converge or diverge and describe whether they do so monotonically or by oscillation. Give the limit when the sequence converges. $$\left\\{(-0.7)^{n}\right\\}$$

Short Answer

Expert verified
If it converges, find the limit and describe if it converges monotonically or by oscillation. Answer: The sequence \((-0.7)^n\) converges with a limit of 0 and converges by oscillation.

Step by step solution

01

Identify the common ratio r and sequence type

The sequence is given by \((-0.7)^{n}\). We can see that it is a geometric sequence with the common ratio \(r=(-0.7)\). The sequence is alternating because it has a negative common ratio.
02

Determine if the sequence converges

A geometric sequence converges if the absolute value of the common ratio r is less than 1. In this case, \(|-0.7|=0.7 < 1\). Since the absolute value of r is less than 1, the sequence converges.
03

Find the limit of the sequence

As the sequence converges, we can find the limit L as \(n \to \infty\). For a converging geometric sequence, the limit is given by \(L = \lim_{n \to \infty} r^n\). In this case, we find the limit by taking \(\lim_{n \to \infty} (-0.7)^n\). Since \(|-0.7| < 1\), the limit must be 0.
04

Determine the type of convergence

Now, we need to determine if the sequence converges monotonically or by oscillation. Since the sequence has a negative common ratio, it oscillates between positive and negative values. Thus, the sequence converges by oscillation. To summarize the solution, 1. The sequence \((-0.7)^n\) converges. 2. The limit of the sequence is 0. 3. The sequence converges by oscillation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Sequence
Geometric sequences are sequences of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. This type of sequence is expressed in the form \( a, ar, ar^2, ar^3, \ldots \), where \( a \) is the initial term and \( r \) is the common ratio.

Key aspects of geometric sequences include:
  • If the absolute value of the common ratio \(|r| < 1\), the sequence converges.
  • If \(|r| \geq 1\), the sequence diverges.
For example, the sequence \((-0.7)^n\) is a geometric sequence with \( r = -0.7 \). Because the absolute value \( |r| = 0.7 < 1 \), this tells us immediately that the sequence converges.

Understanding geometric sequences help in predicting the behavior of series and can also be applied in fields such as finance, physics, and computer science.
Alternating Sequence
An alternating sequence is a sequence in which the signs of the terms alternate between positive and negative. In many cases, this alteration can be attributed to a negative common ratio. This is evident in our sequence, \((-0.7)^n\), where the negative common ratio \(-0.7\) causes the terms to switch signs with each iteration:
  • When \(n\) is even, \((-0.7)^n\) results in a positive term.
  • When \(n\) is odd, \((-0.7)^n\) results in a negative term.
Alternating sequences can either converge or diverge based on additional properties like the absolute value of the common ratio. When evaluating these sequences, it's essential to recognize that alternating signs alone do not determine convergence, as convergence is dependent on other factors such as whether the sequence is a geometric sequence and \(|r| < 1\).

Understanding alternating sequences is crucial in determining the behavior of terms within a sequence and further analyzing their convergence or divergence properties.
Limit of a Sequence
The limit of a sequence refers to the value that the terms of the sequence approach as the index \(n\) goes to infinity. For sequences where terms become infinitely large or small, finding the limit helps in identifying whether the sequence converges or diverges. The limit does not exist if the sequence diverges.

For a converging geometric sequence like \((-0.7)^n\), the limit can be determined by observing that as \(n\) becomes very large, \(|-0.7|^n\) becomes very small. This implies that the limit of the sequence at \(n \to \infty\) is 0, given the absolute value is less than one.

Key points about the limit of sequences include:
  • If the limit exists and is finite, the sequence converges.
  • If the limit does not exist or is infinite, the sequence diverges.
Understanding limits is essential in various branches of mathematics and other scientific disciplines, as it allows for precise descriptions of the behavior of functions and sequences.
Convergence by Oscillation
Convergence by oscillation occurs when the terms of a sequence converge to a certain value, but the terms oscillate between positive and negative values along the way. This type of convergence is often associated with sequences that have alternating signs, like our example \((-0.7)^n\).

Oscillatory convergence is different from monotone convergence where a sequence approaches its limit by settling into a consistent increasing or decreasing pattern without switching signs. In oscillatory convergence:
  • The sequence approaches the limit, but the path includes alternating terms.
  • The sequence \((-0.7)^n\) converges to 0, but because of the negative common ratio, it does so by oscillating between negative and positive values.
Recognizing when a sequence converges by oscillation aids in understanding diverse types of sequence behaviors and helps in calculating precise limits amid these oscillations. This concept has applications in oscillatory phenomena observed in physics and engineering.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a positive real number \(p,\) how do you interpret \(p^{p^{p \cdot *}},\) where the tower of exponents continues indefinitely? As it stands, the expression is ambiguous. The tower could be built from the top or from the bottom; that is, it could be evaluated by the recurrence relations \(a_{n+1}=p^{a_{n}}\) (building from the bottom) or \(a_{n+1}=a_{n}^{p}(\text { building from the top })\) where \(a_{0}=p\) in either case. The two recurrence relations have very different behaviors that depend on the value of \(p\). a. Use computations with various values of \(p > 0\) to find the values of \(p\) such that the sequence defined by (2) has a limit. Estimate the maximum value of \(p\) for which the sequence has a limit. b. Show that the sequence defined by (1) has a limit for certain values of \(p\). Make a table showing the approximate value of the tower for various values of \(p .\) Estimate the maximum value of \(p\) for which the sequence has a limit.

Consider the series \(\sum_{k=2}^{\infty} \frac{1}{k(\ln k)^{p}},\) where \(p\) is a real number. a. Use the Integral Test to determine the values of \(p\) for which this series converges. b. Does this series converge faster for \(p=2\) or \(p=3 ?\) Explain.

Find the limit of the sequence $$\left\\{a_{n}\right\\}_{n=2}^{\infty}=\left\\{\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right) \cdots\left(1-\frac{1}{n}\right)\right\\}.$$

Suppose an alternating series \(\sum(-1)^{k} a_{k}\) converges to \(S\) and the sum of the first \(n\) terms of the series is \(S_{n}\) Suppose also that the difference between the magnitudes of consecutive terms decreases with \(k\). It can be shown that for \(n \geq 1,\) $$\left|S-\left[S_{n}+\frac{(-1)^{n+1} a_{n+1}}{2}\right]\right| \leq \frac{1}{2}\left|a_{n+1}-a_{n+2}\right|$$ a. Interpret this inequality and explain why it gives a better approximation to \(S\) than simply using \(S_{n}\) to approximate \(S\). b. For the following series, determine how many terms of the series are needed to approximate its exact value with an error less than \(10^{-6}\) using both \(S_{n}\) and the method explained in part (a). (i) \(\sum_{k=1}^{\infty} \frac{(-1)^{k}}{k}\) (ii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{k \ln k}\) (iii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{\sqrt{k}}\)

A glimpse ahead to power series Use the Ratio Test to determine the values of \(x \geq 0\) for which each series converges. $$\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free