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Determine whether the following statements are true and give an explanation or counterexample. a. A direction field allows you to visualize the solution of a differential equation, but it does not give exact values of the solution at particular points. b. Euler's method is used to compute exact values of the solution of an initial value problem.

Short Answer

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Question: Determine whether the following statements are true or false, and provide either an explanation or counterexample for each statement. a) A direction field only allows us to visualize the solution of a differential equation without giving exact values of the solution. b) Euler's method can be used to compute exact values of the solution of an initial value problem. Answer: a) True. Direction fields provide an approximate graphical representation of the solution curves but do not give exact values of the solution. b) False. Euler's method is an approximate numerical method and not meant for computing exact values of the solution of an initial value problem.

Step by step solution

01

Statement a - Direction field's purpose

Direction fields, also known as slope fields, are used to visualize the behavior of the solutions to a differential equation by depicting the slopes of the tangent lines to the solution curves at individual points. They do not provide exact values of the solution but offer an approximate graphical representation of the solution curves. As a result, this statement is true.
02

Statement b - Euler's method for exact solution computation

Euler's method is a numerical approach used to estimate the value of the solution of an initial value problem at discrete points by approximating the differential equation with a series of tangent lines. Although Euler's method might provide a good approximation for the solution, it rarely gives exact values. Increasing the number of steps might decrease the error, but the method, by its nature, remains an approximation method. Therefore, this statement is false. To sum up, statement a is true whereas statement b is false. A direction field only allows us to visualize the solution of a differential equation without giving exact values of the solution. On the other hand, Euler's method is an approximate numerical method and not meant for computing exact values of the solution of an initial value problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direction Fields
Direction fields, also known as slope fields, provide a visual understanding of differential equations. Similar to a map, they plot the slope of solution curves over a specified region. This graphical representation helps you see how potential solutions to the differential equation might behave without solving the equation directly.

While direction fields are beneficial for visualizing the general path of solutions, they don’t offer precise numerical values at specific points. Instead, they show how the slope of the solution curve changes based on the differential equation. This can give you an intuitive grasp of where solutions are heading.

The main benefits of using direction fields include:
  • Visualizing the overall behavior of solutions.
  • Identifying equilibrium solutions.
  • Understanding the nature of stability in systems.
It's important to remember that while direction fields are excellent for gaining insights, they are not meant for obtaining exact answers.
Euler's Method
Euler's Method is a simple and effective numerical technique used in solving initial value problems for differential equations. It helps estimate the values of solutions, providing an iterative approach to approximate the solution curve.

The basis of Euler's Method is to start from an initial point and move stepwise along the curve, using the slope provided by the differential equation to find the next point. This creates a polygonal path that approximates the true solution curve.

Key aspects of Euler's Method include:
  • It uses a step-by-step approach.
  • Estimates are made using tangent slopes from the differential equation.
  • It is an approximate method, not exact.
By increasing the number of steps or decreasing the step size, the approximation can be refined, however, it is still not an exact representation of the solution.
Initial Value Problem
An initial value problem (IVP) is a type of differential equation with specified starting conditions. Essentially, it means solving a differential equation that not only satisfies the equation but also touches a known point at a specific value.

Let's break down the concept of an IVP:
  • The differential equation describes how a quantity changes.
  • The initial condition specifies the state of this quantity at a particular starting point.
  • The solution is a function that fits both the equation and the initial condition.
Solving an IVP involves finding a function that follows the rule given by the differential equation, all while passing through that initial condition point. This ensures that any solution found is the right one corresponding to the given start of your problem.

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Most popular questions from this chapter

A special class of first-order linear equations have the form \(a(t) y^{\prime}(t)+a^{\prime}(t) y(t)=f(t),\) where \(a\) and \(f\) are given functions of \(t.\) Notice that the left side of this equation can be written as the derivative of a product, so the equation has the form $$a(t) y^{\prime}(t)+a^{\prime}(t) y(t)=\frac{d}{d t}(a(t) y(t))=f(t)$$ Therefore, the equation can be solved by integrating both sides with respect to \(t.\) Use this idea to solve the following initial value problems. $$t y^{\prime}(t)+y=1+t, y(1)=4$$

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Consider the differential equation \(y^{\prime}(t)=\frac{y(y+1)}{t(t+2)}\) and carry out the following analysis. a. Show that the general solution of the equation can be written in the form $$ y(t)=\frac{\sqrt{t}}{C \sqrt{t+2}-\sqrt{t}} $$ b. Now consider the initial value problem \(y(1)=A,\) where \(A\) is a real number. Show that the solution of the initial value problem is $$ y(t)=\frac{\sqrt{t}}{\left(\frac{1+A}{\sqrt{3} A}\right) \sqrt{t+2}-\sqrt{t}} $$ c. Find and graph the solution that satisfies the initial condition \(y(1)=1\) d. Describe the behavior of the solution in part (c) as \(t\) increases. e. Find and graph the solution that satisfies the initial condition \(y(1)=2\) f. Describe the behavior of the solution in part (e) as \(t\) increases. g. In the cases in which the solution is bounded for \(t>0,\) what is the value of \(\lim _{t \rightarrow \infty} y(t) ?\)

U.S. population projections According to the U.S. Census Bureau, the nation's population (to the nearest million) was 281 million in 2000 and 310 million in \(2010 .\) The Bureau also projects a 2050 population of 439 million. To construct a logistic model, both the growth rate and the carrying capacity must be estimated. There are several ways to estimate these parameters. Here is one approach: a. Assume that \(t=0\) corresponds to 2000 and that the population growth is exponential for the first ten years; that is, between 2000 and \(2010,\) the population is given by \(P(t)=P(0) e^{n}\) Estimate the growth rate \(r\) using this assumption. b. Write the solution of the logistic equation with the value of \(r\) found in part (a). Use the projected value \(P(50)=439 \mathrm{mil}\) lion to find a value of the carrying capacity \(K\) c. According to the logistic model determined in parts (a) and (b), when will the U.S. population reach \(95 \%\) of its carrying capacity? d. Estimations of this kind must be made and interpreted carefully. Suppose the projected population for 2050 is 450 million rather than 439 million. What is the value of the carrying capacity in this case? e. Repeat part (d) assuming the projected population for 2050 is 430 million rather than 439 million. What is the value of the carrying capacity in this case? f. Comment on the sensitivity of the carrying capacity to the 40-year population projection.

The following models were discussed in Section 1 and reappear in later sections of this chapter. In each case carry out the indicated analysis using direction fields. The delivery of a drug (such as an antibiotic) through an intravenous line may be modeled by the differential equation \(m^{\prime}(t)+k m(t)=I,\) where \(m(t)\) is the mass of the drug in the blood at time \(t \geq 0, k\) is a constant that describes the rate at which the drug is absorbed, and \(I\) is the infusion rate. Let \(I=10 \mathrm{mg} / \mathrm{hr}\) and \(k=0.05 \mathrm{hr}^{-1}\). a. Draw the direction field, for \(0 \leq t \leq 100,0 \leq y \leq 600\). b. What is the equilibrium solution? c. For what initial values \(m(0)=A\) are solutions increasing? Decreasing?

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