Chapter 8: Problem 25
For the following initial value problems, compute the first two approximations \(u_{1}\) and \(u_{2}\) given by Euler's method using the given time step. $$y^{\prime}(t)=2 y, y(0)=2 ; \Delta t=0.5$$
Short Answer
Expert verified
Answer: The first two approximations are \(u_1 = 4\) and \(u_2 = 8\).
Step by step solution
01
Identify the given problem and initial condition
We have the initial value problem \(y^{\prime}(t) = 2y\) with the initial condition \(y(0) = 2\). The time step given is \(\Delta t = 0.5\).
02
Identify the function f(t, y)
The function to be used in Euler's method formula is found on the right side of the differential equation. In this case, it's \(f(t, y) = 2y\).
03
Calculate the first approximation \(u_1\)
Using Euler's method formula, let's calculate the first approximation \(u_1\). Here, \(t_0 = 0\), \(u_0 = y(0) = 2\), \(\Delta t = 0.5\). The formula is as follows:
$$u_{n+1} = u_n + \Delta t \cdot f(t_n, u_n)$$
Replace the variables for the first approximation:
$$u_1 = u_0 + \Delta t \cdot f(t_0, u_0) = 2 + 0.5 \cdot 2 \cdot 2$$
Compute the result:
$$u_1 = 2 + 2 = 4$$
04
Calculate the second approximation \(u_2\)
Now, let's calculate the second approximation \(u_2\). Here, \(t_1 = 0.5, u_1 = 4, \Delta t= 0.5\). Use the same formula from the previous step:
$$u_{n+1} = u_n + \Delta t \cdot f(t_n, u_n)$$
Replace the variables for the second approximation:
$$u_2 = u_1 + \Delta t \cdot f(t_1, u_1) = 4 + 0.5 \cdot 2 \cdot 4$$
Compute the result:
$$u_2 = 4 + 4 = 8$$
05
Conclusion
The first two approximations using Euler's method for the initial value problem \(y^{\prime}(t)=2y, y(0)=2 ; \Delta t=0.5\) are:
$$u_1 = 4$$
$$u_2 = 8$$
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Initial Value Problem
In mathematics, an initial value problem lays the foundation for needing solutions to differential equations. Essentially, it involves determining a function from its derivative (or rate of change) and an initial condition.
This initial condition typically specifies the value of the function at a given point, often called the starting point. For example, in this exercise, the initial condition is given as \( y(0) = 2 \).
This means that at time \( t = 0 \), the value of the function \( y \) is 2. Solving an initial value problem requires not just finding a family of solutions to the differential equation, but also picking out the one solution that fits the given initial condition.
This initial condition typically specifies the value of the function at a given point, often called the starting point. For example, in this exercise, the initial condition is given as \( y(0) = 2 \).
This means that at time \( t = 0 \), the value of the function \( y \) is 2. Solving an initial value problem requires not just finding a family of solutions to the differential equation, but also picking out the one solution that fits the given initial condition.
- Initial Value: Specifies where the function starts, such as \( y(0) = 2 \).
- Objective: Find the specific function solution that satisfies both the differential equation and initial condition.
Differential Equations
Differential equations play a crucial role in modeling situations where quantities change over time. They involve equations that relate a function to its derivatives, expressing how the function changes. In this particular problem, the differential equation is \( y^{\prime}(t) = 2y \).
This equation suggests a relationship between the rate of change of \( y \), denoted as \( y^{\prime}(t) \), and the current value of \( y \) itself. Such equations are common in real-world scenarios, ranging from population growth to the decay of radioactive substances.
This equation suggests a relationship between the rate of change of \( y \), denoted as \( y^{\prime}(t) \), and the current value of \( y \) itself. Such equations are common in real-world scenarios, ranging from population growth to the decay of radioactive substances.
- Significance: Illustrates how a function evolves over time.
- Solution: Finding a function or set of functions that satisfy the equation throughout its domain.
Numerical Approximation
Numerical approximation, like Euler's Method, is vital when solving differential equations that don't have straightforward solutions. Euler’s Method allows us to calculate function values at discrete steps by finding slopes at points and moving a small step (\( \Delta t \)) along the slope.
In this example, we used a step size of \( \Delta t = 0.5 \) to approximate values \( u_1 \) and \( u_2 \). The method doesn't provide perfect solutions but offers a close enough approximation to understand how the function behaves over an interval.
In this example, we used a step size of \( \Delta t = 0.5 \) to approximate values \( u_1 \) and \( u_2 \). The method doesn't provide perfect solutions but offers a close enough approximation to understand how the function behaves over an interval.
- Step Size \( \Delta t \): Determines precision and is the interval between successive points.
- Process: Estimate the next point using current estimate and slope.