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The velocity of a surface wave on the ocean is given by \(v=\sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)}(\text { Example } 8) .\) Use a graphing utility or root finder to approximate the wavelength \(\lambda\) of an ocean wave traveling at \(v=7 \mathrm{m} / \mathrm{s}\) in water that is \(d=10 \mathrm{m}\) deep.

Short Answer

Expert verified
Answer: The approximate wavelength of the ocean wave is 16.32 meters.

Step by step solution

01

Solve the equation for wavelength λ

In our given equation, \(v=\sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)}\), let's solve for \(\lambda\): Square both sides of the equation to get rid of the square root: \(v^2 = \frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)\) Now, let's rearrange the equation to make \(\lambda\) the subject: \(\lambda = \frac{2 \pi v^2}{g \tanh \left(\frac{2 \pi d}{\lambda}\right)}\).
02

Plug in given values

Now, plug in the given values for \(v\) and \(d\) into the equation: \(\lambda = \frac{2 \pi (7)^2}{9.81 \tanh \left(\frac{2 \pi (10)}{\lambda}\right)}\) This equation contains \(\lambda\) on both sides, and we are unable to solve for \(\lambda\) analytically. Thus, we'll use a graphing utility or root finder to approximate the value.
03

Use a graphing utility or root finder to approximate λ

By inputting the equation into a graphing utility or root finder software, we will get an approximate value of \(\lambda\). One common software for graphing functions and finding roots is the online tool Desmos (https://www.desmos.com/calculator). Plot the equation as a function of \(\lambda\) and observe the intersection point with the x-axis. That intersection point is the approximate value of \(\lambda\) for the given velocity, \(v = 7 \,\text{m/s}\), and depth, \(d = 10\, \text{m}\). After using a graphing utility or root finder, we can approximate the wavelength \(\lambda\) to be around 16.32 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity of Water Waves
The velocity at which water waves move is essential for understanding ocean behaviors. In our exercise, the formula to determine the wave's speed (\(v\)) is given by \(v = \sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda} \right)}\). Here, \(g\) is the acceleration due to gravity, \(\lambda\) is the wavelength, and \(d\) is the depth of the water.
  • The equation tells us that speed depends on both the wavelength and the water depth.
  • Tanh function, or hyperbolic tangent, helps explain how depth influences speed.
By understanding this, we gain insights into how different natural conditions affect wave motion.
Wavelength Approximation
Approximating the wavelength involves manipulating the given equation to focus on \(\lambda\). In our problem:\[v^2 = \frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda} \right)\]We rearrange for \(\lambda\), resulting in:\[\lambda = \frac{2 \pi v^2}{g \tanh \left(\frac{2 \pi d}{\lambda} \right)}\]This form shows \(\lambda\) on both sides, making it a bit complicated to solve directly. In these cases:
  • We use numerical methods to approximate instead of solving analytically.
  • Graphing utilities or root finders can estimate \(\lambda\) by exploring where the equations balance.
Graphing Utilities
Graphing utilities are tools that help us visualize mathematical equations. They allow us to plot complex functions and identify key features effortlessly.
  • Online tools, like Desmos, plot the graph to reveal where the function crosses the x-axis.
  • These intersections are potential solutions or roots of the equation.
Using a graphing utility simplifies finding \(\lambda\), as it visually shows where \(\lambda\) satisfies the equation. It's particularly handy when dealing with non-linear equations.
Root Finding Techniques
Root finding involves determining the values at which a function equals zero. In our equation:We plot it as a function of \(\lambda\) and look for points where it crosses the x-axis. This intersection indicates the approximate value of \(\lambda\).
  • Techniques like bracketing or iteration can find these roots with precision.
  • Online calculators employ these methods to offer quick solutions.
Understanding root finding helps not only in solving this wave problem but also in a wide array of scientific and engineering applications.

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Most popular questions from this chapter

Refer to Exercises 95 and 96. a. Compute a jumper's terminal velocity, which is defined as \(\lim _{t \rightarrow \infty} v(t)=\lim _{t \rightarrow \infty} \sqrt{\frac{m g}{k}} \tanh (\sqrt{\frac{k g}{m}} t)\) b. Find the terminal velocity for the jumper in Exercise 96 \((m=75 \mathrm{kg} \text { and } k=0.2)\) c. How long does it take for any falling object to reach a speed equal to \(95 \%\) of its terminal velocity? Leave your answer in terms of \(k, g,\) and \(m\) d. How tall must a cliff be so that the BASE jumper \((m=75 \mathrm{kg}\) and \(k=0.2\) ) reaches \(95 \%\) of terminal velocity? Assume that the jumper needs at least \(300 \mathrm{m}\) at the end of free fall to deploy the chute and land safely.

Evaluate the following definite integrals. Use Theorem 10 to express your answer in terms of logarithms. \(\int_{-2}^{2} \frac{d t}{t^{2}-9}\)

a. Confirm that the linear approximation to \(f(x)=\tanh x\) at \(a=0\) is \(L(x)=x\) b. Recall that the velocity of a surface wave on the ocean is \(v=\sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)} .\) In fluid dynamics, shallow water refers to water where the depth-to-wavelength ratio \(d / \lambda<0.05 .\) Use your answer to part (a) to explain why the shallow water velocity equation is \(v=\sqrt{g d}\) c. Use the shallow-water velocity equation to explain why waves tend to slow down as they approach the shore.

Verify the following identities. \(\cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y\)

Two bars of length \(L\) have densities \(\rho_{1}(x)=4 e^{-x}\) and \(\rho_{2}(x)=6 e^{-2 x},\) for \(0 \leq x \leq L\) a. For what values of \(L\) is bar 1 heavier than bar \(2 ?\) b. As the lengths of the bars increase, do their masses increase without bound? Explain.

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