Chapter 6: Problem 26
Compute \(d y / d x\) for the following functions. \(y=\sqrt{\operatorname{coth} 3 x}\)
Short Answer
Expert verified
The derivative of the function \(y = \sqrt{\operatorname{coth} 3x}\) with respect to \(x\) is \(\frac{dy}{dx} = -\frac{3}{2\sqrt{\operatorname{coth} 3x} (\operatorname{sinh}(3x))^2}\).
Step by step solution
01
Compute the derivative of \(f(u)\) with respect to \(u\)
Using the power rule, we have
\(\frac{d}{du}\sqrt{u} = \frac{1}{2\sqrt{u}}\)
02
Compute the derivative of \(g(x)\) with respect to \(x\)
We have \(g(x) = \operatorname{coth} 3x\), so let's first find the derivative of \(\operatorname{coth} u\) with respect to \(u\).
Recall that \(\operatorname{coth} u = \frac{\operatorname{cosh} u}{\operatorname{sinh} u}\).
Using the quotient rule, we get
\(\frac{d}{du} \operatorname{coth} u = \frac{ \operatorname{sinh} u(\operatorname{cosh} u)' - \operatorname{cosh} u(\operatorname{sinh} u)'}{(\operatorname{sinh} u)^2} = \frac{\operatorname{sinh} u( \operatorname{sinh} u ) - \operatorname{cosh} u( \operatorname{cosh} u)}{(\operatorname{sinh} u)^2} = \frac{(\operatorname{cosh} u)^2 - (\operatorname{sinh} u)^2}{(\operatorname{sinh} u)^2}\)
Using the identity \(\operatorname{cosh}^2 u - \operatorname{sinh}^2 u = 1\), we then have
\(\frac{d}{du} \operatorname{coth} u = -\frac{1}{(\operatorname{sinh} u)^2}\)
Now, we can find the derivative of \(g(x)\) with respect to \(x\) using the chain rule:
\(\frac{d}{dx}\operatorname{coth} 3x = -\frac{1}{(\operatorname{sinh} (3x))^2} (3) = -\frac{3}{(\operatorname{sinh} (3x))^2}\)
03
Apply the chain rule
Finally, using the chain rule to find the derivative of \(y\) with respect to \(x\), we get
\(\frac{dy}{dx} = \frac{d}{dx}\sqrt{\operatorname{coth} 3x} = \frac{1}{2\sqrt{\operatorname{coth} 3x}}\cdot\left(-\frac{3}{(\operatorname{sinh} (3x))^2}\right) = -\frac{3}{2\sqrt{\operatorname{coth} 3x} (\operatorname{sinh}(3x))^2}\)
So, the derivative of the given function with respect to \(x\) is:
\(\frac{dy}{dx} = -\frac{3}{2\sqrt{\operatorname{coth} 3x} (\operatorname{sinh}(3x))^2}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental tool in calculus for finding the derivative of composite functions, which are functions whose inputs are also functions. It allows you to "link" the derivatives of the inner and outer functions together for this purpose. When dealing with composite functions of the form \(f(g(x))\), the chain rule states that the derivative \(\frac{d}{dx}f(g(x))\) is the derivative of the outer function \(f\) evaluated at the inner function \(g(x)\), multiplied by the derivative of the inner function \(g(x)\).
- Mathematically expressed, it is: \( \frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x) \).
- This rule is crucial when dealing with nested functions, as it allows us to compute the outer function's contribution and the inner function's rate of change separately.
Hyperbolic Functions
Hyperbolic functions are analogs of trigonometric functions that are based on hyperbolas instead of circles. They are important in various mathematical applications, particularly in calculus and complex analysis. The main hyperbolic functions are the hyperbolic sine \(\operatorname{sinh} x\) and hyperbolic cosine \(\operatorname{cosh} x\), from which other hyperbolic functions are derived.
- \(\operatorname{coth}(x)\), or hyperbolic cotangent, is one such derived function, defined as \( \operatorname{coth}(x) = \frac{\operatorname{cosh} x}{\operatorname{sinh} x} \).
- The identity \(\operatorname{cosh}^2 u - \operatorname{sinh}^2 u = 1\) is particularly useful, similar to the Pythagorean identity in trigonometry.
Quotient Rule
The quotient rule is a method for finding the derivative of a function that is the ratio of two differentiable functions. It is particularly useful when the standard rules for derivatives, such as the product rule, do not easily apply. For two functions \(u(x)\) and \(v(x)\), if we have a function \(h(x) = \frac{u(x)}{v(x)}\), the derivative \(h'(x)\) can be found using the quotient rule.
- The formula for the quotient rule is: \[ \frac{d}{dx} \left( \frac{u(x)}{v(x)} \right) = \frac{v(x)u'(x) - u(x)v'(x)}{[v(x)]^2} \].
- This formula helps avoid the messiness of manually working through derivatives of such ratios.