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Evaluate the following limits. $$\lim _{(x, y, z) \rightarrow(0,1,0)} \ln e^{x z}(1+y)$$

Short Answer

Expert verified
Answer: The limit of the function is 0.

Step by step solution

01

Simplify the given function

First, let's simplify the given function: $$ \ln e^{xz}(1+y) $$ We have two parts here: 1. \(\ln e^{xz}\) 2. \((1+y)\) Using the properties of the natural logarithm function, the first part simplifies to: $$ \ln e^{xz} = xz $$ Thus, the entire simplified function becomes: $$ f(x, y, z) = xz(1+y) $$
02

Find the limit with the given values

As \((x,y,z)\) approaches \((0,1,0)\), we substitute these values into the simplified function: $$ \lim_{(x, y, z) \to (0, 1, 0)} xz(1+y) $$ Now, let's determine the limit: $$ \lim_{(x, y, z) \to (0, 1, 0)} xz(1+y) = (0)(0)(1+1) = 0 $$ The limit of the function \(f(x, y, z) = xz(1+y)\) as \((x, y, z) \to (0, 1, 0)\) is equal to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm Properties
Understanding the properties of the natural logarithm is crucial in simplifying complex expressions. The natural logarithm, denoted as \( \ln \), has several key properties that can simplify calculus problems:
  • \( \ln(e^x) = x \): This property is incredibly useful for simplification, as shown in the exercise. When the term \( \ln(e^{xz}) \) appears, it reduces directly to \( xz \).
  • \( \ln(a \cdot b) = \ln a + \ln b \): This property helps break down products inside a logarithm into more manageable terms.
  • \( \ln\left(\frac{a}{b}\right) = \ln a - \ln b \): Useful for dividing terms under a logarithm.
By applying these properties, you can transform seemingly complicated expressions into simpler, manageable forms. This is exactly what happens when we simplify \( \ln e^{xz}(1+y) \) to \( xz(1+y) \). Understanding these transformations makes evaluating limits much more straightforward.
Limit Evaluation
The process of evaluating limits in calculus is a method to understand how a function behaves as it approaches a particular point. This exercise deals with the multivariable limit of a function as the variables \((x, y, z)\) approach \((0,1,0)\). The steps are as follows:
  • Simplify the function wherever possible, as seen with the natural logarithm properties. Here, the expression simplified to \( f(x, y, z) = xz(1+y) \).
  • Substitute the values into the simplified function. For the point \((0, 1, 0)\), replace each variable accordingly.
  • Calculate the expression: \( (0)(0)(1+1) = 0 \).
As the function approaches the specified point, if the outcome is consistent, you have successfully evaluated the limit. The overall approach helps to predict behavior or trends of a function near given points without needing to compute directly at those points.
Multivariable Calculus
Multivariable calculus extends the principles of calculus to functions of several variables. When evaluating limits in this context, it is important to consider how changes in each variable can independently affect the entire function. Key considerations in multivariable calculus include:
  • Understanding the point the variables are approaching. For our exercise, this is \((0,1,0)\).
  • Identifying simplifying opportunities using properties, such as breaking down the logarithm.
  • Employing substitution to find the limit, taking careful steps to ensure every part of the expression is correctly approached.
Handling multivariable functions can be quite complex; however, breaking them into simpler parts, as seen with the given function \( f(x, y, z) = xz(1+y) \), allows for a more manageable approach. Learning to work with these kinds of functions enhances your understanding of how calculus operates in multi-dimensional scenarios.

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Most popular questions from this chapter

Let \(x, y,\) and \(z\) be nonnegative numbers with \(x+y+z=200\). a. Find the values of \(x, y,\) and \(z\) that minimize \(x^{2}+y^{2}+z^{2}\). b. Find the values of \(x, y,\) and \(z\) that minimize \(\sqrt{x^{2}+y^{2}+z^{2}}\). c. Find the values of \(x, y,\) and \(z\) that maximize \(x y z\). d. Find the values of \(x, y,\) and \(z\) that maximize \(x^{2} y^{2} z^{2}\).

Problems with two constraints Given a differentiable function \(w=f(x, y, z),\) the goal is to find its maximum and minimum values subject to the constraints \(g(x, y, z)=0\) and \(h(x, y, z)=0\) where \(g\) and \(h\) are also differentiable. a. Imagine a level surface of the function \(f\) and the constraint surfaces \(g(x, y, z)=0\) and \(h(x, y, z)=0 .\) Note that \(g\) and \(h\) intersect (in general) in a curve \(C\) on which maximum and minimum values of \(f\) must be found. Explain why \(\nabla g\) and \(\nabla h\) are orthogonal to their respective surfaces. b. Explain why \(\nabla f\) lies in the plane formed by \(\nabla g\) and \(\nabla h\) at a point of \(C\) where \(f\) has a maximum or minimum value. c. Explain why part (b) implies that \(\nabla f=\lambda \nabla g+\mu \nabla h\) at a point of \(C\) where \(f\) has a maximum or minimum value, where \(\lambda\) and \(\mu\) (the Lagrange multipliers) are real numbers. d. Conclude from part (c) that the equations that must be solved for maximum or minimum values of \(f\) subject to two constraints are \(\nabla f=\lambda \nabla g+\mu \nabla h, g(x, y, z)=0,\) and \(h(x, y, z)=0\)

Use the definition of the gradient (in two or three dimensions), assume that \(f\) and \(g\) are differentiable functions on \(\mathbb{R}^{2}\) or \(\mathbb{R}^{3},\) and let \(c\) be a constant. Prove the following gradient rules. a. Constants Rule: \(\nabla(c f)=c \nabla f\) b. Sum Rule: \(\nabla(f+g)=\nabla f+\nabla g\) c. Product Rule: \(\nabla(f g)=(\nabla f) g+f \nabla g\) d. Quotient Rule: \(\nabla\left(\frac{f}{g}\right)=\frac{g \nabla f-f \nabla g}{g^{2}}\) e. Chain Rule: \(\nabla(f \circ g)=f^{\prime}(g) \nabla g,\) where \(f\) is a function of one variable

Given three distinct noncollinear points \(A, B,\) and \(C\) in the plane, find the point \(P\) in the plane such that the sum of the distances \(|A P|+|B P|+|C P|\) is a minimum. Here is how to proceed with three points, assuming that the triangle formed by the three points has no angle greater than \(2 \pi / 3\left(120^{\circ}\right)\). a. Assume the coordinates of the three given points are \(A\left(x_{1}, y_{1}\right)\) \(B\left(x_{2}, y_{2}\right),\) and \(C\left(x_{3}, y_{3}\right) .\) Let \(d_{1}(x, y)\) be the distance between \(A\left(x_{1}, y_{1}\right)\) and a variable point \(P(x, y) .\) Compute the gradient of \(d_{1}\) and show that it is a unit vector pointing along the line between the two points. b. Define \(d_{2}\) and \(d_{3}\) in a similar way and show that \(\nabla d_{2}\) and \(\nabla d_{3}\) are also unit vectors in the direction of the line between the two points. c. The goal is to minimize \(f(x, y)=d_{1}+d_{2}+d_{3}\) Show that the condition \(f_{x}=f_{y}=0\) implies that \(\nabla d_{1}+\nabla d_{2}+\nabla d_{3}=0\). d. Explain why part (c) implies that the optimal point \(P\) has the property that the three line segments \(A P, B P,\) and \(C P\) all intersect symmetrically in angles of \(2 \pi / 3\). e. What is the optimal solution if one of the angles in the triangle is greater than \(2 \pi / 3\) (just draw a picture)? f. Estimate the Steiner point for the three points (0,0),(0,1) and (2,0)

What point on the plane \(x-y+z=2\) is closest to the point (1,1,1)\(?\)

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