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Midpoint of a line segment Use vectors to show that the midpoint of the line segment joining \(P\left(x_{1}, y_{1}\right)\) and \(Q\left(x_{2}, y_{2}\right)\) is the point \(\left(\left(x_{1}+x_{2}\right) / 2,\left(y_{1}+y_{2}\right) / 2\right) .\) (Hint: Let \(O\) be the origin and let \(M\) be the midpoint of \(P Q\). Draw a picture and show that \(\overrightarrow{O M}=\overrightarrow{O P}+\frac{1}{2} \overrightarrow{P Q}=\overrightarrow{O P}+\frac{1}{2}(\overrightarrow{O Q}-\overrightarrow{O P})\).

Short Answer

Expert verified
Answer: The coordinates of the midpoint are \(\left(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\right)\).

Step by step solution

01

Represent Points with Vectors

Let's represent each point with the respective vectors: - Point \(P\left(x_{1}, y_{1}\right)\): \(\overrightarrow{O P}=\begin{bmatrix} x_1 \\ y_1 \end{bmatrix}\). - Point \(Q\left(x_{2}, y_{2}\right)\): \(\overrightarrow{O Q}=\begin{bmatrix} x_2 \\ y_2 \end{bmatrix}\). - Point \(M\left(x_m, y_m\right)\): \(\overrightarrow{O M}=\begin{bmatrix} x_m \\ y_m \end{bmatrix}\).
02

Calculate Vector PQ

We can calculate vector \(\overrightarrow{P Q}\) by subtracting the vector \(\overrightarrow{O P}\) from \(\overrightarrow{O Q}\): \(\overrightarrow{P Q}=\overrightarrow{O Q}-\overrightarrow{O P}\) So, \(\overrightarrow{P Q}=\begin{bmatrix} x_2-x_1 \\ y_2-y_1 \end{bmatrix}\).
03

Calculate the Sum of OP and half PQ

Now, let's calculate \(\overrightarrow{O P}+\frac{1}{2} \overrightarrow{P Q}\) using the given formula. It is given in the formula that \(\overrightarrow{O M}=\overrightarrow{O P}+\frac{1}{2} \overrightarrow{P Q}\). So, \(\begin{bmatrix} x_m \\ y_m \end{bmatrix} =\begin{bmatrix} x_1 \\ y_1 \end{bmatrix} + \frac{1}{2} \begin{bmatrix} x_2-x_1 \\ y_2-y_1 \end{bmatrix}\). Now, let's calculate the answer for both \(x_m\) and \(y_m\). - \(x_m= x_1 + \frac{1}{2}(x_2-x_1) = \frac{x_1 + x_2}{2}\) - \(y_m= y_1 + \frac{1}{2}(y_2-y_1) = \frac{y_1 + y_2}{2}\)
04

Conclude the Midpoint

Therefore, the midpoint \(M\) of the line segment joining \(P\left(x_{1}, y_{1}\right)\) and \(Q\left(x_{2}, y_{2}\right)\) is the point \(\left(\left(x_{1}+x_{2}\right) / 2,\left(y_{1}+y_{2}\right) / 2\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Midpoint
The midpoint of a line segment is a key concept in geometry. It is the point exactly halfway between two endpoints of a segment. In vector terms, the midpoint of a line segment connecting two points \(P(x_1, y_1)\) and \(Q(x_2, y_2)\) is calculated by averaging the coordinates of \(P\) and \(Q\). This is done by:
  • Finding the average of the \(x\)-coordinates: \((x_1 + x_2) / 2\)
  • Finding the average of the \(y\)-coordinates: \((y_1 + y_2) / 2\)
Applying these calculations, the midpoint \(M\) is given by the coordinates \(M((x_1 + x_2)/2, (y_1 + y_2)/2)\). This method simplifies determining the central point between two specific locations.
Line Segment
A line segment consists of two endpoints and all the points in between them. It is different from a line, which extends infinitely in both directions. In mathematics, we often represent a line segment by its endpoints, such as \(P(x_1, y_1)\) and \(Q(x_2, y_2)\). This exercise involves:
  • Labeling and representing endpoints as vectors, such as \(\overrightarrow{OP}\) and \(\overrightarrow{OQ}\).
  • Calculating the vector \(\overrightarrow{PQ}\), which connects the endpoints by subtracting one vector from the other: \(\overrightarrow{PQ} = \overrightarrow{OQ} - \overrightarrow{OP}\).
This concept helps us understand relationships and calculations related to distances and midpoints.
Origin
The origin plays a central role in vector problems. It is the point \((0, 0)\) in a coordinate system, acting as the starting reference point for vectors. In this exercise:
  • We define vectors such as \(\overrightarrow{OP}\) and \(\overrightarrow{OQ}\) with the origin \(O\) as the initial point.
  • The vector addition principle involves calculating vector \(\overrightarrow{OM}\), starting from the origin, using known vectors.
Utilizing the origin allows for consistency and simplicity in calculations involving vector addition and midpoint determination.
Vector Addition
Vector addition is a foundational aspect of understanding vector mechanics. It involves combining vectors to determine a resultant vector. Here's how it works in this context:
  • To find \(\overrightarrow{OM}\), the formula \(\overrightarrow{OM} = \overrightarrow{OP} + \frac{1}{2} \overrightarrow{PQ}\) is used.
  • This equation allows us to express \(OM\) as the sum of vector \(OP\) and half of vector \(PQ\).
By adding vectors, we ascertain both the direction and magnitude of resultant vectors, making calculations clear and systematic. This principle is crucial in determining points like midpoints effectively.

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Most popular questions from this chapter

Consider the motion of an object given by the position function $$\mathbf{r}(t)=f(t)\langle a, b, c\rangle+\left(x_{0}, y_{0}, z_{0}\right\rangle, \text { for } t \geq 0$$ where \(a, b, c, x_{0}, y_{0},\) and \(z_{0}\) are constants and \(f\) is a differentiable scalar function, for \(t \geq 0\) a. Explain why this function describes motion along a line. b. Find the velocity function. In general, is the velocity constant in magnitude or direction along the path?

Parabolic trajectory Consider the parabolic trajectory $$ x=\left(V_{0} \cos \alpha\right) t, y=\left(V_{0} \sin \alpha\right) t-\frac{1}{2} g t^{2} $$ where \(V_{0}\) is the initial speed, \(\alpha\) is the angle of launch, and \(g\) is the acceleration due to gravity. Consider all times \([0, T]\) for which \(y \geq 0\) a. Find and graph the speed, for \(0 \leq t \leq T.\) b. Find and graph the curvature, for \(0 \leq t \leq T.\) c. At what times (if any) do the speed and curvature have maximum and minimum values?

Assume that \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) are vectors in \(\mathrm{R}^{3}\) that form the sides of a triangle (see figure). Use the following steps to prove that the medians intersect at a point that divides each median in a 2: 1 ratio. The proof does not use a coordinate system. a. Show that \(\mathbf{u}+\mathbf{v}+\mathbf{w}=\mathbf{0}\) b. Let \(\mathbf{M}_{1}\) be the median vector from the midpoint of \(\mathbf{u}\) to the opposite vertex. Define \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) similarly. Using the geometry of vector addition show that \(\mathbf{M}_{1}=\mathbf{u} / 2+\mathbf{v} .\) Find analogous expressions for \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) c. Let \(a, b,\) and \(c\) be the vectors from \(O\) to the points one-third of the way along \(\mathbf{M}_{1}, \mathbf{M}_{2},\) and \(\mathbf{M}_{3},\) respectively. Show that \(\mathbf{a}=\mathbf{b}=\mathbf{c}=(\mathbf{u}-\mathbf{w}) / 3\) d. Conclude that the medians intersect at a point that divides each median in a 2: 1 ratio.

The points \(P, Q, R,\) and \(S,\) joined by the vectors \(\mathbf{u}, \mathbf{v}, \mathbf{w},\) and \(\mathbf{x},\) are the vertices of a quadrilateral in \(\mathrm{R}^{3}\). The four points needn't lie in \(a\) plane (see figure). Use the following steps to prove that the line segments joining the midpoints of the sides of the quadrilateral form a parallelogram. The proof does not use a coordinate system. a. Use vector addition to show that \(\mathbf{u}+\mathbf{v}=\mathbf{w}+\mathbf{x}\) b. Let \(m\) be the vector that joins the midpoints of \(P Q\) and \(Q R\) Show that \(\mathbf{m}=(\mathbf{u}+\mathbf{v}) / 2\) c. Let n be the vector that joins the midpoints of \(P S\) and \(S R\). Show that \(\mathbf{n}=(\mathbf{x}+\mathbf{w}) / 2\) d. Combine parts (a), (b), and (c) to conclude that \(\mathbf{m}=\mathbf{n}\) e. Explain why part (d) implies that the line segments joining the midpoints of the sides of the quadrilateral form a parallelogram.

Show that the two-dimensional trajectory $$x(t)=u_{0} t+x_{0}\( and \)y(t)=-\frac{g t^{2}}{2}+v_{0} t+y_{0},\( for \)0 \leq t \leq T$$ of an object moving in a gravitational field is a segment of a parabola for some value of \(T>0 .\) Find \(T\) such that \(y(T)=0\)

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