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Let \(\mathbf{u}=\left\langle u_{1}, u_{2}, u_{3}\right\rangle\) \(\mathbf{v}=\left\langle v_{1}, v_{2}, v_{3}\right\rangle\), and \(\mathbf{w}=\) \(\left\langle w_{1}, w_{2}, w_{3}\right\rangle\). Let \(c\) be a scalar. Prove the following vector properties. \(\mathbf{u} \cdot \mathbf{v}=\mathbf{v} \cdot \mathbf{u}\)

Short Answer

Expert verified
Question: Prove the commutative property for the dot product of two vectors \(\mathbf{u}\) and \(\mathbf{v}\): \(\mathbf{u} \cdot \mathbf{v} = \mathbf{v} \cdot \mathbf{u}\). Answer: Using the definition of the dot product and the commutative property of multiplication, we showed that \(\mathbf{u} \cdot \mathbf{v} = u_{1}v_{1} + u_{2}v_{2} + u_{3}v_{3}\) and \(\mathbf{v} \cdot \mathbf{u} = v_{1}u_{1} + v_{2}u_{2} + v_{3}u_{3}\), which are equal expressions. Therefore, \(\mathbf{u} \cdot \mathbf{v} = \mathbf{v} \cdot \mathbf{u}\), proving the commutative property for the dot product.

Step by step solution

01

Write down the definition of the dot product

The dot product of two vectors \(\mathbf{u}\) and \(\mathbf{v}\) is defined as \(\mathbf{u} \cdot \mathbf{v} = u_{1}v_{1} + u_{2}v_{2} + u_{3}v_{3}\).
02

Calculate \(\mathbf{u} \cdot \mathbf{v}\)

Using the definition of the dot product, we can calculate \(\mathbf{u} \cdot \mathbf{v}\) as \(u_{1}v_{1} + u_{2}v_{2} + u_{3}v_{3}\).
03

Calculate \(\mathbf{v} \cdot \mathbf{u}\)

Similarly, we can calculate \(\mathbf{v} \cdot \mathbf{u}\) as \(v_{1}u_{1} + v_{2}u_{2} + v_{3}u_{3}\).
04

Prove the commutative property

Since multiplication is commutative, we know that \(u_{1}v_{1}=v_{1}u_{1}\), \(u_{2}v_{2}=v_{2}u_{2}\), and \(u_{3}v_{3}=v_{3}u_{3}\). So, the expressions for \(\mathbf{u} \cdot \mathbf{v}\) and \(\mathbf{v} \cdot \mathbf{u}\) are equal: $$u_{1}v_{1} + u_{2}v_{2} + u_{3}v_{3} = v_{1}u_{1} + v_{2}u_{2} + v_{3}u_{3}$$ Thus, we have proven the commutative property for the dot product: \(\mathbf{u} \cdot \mathbf{v} = \mathbf{v} \cdot \mathbf{u}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product is an essential concept in vector algebra that involves two vectors. Given two vectors \( \mathbf{u} = \langle u_1, u_2, u_3 \rangle \) and \( \mathbf{v} = \langle v_1, v_2, v_3 \rangle \), their dot product is calculated as the sum of the products of their corresponding components:
  • \( \mathbf{u} \cdot \mathbf{v} = u_1 v_1 + u_2 v_2 + u_3 v_3 \)
This operation results in a scalar, not a vector. The dot product measures the extent to which two vectors point in the same direction.
If the result is positive, the vectors tend to point in the same direction. If it's zero, the vectors are perpendicular.
Understanding the dot product helps explore concepts such as projection and orthogonality, which are fundamental in physics and engineering.
Commutative Property
In mathematics, the commutative property refers to the idea that the order in which two numbers are added or multiplied does not change the result. This holds true for the dot product of vectors as well.
To demonstrate the commutative property for the dot product, consider two vectors \( \mathbf{u} = \langle u_1, u_2, u_3 \rangle \) and \( \mathbf{v} = \langle v_1, v_2, v_3 \rangle \).
Calculating \( \mathbf{u} \cdot \mathbf{v} \) gives us:
  • \( u_1 v_1 + u_2 v_2 + u_3 v_3 \)
Similarly, \( \mathbf{v} \cdot \mathbf{u} \) yields:
  • \( v_1 u_1 + v_2 u_2 + v_3 u_3 \)
Since multiplication is commutative\( (a \cdot b = b \cdot a) \), each of these expressions is identical, demonstrating that:
  • \( \mathbf{u} \cdot \mathbf{v} = \mathbf{v} \cdot \mathbf{u} \)
This property makes the dot product symmetrical and convenient for analysis of vector relationships.
Vector Operations
Vector operations encompass various ways to manipulate vectors mathematically. Common operations include:
  • Addition and Subtraction: Vectors are added by summing their corresponding components. Subtraction works the same, but instead subtracts components.

  • Scalar Multiplication: Each component of the vector is multiplied by a scalar, altering the vector's magnitude but not its direction.

  • Dot Product: As we defined earlier, the dot product is a scalar value indicating the directional relationship between two vectors.

  • Cross Product: Exclusive to three-dimensional space, the cross product results in a vector perpendicular to the original vectors, representing the area of the parallelogram formed by them.
Understanding vector operations is vital, as they are applied in numerous fields such as physics, engineering, and computer graphics. Such operations allow us to handle spatial objects efficiently, predict motion, and simulate real-world environments. Each operation uniquely addresses specific problems and enhances our ability to work with vector quantities.

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Most popular questions from this chapter

Determine whether the following statements are true and give an explanation or counterexample. a. The line \(\mathbf{r}(t)=\langle 3,-1,4\rangle+t\langle 6,-2,8\rangle\) passes through the origin. b. Any two nonparallel lines in \(\mathbb{R}^{3}\) intersect. c. The curve \(\mathbf{r}(t)=\left\langle e^{-t}, \sin t,-\cos t\right\rangle\) approaches a circle as \(t \rightarrow \infty\). d. If \(\mathbf{r}(t)=e^{-t^{2}}\langle 1,1,1\rangle\) then \(\lim _{t \rightarrow \infty} \mathbf{r}(t)=\lim _{t \rightarrow-\infty} \mathbf{r}(t)\).

An object moves clockwise around a circle centered at the origin with radius \(5 \mathrm{m}\) beginning at the point (0,5) a. Find a position function \(\mathbf{r}\) that describes the motion if the object moves with a constant speed, completing 1 lap every 12 s. b. Find a position function \(\mathbf{r}\) that describes the motion if it occurs with speed \(e^{-t}\)

An object moves on the helix \(\langle\cos t, \sin t, t\rangle,\) for \(t \geq 0\) a. Find a position function \(\mathbf{r}\) that describes the motion if it occurs with a constant speed of \(10 .\) b. Find a position function \(\mathbf{r}\) that describes the motion if it occurs with speed \(t\)

Consider the curve \(\mathbf{r}(t)=(a \cos t+b \sin t) \mathbf{i}+(c \cos t+d \sin t) \mathbf{j}+(e \cos t+f \sin t) \mathbf{k}\) where \(a, b, c, d, e,\) and fare real numbers. It can be shown that this curve lies in a plane. Graph the following curve and describe it. $$\begin{aligned} \mathbf{r}(t)=&\left(\frac{1}{\sqrt{2}} \cos t+\frac{1}{\sqrt{3}} \sin t\right) \mathbf{i}+\left(-\frac{1}{\sqrt{2}} \cos t+\frac{1}{\sqrt{3}} \sin t\right) \mathbf{j} \\ &+\left(\frac{1}{\sqrt{3}} \sin t\right) \mathbf{k} \end{aligned}$$

Suppose \(\mathbf{u}\) and \(\mathbf{v}\) are nonzero vectors in \(\mathbb{R}^{3}\). a. Prove that the equation \(\mathbf{u} \times \mathbf{z}=\mathbf{v}\) has a nonzero solution \(\mathbf{z}\) if and only if \(\mathbf{u} \cdot \mathbf{v}=0 .\) (Hint: Take the dot product of both sides with v.) b. Explain this result geometrically.

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