Chapter 12: Problem 70
Circle and radius of curvature Choose a point \(P\) on a smooth curve \(C\) in the plane. The circle of curvature (or osculating circle) at the point \(P\) is the circle that (a) is tangent to \(C\) at \(P,\) (b) has the same curvature as \(C\) at \(P,\) and ( \(c\) ) lies on the same side of \(C\) as the principal unit normal \(\mathbf{N}\) (see figure). The radius of curvature is the radius of the circle of curvature. Show that the radius of curvature is \(1 / \kappa,\) where \(\kappa\) is the curvature of \(C\) at \(P.\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.