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Give a geometric description of the set of points \((x, y, z)\) that lie on the intersection of the sphere \(x^{2}+y^{2}+z^{2}=36\) and the plane \(z=6\)

Short Answer

Expert verified
Answer: The geometric description is a single point \((0, 0, 6)\).

Step by step solution

01

Substitute the plane equation into the sphere equation

We will substitute the equation of the plane, \(z=6\), into the equation of the sphere, \(x^2+y^2+z^2=36\): \(x^2+y^2+(6)^2=36\) This simplifies to: \(x^2+y^2+36=36\)
02

Simplify the equation

Now, we'll subtract 36 from both sides of the equation: \(x^2+y^2=0\)
03

Analyze the simplified equation

The equation \(x^2+y^2=0\) represents a circle in the xy-plane with a radius of 0. This means that the intersection of the sphere and the plane is a single point, namely \((0,0,6)\). The geometric description of the set of points \((x, y, z)\) that lie on the intersection of the sphere and the plane is the single point \((0, 0, 6)\).

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