Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Give two alternative representations of the points in polar coordinates. $$\left(-4, \frac{3 \pi}{2}\right)$$

Short Answer

Expert verified
Answer: The two alternative representations of the point in polar coordinates are \((-4, \frac{7\pi}{2})\) and \((4, \frac{\pi}{2})\).

Step by step solution

01

Identify the given polar coordinates

The given polar coordinates are \((-4, \frac{3\pi}{2})\). We have \(r = -4\) and \(\theta = \frac{3\pi}{2}\).
02

Add or subtract multiples of \(2\pi\) to the given angle

We can add or subtract multiples of \(2\pi\) to the angle without changing the location of the point. In this case, let's add \(2\pi\) to the given angle: New angle: $$\theta_1 = \frac{3 \pi}{2} + 2 \pi = \frac{3 \pi}{2} + \frac{4 \pi}{2} = \frac{7 \pi}{2}$$ Alternative representation 1: \((-4, \frac{7\pi}{2})\)
03

Negate the distance and add or subtract odd multiples of \(\pi\) from the given angle

We can negate the distance and add or subtract odd multiples of \(\pi\) from the angle to find another alternative representation: New distance: $$r_1 = -(-4) = 4$$ New angle (subtracting \(\pi\)): $$\theta_2 = \frac{3 \pi}{2} - \pi = \frac{3 \pi}{2} - \frac{2 \pi}{2} = \frac{ \pi}{2}$$ Alternative representation 2: \((4, \frac{\pi}{2})\) The two alternative representations of the point in polar coordinates are: $$\left(-4, \frac{7\pi}{2}\right) \text{ and } \left(4, \frac{\pi}{2}\right)$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle Addition in Polar Coordinates
In the realm of polar coordinates, adding or subtracting certain angles can help represent the same point differently. This is because angles in polar coordinates are periodic. You might wonder why we can just add angles and not change the point's position at all. The key lies in recognizing that a full circle, or complete rotation, measures \(2\pi\) radians. Therefore, \(2\pi\) radians added or subtracted to an angle brings the point back to the initial heading, since it's just a full loop around the circle.
  • For instance, given an angle \(\frac{3\pi}{2}\), adding \(2\pi\) gets us to \(\frac{7\pi}{2}\).
  • The coordinates \((-4, \frac{3\pi}{2})\) change to \((-4, \frac{7\pi}{2})\) upon angle addition.
This is a useful tool in polar coordinate transformation as it maintains the point's location but provides a different visual interpretation, which can aid in solving problems by offering alternative views.
Coordinate Transformation: Polar to Polar
Coordinate transformation involves changing how coordinates are represented, without altering the point's position itself. In polar coordinates, this can mean altering either the direction by adjusting the angle, or the magnitude by changing the radius, or both.
  • One way is through angle addition, as previously discussed.
  • Another method is through distance negation, which takes a bit of a different path.
When it comes to transforming coordinates, the focus is often on changing values like the angle for clarity in problems. Still, it holds the essence of keeping the point constant in its original or intended position without actual movement in space. This allows students to understand better how each mathematical change affects or reroutes understanding while staying true to the origin of the coordinates.
Understanding Distance Negation
Distance negation is an intriguing concept in polar coordinates that helps to find alternative representations by reversing the sign of the radius. In simple terms, negating the distance ( ") means switching sides of the origin polar point.
  • If the radius is negative, like -4, negating it becomes positive ( = 4).
  • To achieve this without shifting the point, altering the angle by \(\pi\) or other odd multiples is necessary.
Through this, you maintain the directionality, essentially mirroring the point over the origin. By flipping it around and changing the perspective with a short angle adjustment, the new coordinates remain linked to their original as valid representations in a different frame. Thus, a point like \((-4, \frac{3\pi}{2})\) can be transformed to \(4, \frac{\pi}{2}\). This is an action that mathematics uses to maintain coherence and flexibility in problem-solving, allowing students to see how changes affect viewpoints without altering the position.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sketch the graph of the following ellipses. Plot and label the coordinates of the vertices and foci, and find the lengths of the major and minor axes. Use a graphing utility to check your work. $$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1$$

Modify Figure 56 to derive the polar equation of a conic section with a focus at the origin in the following three cases. a. Vertical directrix at \(x=-d,\) where \(d > 0\) b. Horizontal directrix at \(y=d,\) where \(d > 0\) c. Horizontal directrix at \(y=-d,\) where \(d > 0\)

A focal chord of a conic section is a line through a focus joining two points of the curve. The latus rectum is the focal chord perpendicular to the major axis of the conic. Prove the following properties. The length of the latus rectum of an ellipse centered at the origin is \(2 b^{2} / a=2 b \sqrt{1-e^{2}}\)

Sketch the graph of the following ellipses. Plot and label the coordinates of the vertices and foci, and find the lengths of the major and minor axes. Use a graphing utility to check your work. $$\frac{x^{2}}{5}+\frac{y^{2}}{7}=1$$

Water flows in a shallow semicircular channel with inner and outer radii of \(1 \mathrm{m}\) and \(2 \mathrm{m}\) (see figure). At a point \(P(r, \theta)\) in the channel, the flow is in the tangential direction (counterclockwise along circles), and it depends only on \(r\), the distance from the center of the semicircles. a. Express the region formed by the channel as a set in polar coordinates. b. Express the inflow and outflow regions of the channel as sets in polar coordinates. c. Suppose the tangential velocity of the water in \(\mathrm{m} / \mathrm{s}\) is given by \(v(r)=10 r,\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.5, \frac{\pi}{4}\right)\) or \(\left(1.2, \frac{3 \pi}{4}\right) ?\) Explain. d. Suppose the tangential velocity of the water is given by \(v(r)=\frac{20}{r},\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.8, \frac{\pi}{6}\right)\) or \(\left(1.3, \frac{2 \pi}{3}\right) ?\) Explain. e. The total amount of water that flows through the channel (across a cross section of the channel \(\theta=\theta_{0}\) ) is proportional to \(\int_{1}^{2} v(r) d r .\) Is the total flow through the channel greater for the flow in part (c) or (d)?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free