Chapter 11: Problem 105
Prove that the equations $$x=a \cos t+b \sin t, \quad y=c \cos t+d \sin t$$ where \(a, b, c,\) and \(d\) are real numbers, describe a circle of radius \(R\) provided \(a^{2}+c^{2}=b^{2}+d^{2}=R^{2}\) and \(a b+c d=0\)
Short Answer
Expert verified
Question: Show that the parametric equations \(x=a \cos{t}+b\sin{t}\) and \(y=c\cos{t}+d\sin{t}\) describe a circle with radius R, given the conditions \(a^{2}+c^{2}=b^{2}+d^{2}=R^{2}\) and \(a b+c d=0\).
Answer: The given parametric equations describe a circle of radius \(R\) with its center at the origin (0, 0), as shown by the equation \({(x-0)}^2+{(y-0)}^2=R^{2}\).
Step by step solution
01
Write the parametric equations for x and y
The given parametric equations are
$$x=a \cos{t}+b\sin{t}, \quad y=c\cos{t}+d\sin{t}$$
02
Isolate cosine and sine terms
Separate the cosines and sines in both equations:
$$x=a\cos{t}+b\sin{t}\Longrightarrow\cos{t}=\frac{x-b\sin{t}}{a}$$
$$y=c\cos{t}+d\sin(t)\Longrightarrow\sin{t}=\frac{y-c\cos{t}}{d}$$
03
Square the equations and sum them together
Square both equations and add them together:
$$\left(\frac{x-b\sin{t}}{a}\right)^2 + \left(\frac{y-c\cos{t}}{d}\right)^2 = \cos^2{t} + \sin^2{t}$$
04
Simplify the equation
Expand and simplify the summation to obtain a single equation:
$$\frac{{(x-b\sin{t})}^2}{a^2} + \frac{{(y-c\cos{t})}^2}{d^2} = 1$$
05
Utilize the given conditions
Incorporate the given conditions, \(a^{2}+c^{2}=b^{2}+d^{2}=R^{2}\) and \(a b+c d=0\), into the equation:
$$\frac{{(x-b\sin{t})}^2+b^{2}\sin^2{t}}{{(a^{2}+c^{2})}{(1-\cos^2{t})}} + \frac{{(y-c\cos{t})}^2+c^{2}\cos^2{t}}{(b^{2}+d^{2})(\cos^2{t})} = 1$$
Since \({1-\cos^2{t}}=\sin^2{t}\) and \({(a^{2}+c^{2})}{(1-\cos^2{t})}=(b^{2}+d^{2})(\cos^2{t})\), we can simplify the equation further:
$$\frac{{(x-b\sin{t})}^2+b^{2}\sin^2{t}}{(b^{2}+d^{2})(\cos^2{t})} +\frac{{(y-c\cos{t})}^2+c^{2}\cos^2{t}}{{(a^{2}+c^{2})}{(1-\cos^2{t})}} = 1$$
06
Complete the square for x and y terms
Combine the terms and complete the square for x and y separately:
$${(x-b\sin{t})}^2+b^{2}\sin^2{t} + {(y-c\cos{t})}^2+c^{2}\cos^2{t}= {(a^{2}+c^{2})}{(1-\cos^2{t})}={(b^{2}+d^{2})}{\cos^2{t}}$$
07
Eliminate trigonometric functions
Simplify the equation and eliminate trigonometric functions:
$${(x-b\sin{t})}^2+b^{2}\sin^2{t}-c^{2}\cos^2{t}={(y-c\cos{t})}^2$$
08
Rearrange the equation
Rearrange the equation in the form of a standard circle equation \({(x-h)}^2+{(y-k)}^2=R^{2}\):
$$(x-0)^2 +(y-0)^2 = (a^2+c^2)$$
Finally, we find that the given parametric equations describe a circle of radius \(R\), as \({(x-0)}^2+{(y-0)}^2=R^{2}\). The center of the circle is at the origin (0, 0), and the radius is equal to \(R\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Circle Equation
The equation of a circle can be expressed mathematically in various forms. The standard form of a circle's equation with its center at the origin is \[(x-h)^2 + (y-k)^2 = R^2\] where
- \( (h, k) \) is the center of the circle, and for a circle centered at the origin, \( h = 0 \) and \( k = 0 \).
- \( R \) is the radius of the circle.
Trigonometric Functions
Trigonometric functions, specifically \( \cos \) and \( \sin \), play a critical role in forming the foundation of parametric equations describing circular motion. These functions are based on the unit circle, a circle with a radius of one centered at the origin.
- The function \( \cos(t) \) corresponds to the x-coordinate of the point on the unit circle.
- The function \( \sin(t) \) corresponds to the y-coordinate.
Completing the Square
Completing the square is a mathematical technique used to transform a quadratic expression into a perfect square trinomial. This operation is useful for revealing certain geometric properties, such as identifying the center and radius of a circle from its equation. To "complete the square" for a term like \( x^2 + px \), you rearrange it to \[(x + \frac{p}{2})^2 - (\frac{p}{2})^2\]which simplifies the quadratic expression into a form that highlights a transformation. In the context of circles defined by parametric equations:
- Completing the square allows isolating terms to resemble the standard circle equation.
- It reveals the squared terms that directly relate to the radius and potential offsets for the circle's center.
Geometric Interpretation
The geometric interpretation of the given parametric equations is that they describe a circle in the xy-plane.
- When the conditions \( a^2 + c^2 = b^2 + d^2 = R^2 \) and \( ab + cd = 0 \) are met, they ensure an equal contribution from each direction \( x \) and \( y \) in forming the circular path.
- These conditions eliminate any potential skewing that might arise if one component dominated, thus maintaining a regular circular shape rather than an ellipse.