Chapter 0: Problem 38
Find the domain and sketch the graph of the function. What is its range? $$ f(x)=\left\\{\begin{array}{ll} -x-1 & \text { if } x<-1 \\ 0 & \text { if }-1 \leq x \leq 1 \\ x+1 & \text { if } x>1 \end{array}\right. $$
Chapter 0: Problem 38
Find the domain and sketch the graph of the function. What is its range? $$ f(x)=\left\\{\begin{array}{ll} -x-1 & \text { if } x<-1 \\ 0 & \text { if }-1 \leq x \leq 1 \\ x+1 & \text { if } x>1 \end{array}\right. $$
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Get started for freePlot the graph of the function \(f\) in an appropriate viewing window. (Note: The answer is not unique.) $$ \begin{array}{l} f(x)=-2 x^{4}+5 x^{2}-4\\\ \text { 7. } f(x)=\frac{x^{3}}{x^{3}+1} \end{array} $$
Find the zero(s) of the function f to five decimal places. $$ f(x)=x^{3}-9 x+4 $$
Write the expression in algebraic form. $$ \sin \left(\cos ^{-1} x\right) $$
Plot the graph of the function \(f\) in (a) the standard viewing window and (b) the indicated window. $$ f(x)=x \sqrt{4-x^{2}} ; \quad[-3,3] \times[-2,2] $$
Show that \(f\) and \(g\) are inverses of each other by verifying that \(f[g(x)]=x\) and \(g[f(x)]=x\). $$ f(x)=\frac{1+x}{1-x} ; \quad g(x)=\frac{x-1}{x+1} $$
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