Chapter 10: Q 48. (page 801)
Find a vector in the direction opposite to and with magnitude 3.
Short Answer
The required vector is.
Chapter 10: Q 48. (page 801)
Find a vector in the direction opposite to and with magnitude 3.
The required vector is.
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Get started for freeIf u and v are nonzero vectors in , why do the equations role="math" localid="1649263352081" and tell us that the cross product is orthogonal to both u and v?
Consider the sequence of sums
(a) What happens to the terms of this sequence of sums as k gets larger and larger?
(b) Find a sufficiently large value of k which will guarantee that every term past the kth term of this sequence of sums is in the interval (0.49999, 0.5).
In Exercises 37–42, find and find the unit vector in the direction of v.
In Exercises 36–41 use the given sets of points to find:
(a) A nonzero vector N perpendicular to the plane determined by the points.
(b) Two unit vectors perpendicular to the plane determined by the points.
(c) The area of the triangle determined by the points.
Find also sketch
role="math" localid="1649603034674"
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