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Let ax+by+cz=d be the equation of a plane with a,b,c and d all nonzero. What are the coordinates of the intersection of the plane and the x-,y- and z-axes ? Explain how to use these points to sketch the plane.

Short Answer

Expert verified

Coordinates of the intersection of the plane and the x-axes is da,0,0

Coordinates of the intersection of the plane and the y-axes is 0,db,0

Coordinates of intersection of the plane and the z-axes is 0,0,dc

Step by step solution

01

Given information

The equation of the plane to be ax+by+cz=d with a,b,c and d to be non-zero.

02

Calculation

The goal is to determine the coordinates of the plane's intersection with the x,yandz axes, as well as how to sketch the plane using the points.

When the y and z coordinates are zero, a plane and the x-axes intersect.

The coordinates of intersection of the plane and the x-axes is obtained by substituting y=0and z=0

The substitution of y=0and z=0in ax+by+cz=dgives:

ax+b(0)+c(0)=dax=dx=da

Therefore, coordinates of intersection of the plane and the x-axes is da,0,0

03

Calculation

Substituting x=0and z=0yields the intersection coordinates of the plane and they-axes.

The substitution of x=0and z=0in ax+by+cz=dgives:

a(0)+by+c(0)=dby=dy=db

Therefore, coordinates of intersection of the plane and the y-axes is 0,db,0

04

Calculation

Substituting x=0and y=0yields the intersection coordinates of the plane and they-axes.

The substitution of x=0and y=0in ax+by+cz=dgives:

a(0)+b(0)+cz=dcz=dz=dc

Therefore, coordinates of intersection of the plane and the z-axes is 0,0,dc

To draw the plane, take the three coordinates as the triangle's vertices and draw the plane using the triangle.

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