Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Most of the parametric equations and vector-valued functions we have studied have component functions that are continuous. What happens when one of the component functions is discontinuous at a point? For example, the “floor” function z(t)=thas a jump discontinuity for every integer t. What is the graph of the equations x=cos2πt,y=sin2πt,z=t,tR?

Short Answer

Expert verified

The image of the graph has been added below.

Step by step solution

01

Step 1. Given Information

The floor function is z(t)=t, it has jump discontinuity for every integer t.

02

Step 2. Taking example of circular helix

As we know, the objective is to construct a graph when one component is discontinuous at a point
Take an example of circular helix

r(t)=cos2πt,sin2πt,t
x(t)=cos2πt......(1)
y(t)=sin2πt......(2)
z(t)=t......(3)

03

Step 3. Tabulating different values oft 

A table of different values of t

t
x(t)=cos2πt
y(t)=sin2πt
z(t)=t
(x,y,z)
0
1
0
0
(1,0,0)
1
1
0
1
(1,0,1)
2
1
0
2
(1,0,2)
3
1
0
3
(1,0,3)
4
1
0
4
(1,0,4)
04

Step 4. Making the graph 

Image of the graph.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free