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Evaluate the integral:

02πsint,cost,tdt

Short Answer

Expert verified

02πsint,cost,tdt=π1+4π2+12sinh-1(2π)-12sinh-1(0)

Step by step solution

01

Given Information

Consider 02πsint,cost,tdt

The objective is to evaluate the definite integral from0to2π.

02

Calculation

The integral of a Vector Function

r(t)dt=x(t)idt+y(t)jdt+z(t)kdt=ix(t)dt+jy(t)dt+kz(t)dt+c

Where cis a vector constant and has the form c=(c1,c2,c3)for scalar constants c1,c2and c3.

Now,

sint,cost,tdt=sin2t+cos2t+t2dt=1+t2dt=t21+t2+12sinh-1(t)

03

Expression

Now,

02πsint,cost,tdt=t21+t2+12sinh-1(t)02π=2π21+(2π)2+12sinh-1(2π)-12sinh-1(0)=π1+4π2+12sinh-1(2π0-12sinh-1(0)

Thus02πsint,cost,tdt=π1+4π2+12sinh-1(2π)-12sinh-1(0)

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