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Chapter 11: Q. 42 (page 860)

Evaluate the limits in Exercises 42–45.
$\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t)$

Short Answer

Expert verified

The evaluation of the limit $\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t)$ is $j$ .

Step by step solution

Step 1. Given Information.

The function:

$\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t)$

Step 2. Apply the limits.

By applying the limit and solving,

$\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t) = \underset{t \to 0}{l i m} (\sin 3 t) i + \underset{t \to 0}{l i m} (\cos 3 t) j = 0 i + 1 j = j$

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Evaluate the limits in Exercises 42–45.
$\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t)$

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Apply the limits.

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Most popular questions from this chapter

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Evaluate the limits in Exercises 42–45.limt→0(sin3t,cos3t)

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Apply the limits.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Mechanics Maths

Probability and Statistics

Statistics

Theoretical and Mathematical Physics

Pure Maths

Study anywhere. Anytime. Across all devices.

Evaluate the limits in Exercises 42–45.
$\underset{t \to 0}{l i m} (\sin 3 t, \cos 3 t)$