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Evaluate the integrals in Exercises 40–44.

t,t2,t3dt

Short Answer

Expert verified

The value for the given vector function ist22,t33,t44+C.

Step by step solution

01

Step 1. Given Information

Given that,t,t2,t3dt.

Let us assume r(t)=t,t2,t3

02

Step 2. Evaluating the given integral

Evaluation,

r(t)dt=t,t2,t3dt=(ti+t2j+t3k)dt=itdt+jt2dt+kt3dt=i(t22)+j(t33)+k(t44)+C=t22,t33,t44+C

So, the value of the given vector function ist22,t33,t44+C.

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