Question

Describe strategy for solving the type of integral given.

$\int {\cos }^{k}xdx,k$ is even.

Short answer

Write${\cos }^{2}x=\frac{1+\cos 2x}{2}$

Step-by-step solution

Step 1. Given information

Integral is$\int {\cos }^{k}xdx,k$is even.

Step 2. Explanation

Consider the integral $\int {\cos }^{k}xdx,k$is even.

Write${\cos }^{2}x=\frac{1+\cos 2x}{2}$