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Find the integral.

tan24xsec4xdx

Short Answer

Expert verified

Answer is-18lntan2x+π4+18tan4xsec4x+C

Step by step solution

01

Step 1. Given information

Integral istan24xsec4xdx

02

Step 2. Explanation

Let4x=u

4dx=du

tan24xsec4xdx=14tan2usecudu=14sec2u-1secudu=14sec3u-secudu=-18lntanu2+π4+18tanusecu+C=-18lntan2x+π4+18tan4xsec4x+C

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