Chapter 5: Q 42. (page 429)
Solve the integral :
Short Answer
The required answer is.
Chapter 5: Q 42. (page 429)
Solve the integral :
The required answer is.
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Get started for freeWhy don’t we need to have a square root involved in order to apply trigonometric substitution with the tangent? In other words, why can we use the substitution when we see , even though we can’t use the substitution unless the integrand involves the square root of? (Hint: Think about domains.)
Why don’t we ever have cause to use the trigonometric substitution ?
Why is it okay to use a triangle without thinking about the unit circle when simplifying expressions that result from a trigonometric substitution withor ? Why do we need to think about the unit circle after trigonometric substitution with ?
Solve the integral:
Solve each of the integrals in Exercises 39–74. Some integrals require trigonometric substitution, and some do not. Write your answers as algebraic functions whenever possible.
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